The Haloform Reaction: A mechanistic examination using computational chemistry Ben Norris Department of Chemistry, University of Pittsburgh June, 2006 Learning goals: In this assignment, you will explore the haloform reaction using computational chemistry. You will use heat of formation calculations to understand the relative acidities of carbon acids, and the implications these acidities have for the mechanism of the base-promoted -halogenation reaction and the haloform reaction. You should be generally familiar with enolate chemistry (Chapter 18 in Volhardt and Schore, for example) before completing this assignment. You may wish to review acid/base equilibria, heats of formation and enthalpies of reaction from your General Chemistry textbook before working on this assignment. Previous experience with computational chemistry (such as that from the Organic Chemistry Lab Course) is not required. A guide for using the CAChe program as it pertains to this assignment is included in an appendix at the end. Overview: The haloform reaction is a reaction of a methyl ketone (a 2-alkanone) in basic solution in the presence of excess halogen. The organic products of this reaction are the haloform (trihalomethane) and a carboxylate anion. The overall reaction is shown below. O + R 4 OH- O + 3 X2 + R CHX3 + 3 H2O + 3 X- O The haloform reaction is unique to methyl ketones. Other ketones will undergo base-promoted -halogenation, but will react no further. If the halogen used is iodine, the reaction becomes the iodoform test reaction. Iodoform is a bright yellow solid, and its formation can be used as a qualitative test for the presence of a methyl ketone. Part I: Base-promoted -halogenation The first part of the haloform reaction is a base-promoted -halogenation reaction. This reaction can be exhaustive – the presence of excess base and halogen can lead to multiple halogenations. During the first part of this assignment you will use CAChe to examine why this reaction is exhaustive. 1 Exercise 1: Draw the mechanism for the base-promoted -halogenation of acetone to 1,1,1-trihaloacetone. O O X2 X NaOH X X Exercise 2: The following table outlines the three deprotonation reactions when using chlorine as the halogen atom. Use CAChe to determine the heats of formation for each of the species in the table, and then derive the enthalpies of reaction for each of the three reactions. Use the “PM3 geometry in water” since the haloform reaction is often done in aqueous solution. 1. Hf 2. Hf O O + ______ ______ : H + ______ H2O Hrxn ______ ______ O O Cl + ______ Cl OH- ______ O : H + ______ H2O ______ ______ O Cl 3. + OH- Cl Hf H OH- ______ ______ Cl : Cl ______ + H2O ______ ______ 2 Do the enthalpies of reaction show a trend with increasing chlorination? What do these data suggest about the relative acidity of the three ketones? Exercise 3: Fill in the heats of formation on the following tables and calculate the enthalpies of reaction for the deprotonation reactions for bromine and iodine as well. Bromine 1. Hf 2. Hf O O + ______ ______ : H + ______ H2O Hrxn ______ ______ O O Br + ______ Br OH- ______ O : H + ______ H2O ______ ______ O Br 3. + OH- Br Hf H OH- ______ ______ Br : Br ______ + H2O ______ ______ 3 Iodine 1. Hf 2. Hf O O + ______ ______ : H + ______ H2O Hrxn ______ ______ O O I + ______ I OH- ______ : H + ______ H2O ______ ______ O O I 3. + OH- ______ I : + H2O I I Hf H OH- ______ ______ ______ ______ Do you observe the same trend for bromine and iodine as you did for chlorine? In general, how does increasing -halogenation affect the acidity of an -hydrogen on the same carbon? Using what you have learned in the above exercises, provide an explanation as to why the basepromoted -halogenation reaction is exhaustive. Part 2: Nucleophilic Acyl Substitution The second part of the haloform reaction is a nucleophilic acyl substitution (addition/elimination) reaction. This is the part of the haloform reaction that only works with methyl ketones. After exhaustive based promoted -halogenation, a methyl ketone is converted to a trihalomethyl ketone. The trihalomethyl ketone reacts with a hydroxide anion to generate a carboxylate anion and a haloform molecule. This is the part of the haloform reaction that is unique to methyl ketones. During the second part of this assignment you will explore why only trihalomethyl ketones undergo this type of reaction. 4 O O O - OH R R X2 X H - OH X X R O + X X X Exercise 4: Draw the mechanism of the reaction of 1,1,1-trihaloacetone with hydroxide anion. O O X X X OH- H O + X X X Exercise 5: The first step of a nucleophilic acyl substitution is the attack of the nucleophile. Draw 1,1,1-trichloroacetone, 1,1-dichloroacetone, 3,3-dichloro-2-butanone, and acetone in CAChe and optimize their geometries using “PM3 geometry in water”. Then construct the electrostatic potential on electron density surface using “Current geometry with B88-LYP DFT wavefunction”. Then find the partial charge at the carbonyl carbon. Fill in the table. Color of Electron Density at Carbonyl Carbon Partial Charge at Carbonyl Carbon O Cl Cl Cl O Cl Cl O Cl Cl O 5 Based on the information determined in Exercise 5, which carbonyl compound would be most susceptible to nucleophilic attack? Exercise 6: The second step of a nucleophilic acyl substitution reaction is the loss of the leaving group. This is usually the rate-determining step. Good leaving groups are often the conjugate bases of strong acids. Compare the acidity of methane, chloromethane, dichloromethane, and chloroform. Determine the enthalpies of reaction for the following acid dissociation reactions, using the PM3 geometry in water. 