Part III: Sample Chapter Tests and Answers CHAPTER 11 TEST 157 FORM A PAGE 1 First classify the problem as one of the following: Chi-square test of independence Chi-square goodness of fit Chi-square for testing or estimating 2 or F test for two variances One-way ANOVA Two-way ANOVA Then, in each of the problems, when a test is to be performed, do the following: Give the value of the level of significance. State the null and alternate hypotheses. Find the sample test statistic and degrees of freedom. Find or estimate the P value of the sample test statistic. Make a conclusion. Interpret the conclusion in the context of the application. In the case of one-way ANOVA, make a summary table. 1. How old are college students? The national age distribution for college students is shown below. National Age Distribution for College Students Age Percentage Under 26 26–35 36–45 46–55 Over 55 39% 25% 16% 12% 8% The Western Association of Mountain Colleges took a random sample of 212 students and obtained the following sample distribution. Sample Distribution, Western Association of Mountain Colleges Age Number of students Under 26 26–35 36–45 46–55 Over 55 65 73 41 21 12 Is the sample age distribution for the Western Association of Mountain Colleges a good fit to the national distribution? Use = 0.05. Copyright © Houghton Mifflin Company. All rights reserved. 1. ______________________________ Part III: Sample Chapter Tests and Answers CHAPTER 11 TEST 158 FORM A PAGE 2 2. Are teacher evaluations independent of grades? Halfway through the term, a random sample of 284 students were asked to evaluate teacher performance. The students also were asked to supply their midterm grade in the course being evaluated. In this study, only students with a passing grade (A, B, or C) were included in the summary table. Midterm Grade Teacher Evaluation A B C Row Total Positive 35 33 28 96 Neutral 25 46 35 106 Negative 20 22 40 82 Column total 80 101 103 284 Use a 5% level of significance to test the claim that teacher evaluations are independent of midterm grades. 3. If we have a normal population with variance 2 and a random sample of n measurements taken from this population, what probability distribution do we use to test claims about the variance? 2. _____________________________ 3. _____________________________ 4. A technician tested 25 motors for toy electric trains and found the sample standard deviation of electric current to be s = 4.9 amperes. (a) Find a 95% confidence interval for , the population standard deviation of electric current in all such toy trains. 4. (a) __________________________ (b) If the manufacturer specifies that = 4.1 amperes, do the sample data indicate that is larger than 4.1? Use a 1% level of significance. (b) __________________________ 5. Two methods of manufacturing large roller bearings are under study. In this study, the diameters of the bearings are measured. For Method I, a random sample of n1 = 16 bearings had sample standard deviation of s1 = 2.9 mm. For Method II, a random sample of 18 bearings had a sample standard deviation of s2 = 1.2 mm. Assume that the diameters follow a normal distribution. Test the claim that 12 22 using a 1% level of significance. 5. _____________________________ Copyright © Houghton Mifflin Company. All rights reserved. Part III: Sample Chapter Tests and Answers CHAPTER 11 TEST 159 FORM A PAGE 3 6. Sasha has decided to buy one of four different cars. She is interested in whether there is a difference in the gas mileage of the cars. In a study, miles per gallon were obtained for a random sample for each of the four cars. The results of a one-way ANOVA test are summarized below. ANOVA for mpg Source SS d.f. MS F P Value Between groups 65.43 3 21.81 2.42 0.091 Within groups 216.29 24 9.01 Number of students 281.71 27 Use a 5% level of significance to test whether there is a difference among the population means. 