Mass-to-mass Worksheet
…remember…balance the reaction…maybe a menu…mole ratio…maybe another menu…
Name ________________________________
Work must be shown on every problem that has calculations…no work = no credit
1. Write and balance the reaction that occurs between iron (III) chlorate solution and potassium hydroxide
solutions.
2. How many moles of iron (III) hydroxide can be recovered if 14.2 moles of potassium hydroxide were
used up?
3. What mass of iron (III) hydroxide will precipitate out from 1.35 x 10-3 moles of iron (III) chlorate?
4. How many grams of potassium chlorate could be recovered from 396.5 grams of iron (III) chlorate?
5. What is the reaction that creates solid copper and a solution of lithium acetate? Use copper(II) on the
reactant side.
6. How many grams of copper could be recovered from 34.6 moles of lithium?
7. How many grams of lithium acetate would be produced along with 423.987 grams of copper?
8. Write the reaction for the decomposition of ammonia gas (nitrogen trihydride) into its gaseous
elements.
9. How many grams of ammonia would have to decompose to let us collect 4.78 x 10 6 kg of nitrogen gas
through this method?
10. Write a reaction for the combustion of phenol (C6H5OH).
11. How many grams of phenol would have to burn to produce 195 grams of water?
12. How many grams of carbon dioxide would be produced from the same situation as is described in
#11?
Use the following reaction for problems 13-16…
S8 (s) + O2 (g) + H2 (g) 
H2SO4 (aq)
13. How many grams of sulfuric acid can be made from 78.1 grams of sulfur (S8)?
14. How many grams of sulfuric acid could be made from 345 grams of oxygen gas?
15. How many grams of sulfuric acid could be made from 56.9 grams of hydrogen gas?
16. If you had a mixture of 56.9 grams of hydrogen gas, 78.1 grams of sulfur, and 345 oxygen gas, how
many grams of sulfuric acid could you produce? Explain your choice or answer. (Hint: no new work
should be done for this problem – all work should have been done in #13-15.)
Answers…
1.
2.
3.
4.
balances with 1,3 & 1,3
4.73 moles (1 step)
0.144 g (2 steps)
476.1 g (3 steps)
5. use copper (II) on the reactant side
6. 1.10 x 103 g (2 steps)
7. 880.7 g (3 steps)
8. balances with 2 & 3,1
9. 5.81 x 109 g (4 steps)
10. balances with 1,7 & 3,6
11. 340 g (3 steps)
12. 952 g (3 steps)
13. remember to balance the reaction…balances with 1,16,8 & 8…239g (3 steps)
14. 529 g (3 steps)
15. 2.76 x 103 g (3 steps)