CONTENTS Introduction 4 Section 1: Structure of micro-organisms 5 Section 2: Microbial metabolism 21 Section 3: Patterns of growth 31 Section 4: Copying and translating genes 39 Section 5: Genetic engineering 56 Section 6: Infection and immunity 67 Bibliography 74 Appendix: Advice for problem-solving outcomes 76 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- SECTION 4 Copying and Translating Genes In Section 1 of this unit (Structure of Micro-organisms), you were introduced to the concept that all cells have a genome organised into chromosomes, which control all the activities of the cell. The genome itself consists of a series of genes, many of which code for proteins. These genes are made of a nucleic acid called deoxyribonucleic acid (DNA). In this section you will find out about the following: the structure of deoxyribonucleic acid; how genes control the cell by directing the making of proteins within the cell; how genes in prokaryotes are regulated. The structure of DNA The genes that make up a chromosome are made of a nucleic acid called deoxyribonucleic acid (shortened to DNA). This is a long, threadlike molecule consisting of two strands twisted into a helical (spiral) molecule. The building blocks of each strand of the DNA molecule are called nucleotides that are joined together to form a long chain. Each nucleotide consists of three components: a phosphate group, a sugar molecule called deoxyribose and an organic base. These three components are arranged in the following way: © Learning and Teaching Scotland 39 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Copying and Translating Genes The deoxyribose sugar is given a special numbering system in that each carbon atom (of which there are 5) is given a number. The carbon atoms of the sugar that are known as 3´(said 3 prime) and 5´(said 5 prime) are shown in the above diagram. There are 4 organic bases found in a DNA molecule, namely ADENINE (A), GUANINE (G), CYTOSINE (G) and THYMINE (T), and so there are 4 different types of nucleotides found in DNA, each containing a different organic base. As mentioned, the nucleotides join together to make a long strand of DNA. The phosphate group linked to the 5’ end of one nucleotide joins to the 3’ of the sugar of the neighbouring nucleotide, thus forming a phosphate–sugar backbone. In this way the nucleotides form a long single strand of DNA, one end with a 5’ phosphate and the other end with a free 3’ group on the sugar. Two strands of nucleotides link together with weak hydrogen bonds between their organic bases. The two strands of nucleotides run in opposite directions to each other, so they are said to be antiparallel. One strand starts with a 5´ end and finishes with a 3´ end, while the other strand starts with a 3~end and finishes with a 5´ end: 5´ _________________________________________ 3´ 3´ _________________________________________ 5´ Each organic base in a nucleotide from one strand can form a hydrogen bond with only one other type of organic base in a nucleotide in the other strand: A bonds only with T C bonds only with G A-T and C-G are known as base pairs. A fragment of double stranded DNA showing only the sequence of organic bases in each strand is represented below: 5´ AGCTTGCATTAACGTCGC 3´ 3´ TCGAACGTAATTGCAGCG 5´ One strand is known as the sense strand, while the other is called the antisense strand. You will come across these terms again when the making of another type of nucleic acid (called messenger ribonucleic acid) is discussed. © Learning and Teaching Scotland 40 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Copying and Translating Genes The double strand of DNA is twisted into a structure called a double helix. This resembles a spiral staircase with the phosphate-sugar backbone forming the uprights and the base pairs forming the rungs (Fig. 18). Chromosomes and genes in eukaryotes In eukaryotes chromosomes are found in the nucleus. Under a very high powered microscope the chromosomes appear to be striped. Each stripe represents one single gene, so eukaryotic chromosomes are made up of lots of genes. Many of the genes in a chromosome contain the genetic code (DNA) needed to make proteins. When a protein is made from a gene (DNA), the gene is said to be ‘expressed’. It has been found that only some parts of a gene (DNA) are expressed. These parts are known as exons or coding regions of the gene. The parts of the gene that do not code for protein are called introns or intervening, non-coding regions. Chromosomes and genes in prokaryotes Prokaryotes have a single circular chromosome. It has been found that genes which have a related function are grouped together in prokaryotes. This group of genes is called an operon. You will