Genetics of Drosophila melanogaster Objectives The purpose of this lab is to use genetic crosses to illustrate independent assortment and sex-linkage in the fruit fly, Drosophila melanogaster. You will be given monohybrid, dihybrid, and/or sex-linked crosses with well-defined mutant traits. Over the course of four weeks, you will observe and record what happens to the mutant traits as they are passed from one generation to the next. Additionally, you will learn the life cycle of the fruit fly and learn how to recognize the sex of fruit flies, and several types of classic mutations. Lastly, you will compare the predicted results with the actual results using a chi-square analysis. Drosophila Life Cycle Fruit flies are an ideal organism for conducting genetic studies. They have a short generation time and are easily cultured in the lab because they have simple food requirements and occupy little space. In addition, they produce large numbers of offspring that can be easily manipulated and examined under a low-power microscope. The fruit fly life cycle is approximately two weeks at room temperature (see Figure 1). Several days after a breeding pair has mated, the female lays an ellipsoid egg with two filaments at one end. They are generally laid on the surface of the medium. The eggs develop into larvae after about a day. The larvae develop into three progressively larger larval stages called instars. The larvae appear worm-like and eat almost continuously. They channel through the culture medium while eating. As the larvae mature, they climb up the side of the culture tube where the larval cuticle darkens and hardens into a puparium. Within the puparium, the eyes, wings, and legs become visible as the fly metamorphoses into an adult. The adult emerges by forcing its way through the anterior end of the puparium. The newly emerged adult is light in color and its wings are not yet fully expanded. The female fruit fly does not mate until 10-12 hours following emergence but once she has mated she can store sperm from multiple partners in receptacles to fertilize the her eggs as she lays them. Therefore, it is important to use only unmated females in controlled crosses. Experimental Design In the following experiment, you will be given fruit fly crosses with one or two mutations. The mutations will be in the form of eye color or shape, bristle number or shape, wing size or shape, or antennae size or shape. You will not be given the any information about the type of crosses nor will you be given the name of the mutations in the crosses. You will identify the types of mutations in both the male and female flies by comparing them to the normal or wild-type individuals (Be sure to draw and describe in detail each mutation). Once you are sure you have identified a mutant trait, you should make up a name for that trait. Procedure Lab 1 1. Your teacher will provide you with a vial of wild-type fruit flies. 2. Place the culture tube on its side. Use a small brush to soak up FLYNAP (anesthetic) and insert the brush into the culture tube along the sponge stopper. Be careful not to get any of the FLYNAP on the sponge stopper. DO NOT OVERANESTHETIZE THE FRUIT FLIES! The flies should be out for 15-20 minutes. 3. When the flies are anesthetized, place them on an index card to view under a dissecting microscope. 4. Learn to distinguish male from female flies with the following three characteristics (see Figure 2). First, males are generally smaller than females. The abdominal tip of males is dark and blunt whereas females are lighter and pointed abdominal ends. Also, females have transverse stripes on the abdomen. Third, males have sex combs that are groups of black bristles on the uppermost joint of the forelegs. Females lack these combs. 5. Familiarize yourself with the features of the wild-type individuals. a. What is the eye color? ____________________ b. What is the shape of the eye? ____________________ c. What is the wing size? ____________________ d. What is the wing shape? ____________________ e. What is the body color? ____________________ f. How many bristles are present? ____________________ g. What is the shape of the bristles? ____________________ 1. When you are confident that you can identify the different traits of your fruit flies, obtain an experimental vial from your teacher. 2. Record the cross number of the vial. These adult flies are the parental generation and have already mated. The eggs or larvae should be on the surface of the culture medium. These eggs, larvae, and any pupae represent the F1 (i.e. filial) generation. 3. Anesthetize the adults with the procedure from step 2. 4. Remove the anesthetized parents and observe them carefully. Be sure to separate the males from the females and note the mutations (if any) present in each sex. If the trait is not normal (wild-type) you have to describe and name it. 5. Record your data in the table below. What is the parental cross? __________________ Trait/Mutation Eye color Eye shape Wing size Wing shape Body color Bristle number Bristle shape Female Male 1. Label the experimental vial with the parental cross. This should be based on the data collected in step 10. Lab 2 2. Anesthetize the newly emerging F1 fruit flies. Examine the flies carefully. Record and tally the number of mutations (if any) in males and females separately in the table below. Trait/Mutation Female Male 1. Place five to six pairs of fruit flies into a new culture vial. For this mating the females do not need to be virgins. 