1. Hf 2. Hf 3. Hf 4. Hf CH4 ______ H3CCl ______ H2CCl2 ______ HCCl3 ______ + H2O H3C- + ______ H2O ______ H2ClC- + ______ H2O ______ HCl2C- + ______ H2O ______ Cl3C- ______ ______ + H3O+ Hrxn + ______ H3O+ ______ Hrxn + ______ H3O+ ______ Hrxn + ______ H3O+ ______ Hrxn ______ ______ Rank the following four compounds in order of increasing acidity. CH4 CH3Cl CH2Cl2 CHCl3 Which of the following four anions is the best leaving group? Explain your choice based on the data in the table above. H3C- H2ClC- HCl2C- Cl3C- 6 Exercise 7: Compare the acidity of chloroform, and 1,1-dichloroethane. Calculate the enthalpies of reaction for the following reactions using the PM3 geometry in water. 1. HCCl3 Hf 2. Hf ______ H3CCHCl2 ______ + H2O Cl3C:- + ______ H2O ______ H3CCl2C:- ______ ______ + H3O+ Hrxn + ______ H3O+ ______ Hrxn ______ ______ Which of the following tetrahedral intermediates is more likely to kick out the carbanion leaving group? Explain using the data in the table above. O H 3C HO O CCl3 H 3C HO CCl2CH3 Based on the exercises you have completed in Part 2, explain why the haloform reaction is unique to methyl ketones. 7 Appendix: Tips for using CAChe for this assignment Introductory quick tips for using the CAChe Workspace program can be found at: http://chemed.chem.pitt.edu/cacc/downloads/WS_quick_tips.pdf More detailed CAChe tutorials can be found, if you are interested, at: http://chemed.chem.pitt.edu/cacc/CACheTutorial/index.htm Calculating Heats of Formation Draw the molecule or ion of interest. The charge of atoms can be changed using the toolbar immediately above the drawing area. Beautify the molecule. Run a new experiment to optimize the geometry. Under “Property of” select Chemical Sample, and under “Property” select optimized geometry. Since most of the calculations in this assignment will use the PM3 geometry in water, select this method from the “Using” menu. Click “Start” to run the experiment. Select “Yes” if asked to save the molecule before the experiment. PM3 is a semi-empirical method that is partially based on empirical parameters. It is a good method for determining optimum geometry of simple organic compounds, and is capable of calculating qualitatively reliable heats of formation with a relatively short calculation time. When the experiment is finished, the heat of formation is returned as a line of text in the Experiment Status window. It should look like the following: The heat of formation of this molecule is -13.073 kcal/mol. Constructing an Electrostatic Potential on Electron Density Surface First, draw, beautify, and optimize the geometry of a molecule or ion as described previously. Then, run a new experiment. This time select electrostatic potential on electron density as the “Property”. Select current geometry with B88-LYP DFT wavefunction under the “Using” menu. Click “Start” to run the experiment. Select “Yes” if asked to save the molecule before the experiment. 8 This calculation uses density functional theory (DFT). The PM3 method is not very good at examining electron density, but DFT is very good at it. Optimizing a molecule’s geometry using DFT is a task that takes much longer than optimizing using PM3. However, DFT can calculate electron density relatively quickly if given a good geometry to start with. This is why we optimize with PM3 first. When the calculation is complete, go to the Analyze menu at the top of the window, and select “Show Surfaces”. Select the XXX.csf.EonD surface (where XXX is the filename), and click “OK”. The surface will then overlay on top of the molecule. The surface is color coded by electron density. Warm colors represent areas of less electron density, and cool colors represent areas of more electron density. In order of increasing electron density, the colors are: White<red<yellow<green<sky blue<blue<magenta<purple Viewing Partial Charges Partial charges can only be determined after running experiments. Part of running any experiment involves assigning partial charges to all the atoms. As partial charges have to do with electron density around an atom, a DFT calculation will give a better partial charge than a PM3 calculation (though any PM3 calculation will generate partial charges). After running an experiment, select the atom of interest. Select “Atom Attributes” on the View menu. On the “Label” tab, put a check by “Partial Charge”. The partial charge label will now appear over the atom of interest. 9