6. _____________________________ 7. A study to determine if management style affects the number of sick days taken by employees in a department was conducted. Three departments with the same number of employees were studied. The management style used in one department was top-down, with employees having little input into decisions. In another department, quality-control experts made recommendations. In the last department, the management gathered input informally from the employees. The total number of sick days taken per month by all the employees in the department was recorded. For a random sample of 3 months, the numbers follow: Top-down management 19 34 28 Quality teams 16 21 15 Informal input 15 12 14 Use a one-way ANOVA to test if the mean number of sick days for departments managed in the various styles are different. Use = 0.05. Copyright © Houghton Mifflin Company. All rights reserved. 7. _____________________________ Part III: Sample Chapter Tests and Answers CHAPTER 11 TEST 160 FORM A PAGE 4 8. Will students perform better if they can choose the section of a course in which they enroll? Does the class status of the student make a difference? A researcher is studying this question. Four blocks of students are formed according to class status: freshman, sophomore, junior, senior. Each student must enroll in Spanish I. The researcher selects a random sample of 10 students from each of the blocks and allows them to enroll in the section of their choice. Another random sample of 10 students from each block is assigned a section of Spanish I. At the end of the semester, all students take the same final exam. The researcher records the scores and compares the scores for all the students participating in the study. (a) Draw a flowchart showing the design of this experiment. 8. (a) __________________________ (b) Does the design fit the model for a two-way ANOVA randomized block design? Explain. (b) __________________________ 9. James drives to work each morning during rush hour. Does commute time depend on route? Does it depend on time of departure? In a study, the times (in minutes) were gathered for random samples. There were four different routes and three different departure times. The results of a two-way ANOVA test are summarized below. ANOVA Source SS d.f. MS F P Value Route 613.4 3 204.5 5.00 0.008 19.1 2 9.5 0.23 0.796 Interaction 357.2 6 59.5 1.45 0.237 Error 982.7 24 40.9 Total 1972.4 35 Departure time (a) Test to see if there is any evidence of interaction between the two factors at a level of significance of 0.01. (b) If there is no evidence of interaction, test to see if there is a difference in mean time based on route. Use = 0.01. 9. (a) __________________________ (b) __________________________ (c) If there is no evidence of interaction, test to see if there is a difference in mean time based on departure time. Use = 0.01. (c) __________________________ Copyright © Houghton Mifflin Company. All rights reserved. Part III: Sample Chapter Tests and Answers CHAPTER 11 TEST 161 FORM B PAGE 1 First, classify the problem as one of the following: Chi-square test of independence Chi-square goodness of fit Chi-square for testing or estimating 2 or F test for two variances One-way ANOVA Two-way ANOVA Then, in each of the problems, when a test is to be performed, do the following: Give the value of the level of significance. State the null and alternate hypotheses. Find the sample test statistic and degrees of freedom. Find or estimate the P value of the sample test statistic. Make a conclusion. Interpret the conclusion in the context of the application. In the case of one-way ANOVA, make a summary table. 1. The Fish and Game Department in Wisconsin stocked a new lake with the following distribution of game fish. Initial Stocking Distribution Fish Pike Trout Perch Bass Bluegill Percent 10% 15% 20% 25% 30% After 6 years, a random sample of 197 fish from the lake was netted, identified, and released. The sample distribution is shown next. Sample Distribution after Six Years Fish Number Pike Trout Perch Bass Bluegill 35 17 33 55 57 Is the sample distribution of fish in the lake after 6 years a good fit to the initial stocking distribution? Use a 5% level of significance. Copyright © Houghton Mifflin Company. All rights reserved. 