Osmosis and Tonicity
Key terms/concepts: Osmosis, turgidity, water potential, solute concentration, hypotonic,
hypertonic, isotonic, plasmolysis.
Objective: To determine the solute concentration of fleshy plant tissue by interpolation of data.
Materials:
Fleshy plant material (potato, carrot, sweet potato, turnip, etc…
Sucrose solutions: 0.2, 0.4, 0.6, 0.8, and 1.0 M (molar) solutions
* A 1.0 molar solution is one gram molecular weight per liter. With
sucrose, the molecular weight is 342 (C12H22O11), so a 1.0 molar
solution of sucrose is 342 grams in a liter (total volume w/ solute) of water. The
other concentrations are adjusted proportionally.
Distilled water
250 ml Beakers
Procedure: Day 1
Cut six uniform sized (same as other lab groups) of some vegetative tissue (provided).
Rinse the cut pieces and allow them to drain on a paper towel for 60 seconds.
Mass the tissue sections on a small piece of aluminum foil to the nearest 0.1 gram.
Put the pieces (all 6) in a beaker in 150 ml of one of the six concentrations of
sucrose as follows: Station 1 - DW; Station 2 - 0.2 M; Station 3 - 0.4 M;
Station 4 - 0.6 M; Station 5 - 0.8 M; Station 6 - 1.0 M.
Leave the potato pieces in the respective solutions overnight...covered with
plastic wrap (label masking tape with group information and put it on the wrap).
Day 2
Remove the potato pieces and drain them on a paper towel for 60 seconds, then mass
them again to the nearest 0.1 gram.
Calculate % change in mass (M) = MF - MI divided by MI) x 100.
Record your group’s % M to one decimal on the table on the board. We will use data
from 3 classes to replicate the experiment 3 times.
Graphical Analysis
Plot the six points on a graph. “Percent change in mass as a function of solute
concentration” Draw a regression line to represent the data.
Determine whether each of the six liquids are hypo-, iso-, or hypertonic to the cells in the
potato.
Determine the solute concentration of the potato from your graph by interpolating from
the point where the regression line intersects Y = 0 (the concentration where the change in
mass was zero).
The point on your graph where the regression line intersects Y = 0 corresponds to the
concentration (X) that best represents the solute concentration of the tuber tissue. Determine
this concentration in moles.
Note that there are both positive and negative values for Y (% M).