Name ________________________________________ Date __________________ Class __________________
LESSON
2-3
Scientific Notation with Negative Powers of 10
Practice and Problem Solving: A/B
Write each number as a negative power of ten.
1.
1
= ____
102
2.
1
= ____
104
3.
1
= ____
105
4.
1
= ____
107
5.
1
= ____
106
6.
1
= ____
103
7.
1
= ____
109
8.
1
= ____
101
Write each power of ten in standard notation.
9. 10−3 = ____
10. 10−5 = ____
11. 10−1 = ____
12. 10−6 = ____
13. 10−2 = ____
14. 10−9 = ____
15. 10−4 = ____
16. 10−7 = ____
19. 0.000473
20. 0.0024
Write each number in scientific notation.
17. 0.025
________________
21. 0.000014565
_________________
18. 0.3
________________
_______________
22. 0.70010
23. 0.0190500
_________________
_________________
________________
24. 0.00330000
________________
Write each number in standard notation.
25. 6 × 10−3
_________________
29. 3.052 × 10−8
_________________
26. 4.5 × 10−2
27. 7 × 10−7
_________________
_________________
30. 5 × 10−1
31. 9.87 × 10−4
_________________
_________________
28. 1.05 × 10−6
________________
32. 5.43 × 10−5
________________
Solve.
33. An E. coli bacterium has a diameter of about 5 × 10−7 meter. Write
this measurement as a decimal in standard notation.
_________________________________________________________________________________________
34. A human hair has an average diameter of about 0.000017 meter.
Write this measurement in scientific notation.
_________________________________________________________________________________________
Original content Copyright © by Houghton Mifflin Harcourt. Additions and changes to the original content are the responsibility of the instructor.
32
30. 0.5
Success for English Learners
1. 3.28 × 10 > 3.28 × 10 because
3.28 × 105 = 328,000 and
3.28 × 103 = 3,280.
31. 0.000987
2. A car; 3 × 106=3,000,000 g, or 3,000 kg,
and a car would weigh many kilograms
but a hair would not.
34. 1.7 × 10−5 m
5
3. 1.86 × 10
3
32. 0.0000543
33. 0.0000005 m
Practice and Problem Solving: C
5
1. 0.0052; 0.0000052; >
4. 4,567.89
2. 0.000005; 0.000025; <
3. 3; 0.1; >
LESSON 2-3
4. 0.00502; 0.000205; >
Practice and Problem Solving: A/B
1. 10
5. 1.2 × 10−3; 4.5 × 10−1
−2
6. 3.2 × 10−4; 2.3 × 10−6
2. 10−4
7. 2.35 × 10−6, 3.25 × 10−6, 5.32 × 10−6, 2.35
× 10−5, 3.25 × 10−5, 5.32 × 10−5
3. 10−5
4. 10−7
5. 10
8. 0 × 100, 1 × 10−1, 5 × 10−1,1 × 100,
5 × 100
−6
6. 10−3
9. 1 × 10−3 m = 1 mm; 1 ×10−1 cm = 1 mm;
equal, so false
7. 10−9
10. 7 × 10−1 cm = 7 mm; 7 × 10−3 m = 7 mm;
equal, so false
8. 10−1
9. 0.001
11. 3.5 × 10−1 cm = 3.5 mm; 3.5 × 10−3
m = 3.5 mm; equal, so true
10. 0.00001
11. 0.1
12. 9 × 10−1 mm; 9 × 10−4 m = 9 × 10−1 mm;
equal, so true
12. 0.000001
13. 0.01
13. 9 ×10−3 liters = 0.009 liters; 3 × 10−5 liters
= 0.00003; 0.009 ÷ 0.00003 = 300 drops
14. 0.000000001
15. 0.0001
19. 4.73 × 10−4
14. 0.00025 meters = 2.5 ×10−4; 0.000125
meters = 1.25 × 10−4; area = length ×
width = (2.5 × 10−4) × (1.25 × 10−4) = 3.125
× 10−8 square meters; to two significant
digits, the answer is 3.1 × 10−8 square
meters.
20. 2.4 × 10−3
Practice and Problem Solving: D
16. 0.0000001
17. 2.5 × 10−2
18. 3 × 10−1
21. 1.4565 × 10−5
22. 7.001 × 10
−1
23. 1.905 × 10−2
24. 3.3 × 10
−3
25. 0.006
26. 0.045
27. 0.0000007
28. 0.00000105
1.
1
100
2.
1
100,000
3.
1
10,000
4.
1
1,000
29. 0.00000003052
Original content Copyright © by Houghton Mifflin Harcourt. Additions and changes to the original content are the responsibility of the instructor.
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