1. ______________________________ Part III: Sample Chapter Tests and Answers CHAPTER 11 TEST 162 FORM B PAGE 2 2. Is the choice of college major independent of grade average? A random sample of 445 students was surveyed by the registrar’s office regarding major field of study and grade average. In this study, only students with passing grades (A, B, or C) were included in the survey. Grade averages were rounded to the nearest letter grade (e.g., 3.6 grade point average was rounded to 4.0, or A). Grade Average Major A B C Row Total Science 38 49 63 150 Business 41 42 59 142 Humanities 32 53 68 153 Column total 111 144 190 445 Use a 1% level of significance to test the claim that choice of major field is independent of grade average. 2. _____________________________ 3. If we have two normal populations with equal variances, and random samples n1 and n2 are taken from these populations, what probability distribution do we use to test claims about the variances? 3. _____________________________ 4. An automobile service station times its quick lube service for a random sample of 22 customers. The sample standard deviation of time was s = 7.2 minutes. (a) Find a 90% confidence interval for , the population standard deviation of quick lube times. 4. (a) __________________________ (b) The service manager specifies that be 6.0 minutes. Do the sample data indicate that is different from 6.0? Use a 1% level of significance. (b) __________________________ 5. A large national chain of department stores has two basic inventories. Variation of cash flow for the two types of inventories is under study. A random sample of n1 = 9 stores with Inventory I had sample standard deviation of daily cash flow s1 = $3,115. Another random sample of n2 = 11 stores with Inventory II had sample standard deviation of daily cash flow s2 = $2,719. Assume that daily cash flow follows a normal distribution. Test the claim that the population variances of the two inventories are different. Use a 5% level of significance. 5. _____________________________ Copyright © Houghton Mifflin Company. All rights reserved. Part III: Sample Chapter Tests and Answers CHAPTER 11 TEST 163 FORM B PAGE 3 6. Elizabeth watches the sodium content of foods because she has high blood pressure. The sodium content was measured for random samples from each of four different brands of tuna. The results of a one-way ANOVA test are summarized below. ANOVA for Sodium Content Source SS d.f. MS F P Value Between groups 11,786 3 3929 4.37 0.016 Within groups 17,979 20 899 Total 29,766 23 Use a 5% level of significance to test whether there is a difference among the population means. 6. _____________________________ 7. A study of depression and exercise was conducted. Three groups were used: a designed exercise program, a sedentary group, and a group of runners. A depression rating (higher scores, meaning more depression) was given to the participants in each group. Small random samples from each group provided the following data on the depression rating. Treatment group 63 58 61 Sedentary group 71 64 68 Runners 49 52 47 Use a one-way ANOVA to test if the mean depression ratings for the three groups are different. Use = 0.05. 7. _____________________________ 8. A study was conducted to measure sales volume of a grocery store item. The study looked at sales volume for the product placed in three different shelf locations: eye level, low, special display. In addition, the study looked at sales volume for the item when it was advertised in two different ways: on TV or with newspaper coupons. A two-way ANOVA test was used to determine if there was any difference in mean sales volume according to shelf location or advertising method. (a) List the factors and the levels of each factor for this study. (b) Explain what it means to have interaction between the factors. State the null and the alternate hypotheses used to test for interaction. Copyright © Houghton Mifflin Company. All rights reserved. 