2. Label the new vial F1. Also, label with the symbols of the cross, the date, and the your name. Lab 3 3. Remove the F1 adults from the vial and place them in ethanol. The eggs, larvae, and pupae represent the F2 generation. Lab 4 4. Anesthetize the F2 flies. Examine the flies carefully. Record and tally the number of mutations (if any) in males and females separately in the table below. Trait/Mutation Female Analysis of Results 1. What is the name of the observed mutation(s)? Male 2. Draw two Punnett squares below to predict the results of the parental and F1 crosses. You may need to review this information. 3. According to the squares, what are the expected ratios for the genotypes and phenotypes of the F1 and F2 generation in the experiment? Expected genotype ratio Expected phenotype ratio F1 F2 1. 2. 3. 4. From the results, define your cross. Sex-linked or autosomal? ____________________ Monohybrid or dihybrid? ____________________ Dominant mutation or recessive mutation? ____________________ Overview: The Chi-square Test The chi-square test is used to compare expected values with observed values. For example, you may be interested in determining whether the phenotypic ratio of a monhybrid cross with independent assortment is 3:1. Parental generation (P): Filial generation (F1): Female FF (purple flowers) Ff (purple flowers) Male ff (white flowers) Ff (purple flowers) X X What is the phenotypic ratio of the F2 generation? The phenotypic ratio would be 3 purple flowers (FF and Ff) to 1 white flower (ff). F1 males F1 females F f F FF Ff f Ff ff Question: Is the observed flower color close enough to the expected 3:1 ratio of purple to white flowers expected for an independently assorting monohybrid cross? Your null and alternative hypotheses are as follows: Ho: The sample comes from a population having a 3:1 phenotypic ratio of purple to white flowers Ha: The sample does not come from a population having a 3:1 phenotypic ratio of purple to white flowers Your level of significance is set at an alpha () of 0.05 and you will use a two-tailed test. The chi-square statistic is given by the following equation: n 2 = ∑ (o-e)2/e i =1 o = the observed value in each category e = the expected value in each category n = number of categories ∑ means that the expression (i.e. (o-e)2/e) is summed from category i = 1 to n To calculate 2: 1. For each category (in this case, pink and white flowers), calculate the expected value. For our example, suppose that you sampled 100 flowers to see how many purple and white flowers you have. Of those 100 flowers, 75 should be purple and 25 should be white if you have a monohybrid cross that assorts independently. 2. For each category, subtract the observed value (o) from the expected value (e) to find the difference (o-e) between the two. 3. Square the difference (o-e)2 4. Divide the value from step 3 by the expected value to find (o-e)2/e 5. Repeat this for all categories. 6. Add up (∑) all the (o-e)2/e, the sum is 2. Phenotype Purple White Observed (o) 65 35 Expected (e) 75 25 (o-e) (o-e)2 (o-e)2/e -10 10 100 100 2calculated: 100/75 100/25 5.3333 Summing the last column yielded a value of 5.3333 for 2. This is called the calculated 2 statistic. Next you will have to calculate the degrees of freedom () by subtracting the number of categories (n) from one. In this example, there are two categories (i.e. purple and white flowers) so is equal to 1. Once you have the 2calculated and , you can compare your calculated value to what is known as the critical chi-square (2critical) value from Table A-2. At an = 0.05 and of 1, the 2critical is 3.841. Use the following decision rule: If the calculated value (2calculated) ≥ the critical value (2critical), then reject the null hypothesis (Ho) and conclude that the difference found between the observed and expected values is significantly different and could not occur by chance alone. 2. Given the expected phenotypic ratios of the F2 generation, did your expected ratio differ from the observed ratio? This question can be answered by performing a chisquare ( analysis. Read the description above for the analysis and then fill in the following table. Phenotype Observed (o) Expected (e) (o-e) (o-e)2 (o-e)2/e Total*: *Only calculate a total for the first, second, and fifth column. State clearly the null and alternative hypotheses: Ho: Ha: What is the calculated chi-square statistic (calculated)? __________ What is the critical chi-square statistic ((critical)? __________ What is the significance level? P = __________ 2. Why was it necessary for the females of the parental generation to be virgins? 3. Why was it not important for the females of the F1 generation to be virgins when they were mated? 4. Why were the adult flies removed from the vials at Lab 2 and Lab 4?