8. (a) __________________________ (b) __________________________ Part III: Sample Chapter Tests and Answers CHAPTER 11 TEST 164 FORM B PAGE 4 9. A travel agent reserves flights primarily with four major airlines. The agent would like to know if the price depends on the airline or if the price depends on the destination. In a study, the prices were gathered for random samples. There were four airlines and four destinations. The results of a two-way ANOVA test are summarized below. ANOVA Source SS d.f. MS F P Value Airline 19,080 3 6,360 0.66 0.585 Destination 326,793 2 163,397 17.05 0.000 Interaction 49,168 6 8,195 0.85 0.545 Error 230,050 24 9,585 Total 625,091 35 (a) Test to see if there is any evidence of interaction between the two factors at a level of significance of 0.05. 9. (a) __________________________ (b) If there is no evidence of interaction, test to see if there is a difference in mean price based on airline. Use = 0.05. (b) __________________________ (c) If there is no evidence of interaction, test to see if there is a difference in mean price based on destination. Use = 0.05. (c) __________________________ Copyright © Houghton Mifflin Company. All rights reserved. Part III: Sample Chapter Tests and Answers CHAPTER 11 TEST 165 FORM C PAGE 1 Write the letter of the response that best answers each problem. 1. A market research study was conducted to compare three different brands of antiperspirant. The results of the study are summarized below. Use a 5% level of significant to test the claim that opinion is independent of brand. Brand Opinion A B C Total Excellent 29 37 50 116 Satisfactory 83 65 83 231 Unsatisfactory 18 9 6 33 Total 130 111 139 380 A. State the null and alternate hypotheses. 1. A. __________ (a) H0: Opinion and brand are dependent; H1: Opinion and brand are independent. (b) H0: A = B = C ; H1: Not all 1, 2, 3 are equal. (c) H0: Opinion and brand are independent; H1: Opinion and brand are not independent. (d) H0: 12 22 ; H1: 1 = 2. (e) H0: The distributions are normal; H1: The distributions are not normal. B. What is the value of the sample test statistic? (a) 2 = 19.00 (b) 2 = 9.49 (c) d.f. = 4 (d) F = 0.10 B. __________ (e) 2 = 11.9 C. What is the P value of the sample test statistic? C. __________ (a) 0.100 < P value < 0.900 (b) 0.005 < P value < 0.010 (c) P value < 0.005 (d) 0.010 < P value < 0.025 (e) 0.025 < P value < 0.050 D. What is your conclusion? (a) Reject H0. (b) Do not reject H0. Copyright © Houghton Mifflin Company. All rights reserved. D. __________ (c) Cannot determine. Part III: Sample Chapter Tests and Answers CHAPTER 11 TEST 166 FORM C PAGE 2 2. How much do second graders weigh? A county hospital found the weight distribution shown below. Hospital Weight Distribution Weight (lb) Under 45 45–59 60–74 75–89 Over 89 7% 21% 41% 19% 12% Percent An elementary school within the county took a random sample of 125 second graders and obtained the following sample distribution. Sample Distribution, Elementary School Weight (lb) Under 45 45–59 60–74 75–89 Over 89 6 29 50 30 10 Number of second graders Is the sample weight distribution for the elementary school a good fit to the hospital distribution? Use = 0.05. A. State the null and alternate hypotheses. 2. A. __________ (a) H0: 1 = 2 = 3 = 4 = 5; H1: Not all 1, 2, 3, are equal. (b) H0: Weight and percent are independent; H1: Weight and percent are dependent. (c) H0: 12 22 ; H1: 1 = 2. (d) H0: The distributions are the same; H1: The distributions are different. (e) H0: The distributions are the same; H1: The distribution for elementary school is higher. B. What is the value of the sample test statistic? (a) 2 = 11.07 (b) 2 = 5.35 (c) 2 = 4.49 (d) t = 7.27 B. __________ (e) 2 = 9.49 C. What is the P value of the sample test statistic? C. __________ (a) 0.100 < P value < 0.900 (b) 0.050 < P value < 0.100 (c) P value > 0.900 (d) 0.0050 < P value < 0.010 (e) P value < 0.005 D. What is your conclusion? (a) Reject H0. (b) Do not reject H0. D. __________ (c) Cannot determine. Copyright © Houghton Mifflin Company. All rights reserved. Part III: Sample Chapter Tests and Answers CHAPTER 11 TEST 167 FORM C PAGE 3 3. Find the P value for each situation. A. Test statistic 2 30 for a right-tailed test. d.f. = 18. (a) P value < 0.01 (b) P value > 0.05 (c) 0.01 < P value < 0.025 (d) P value = 0.05 3. A. __________ (e) 0.025 < P value < 0.05 B. Test statistic 2 3.5 for a left-tailed test. d.f. = 15. (a) 0.005 < P value < 0.010 (b) P value > 0.05 (c) P value < 0.005 (d) P value = 0.01 B. __________ (e) 0.025 < P value < 0.05 C. Test statistic 2 25 for a right-tailed test. d.f. = 20. (a) P value < 0.100 (b) P value < 0.001 (c) 0.05 < P value < 0.10 (d) P value > 0.100 C. __________ (e) 0.025 < P value < 0.05 4. A salesperson tested 30 sport utility vehicles for gas mileage (in miles per gallon) and found the sample standard deviation to be s = 4.7 mpg. A. Find a 95% confidence interval for 2, the population variance of mileage for all such sport utility vehicles. (a) 14.01 < 2 < 39.91 (b) 15.05 < 2 < 36.17 (c) 2.98 < 2 < 8.49 (d) 14.49 < 2 < 41.29 4. A. __________ (e) 13.64 < 2 < 36.65 B. If the manufacturer specifies that = 4.0 mpg, do the sample data indicate that is larger than 4.0? Use = 0.01, and find the value of the sample test statistic and the P value. (a) 2 = 49.59, 0.005 < P value < 0.010 (b) 2 = 40.04, 0.100 < P value < 0.200 (c) 2 = 41.42, 0.050 < P value < 0.100 (d) 2 = 41.42, 0.005 < P value < 0.010 (e) 2 = 40.04, 0.050 < P value < 0.100 Copyright © Houghton Mifflin Company. All rights reserved. B. __________ Part III: Sample Chapter Tests and Answers CHAPTER 11 TEST 168 FORM C PAGE 4 C. What is your conclusion for the test in Part B? C. __________ (a) There is sufficient evidence to conclude that the standard deviation is larger than 4.0 mpg. (b) There is insufficient evidence to conclude that the standard deviation is larger than 4.0 mpg. 5. Two printing machines are under study. For Machine I, a random sample of n1 = 10 newspapers had a sample standard deviation of time s1 = 1.4 minute. For Machine II, a random sample of n2 = 12 newspapers had a sample standard deviation of s2 = 0.8 minutes. Assume that the times follow a normal distribution. Test the claim that 12 22 using a 1% level of significance. A. State the null and alternate hypotheses. 5. A. ___________ (a) H0: 12 22 ; H1: 12 22 (b) H0: 12 0; H1: 22 0 (c) H0: 12 22 ; H1: 12 22 (d) H0: 12 22 ; H1: 12 22 (e) H0: 12 22 ; H1: 12 22 B. What is the value of the sample test statistic? (a) F = 0.33 (b) F = 1.75 (c) F = 3.06 (d) t = 3.06 B. __________ (e) F = 0.57 C. What is the P value? C. __________ (a) 0.001 < P value < 0.010 (b) 0.025 < P value < 0.050 (c) P value > 0.100 (d) P value < 0.100 (e) P value < 0.001 D. What is your conclusion? (a) Reject H0. (b) Do not reject H0. D. __________ (c) Cannot determine. Copyright © Houghton Mifflin Company. All rights reserved. Part III: Sample Chapter Tests and Answers CHAPTER 11 TEST 169 FORM C PAGE 5 6. Do cough medicines differ in the length of time of relief? The relief time was recorded for random samples of volunteers for each of four different brands of cough medicine. The results of ANOVA test are summarized below. ANOVA Source SS d.f. MS F P Value Between groups 6.17 3 2.056 2.11 0.122 Within groups 27.26 28 0.974 Total 33.43 31 Use a 5% level of significance to test whether there is a difference among the population means. A. What are the null and alternate hypotheses? 6. A. __________ (a) H0: 1 = 2 = 3 = 4; H1: Not all of the means are equal. (b) H0: 1 = 2 = 3 = 4; H1: 1 > 2 > 3 > 4. (c) H0: 1 = 2 = 3; H1: Not all of the means are equal. (d) H0: 12 22 32 42 ; H1: 12 22 32 42 . (e) H0: 1 2 3 4; H1: 1 = 2 = 3 = 4. B. What is the value of the sample test statistic? (a) F = 6.85 (b) F = 2.056 (c) F = 0.974 (d) F = 0.122 B. __________ (e) F = 2.11 C. What is the P value? C. __________ (a) 0.974 (b) 2.95 (c) 2.056 (d) 0.122 (e) 2.11 D. What is your conclusion? (a) Reject H0. (b) Do not reject H0. Copyright © Houghton Mifflin Company. All rights reserved. D. __________ (c) Cannot determine. Part III: Sample Chapter Tests and Answers CHAPTER 11 TEST 170 FORM C PAGE 6 7. An ornithologist is studying the length (in seconds) of bird calls. Random samples from three different breeds yielded the following results. Breed 1 2.3 1.9 2.1 Breed 2 0.8 1.2 1.1 Breed 3 2.0 1.4 1.7 Use one-way ANOVA to test if the mean call length differs for the three breeds. Use = 0.05. A. What are the null and alternate hypotheses? 7. A. __________ (a) H0: 1 2 3; H1: 1 = 2 = 3. (b) H0: 12 22 32 ; H1: 12 22 32 . (c) H0: 1 = 2 = 3; H1: Not all of 1, 2, 3 are equal. (d) H0: 1 2 3; H1: 1 > 2 > 3. (e) H0: The distributions are the same; H1: The distributions are not the same. B. What is the value of the sample test statistic? (a) F = 0.005 (b) F = 19.33 (c) 2 = 15.08 (d) F = 15.08 B. __________ (e) F = 5.14 C. What is the P value? C. __________ (a) 0.871 (b) 0.05 (c) 0.010 (d) 0.005 (e) 15.08 D. What is your conclusion? (a) Reject H0. (b) Do not reject H0. D. __________ (c) Cannot determine. Copyright © Houghton Mifflin Company. All rights reserved. Part III: Sample Chapter Tests and Answers CHAPTER 11 TEST 171 FORM C PAGE 7 8. When performing a two-way ANOVA test, which of the following is not a required assumption? 8. __________ (a) There are the same number of measurements in each cell. (b) The measurements in each cell of a two-way ANOVA model are assumed to come from distributions with approximately the same variance. (c) There are the same number of levels for each factor. (d) The measurements in each cell come from independent random samples. (e) The measurements in each cell of a two-way ANOVA model are assumed to be drawn from a population with a normal distribution. 9. Are differences in test scores due to schools or are they due to exam forms? Three different, although supposedly equivalent, forms of a standardized achievement exam were given to a random sample of students in each of four different schools. Their scores were recorded. The results of a two-way ANOVA test are summarized below. ANOVA Source SS d.f. MS F P Value 3,532 2 1,766 8.61 0.002 School 749 3 250 1.22 0.324 Interaction 768 6 128 0.62 0.712 Error 4,917 24 205 Total 9,965 35 Exam form A. When conducting a test to see if there is evidence of interaction between the factors, what are the values of the test statistic and the P value? (a) F = 8.61; P value = 0.002 (b) F = 1.22; P value = 0.324 (c) F = 0.62; P value = 0.712 (d) F = 128; P value = 0.05 9. A. __________ (e) F = 8.62; P value = 0.002 B. What is your conclusion from the test in part A? Use = 0.05. (a) Do not reject H0; there is evidence of interaction. (b) Do not reject H0; there is no evidence of interaction. (c) Reject H0; there is evidence of interaction. (d) Reject H0; there is no evidence of interaction. (e) Cannot determine. Copyright © Houghton Mifflin Company. All rights reserved. B. __________ Part III: Sample Chapter Tests and Answers CHAPTER 11 TEST 172 FORM C PAGE 8 C. Assume that there is no evidence of interaction between the factors. When conducting a test to see if there is a difference in mean scores based on an exam form, what are the critical F value and the value of the test statistic? (a) F = 8.61, P value = 0.002 (b) F = 1.22; P value = 0.324 (c) F = 0.62; P value = 0.712 (d) F = 3.40; P value = 0.002 C. __________ (e) F = 8.61; P value = 0.712 D. Assume that there is no evidence of interaction between the factors. When conducting a test to see if there is a difference in mean scores based on school, what are the value of the test statistic and the P value? (a) F = 8.62; P value = 0.002 (b) F = 0.62; P value = 0.712 (c) F = 1.22; P value = 0.002 (d) F = 1.22; P value = 0.324 D. __________ (e) F = 3.01; P value = 0.05 E. What are your conclusions from the tests in parts C and D? Use = 0.05. E. __________ (a) Cannot determine. (b) Do not reject H0 from C; do not reject H0 from D. (c) Do not reject H0 from C; reject H0 from D. (d) Reject H0 from C; reject H0 from D. (e) Reject H0 from C; do not reject H0 from D. Copyright © Houghton Mifflin Company. All rights reserved.