find out more about operons in prokaryotes later. Not all genes needed by a prokaryote are found on the circular chromosome. Some bacterial genes are found on a plasmid. This is a small circular piece of double stranded DNA. Plasmids are found naturally in bacteria and generally carry genes that are advantageous to the bacteria, but are not essential for their survival. For example, some plasmids have genes that allow the bacteria to grow on certain antibiotics. Plasmids can be transferred from one bacterium to the next, so the advantageous genes can be passed on. © Learning and Teaching Scotland 41 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Copying and Translating Genes Plasmids have been isolated and manipulated by biotechnologists for use in genetic engineering. It is now possible to use plasmids as cloning vectors to introduce new genes into bacteria, to grow the bacteria and for the bacteria to express the new genes and so produce new proteins. DNA replication When a cell divides into two, the two new cells are called daughter cells. The daughter cells have exact copies of the chromosomes that were present in the original parent cell. Before the cell can divide, the DNA molecules must be duplicated exactly. The duplication of the DNA molecules is known as DNA replication. Several factors are required for the replication of a DNA molecule: Double stranded DNA (to act as a template for the new DNA) An enzyme called DNA polymerase Each of the four nucleotides (A, T, C and G bases); Energy in the form of ATP. The steps involved in the replication of DNA are as follows: 1. The parental double stranded DNA to be replicated (or copied) begins to untwist from its helical shape. 2. Hydrogen bonds between complementary bases (A-T and G-C) are broken. This causes the two strands to separate, forming two single strands of DNA. 3. A free DNA nucleotide finds its complementary base on the single strand of DNA. For example, if there is a T on the single strand of DNA, a free A nucleotide lines up with it, similarly if there is a G on the single strand, then a C nucleotide lines up with it. 4. A hydrogen bond forms between the free DNA nucleotide and its complement. 5. The 5´ phosphate group of this new nucleotide joins to the free 3´ of the adjacent nucleotide, thus continuing the formation of the new DNA strand. The enzyme which joins (polymerises) one nucleotide to the next is called DNA polymerase. 6. The newly formed daughter DNA molecule rewinds into a double helix. © Learning and Teaching Scotland 42 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Copying and Translating Genes At the end of DNA replication, two new strands of DNA are formed that are identical to each other and the parental DNA molecule. DNA mutations Sometimes when DNA is being replicated, mistakes happen and the wrong nucleotide is inserted into or a nucleotide is missed out of the new DNA. This is known as a mutation in the DNA. Table 6 shows some of the mutations that can occur in a DNA molecule: © Learning and Teaching Scotland 43 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Copying and Translating Genes Table 6 Mutation Description of the mutation Substitution This is when a nucleotide is substituted for another nucleotide. For example, in the DNA sequence TTGCTAAGCCGT, the 5th T may be substituted for a G. The new sequence would be TTGCGAAGCCGT. Insertion This is when an extra nucleotide is introduced into a DNA molecule. Taking the above sequence as an example, the mutated sequence may be TTGCTAAGACCGT where an extra A nucleotide has been inserted. Deletion This is when a nucleotide is removed from the original sequence. For example, TTGCTAAGCCGT may become TTGCTAGCCGT where the 6th A has been deleted from the sequence. Inversion This is when two nucleotides are inverted. For example, in the sequence TTGCTAAGCCGT the 3rd and 4th nucleotide may change place so that the mutated sequence becomes TTCGTAAGCCGT. The structure of protein As mentioned previously, many genes in the chromosomes of eukaryotes and prokaryotes code for proteins. Proteins are large, complex molecules that carry out many functions in the cell as described below. Some proteins have a structural role in the cell Some proteins are enzymes and carry out biochemical reactions in the cell such as those involved in respiration. There are proteins that are involved in preventing infection in the body. These proteins are known as antibodies Other proteins are involved in the transport of substance around the body. For example, haemoglobin is involved in the transport of oxygen in red blood cells. Proteins are made of building blocks called amino acids that join together by strong peptide bonds to make large polypeptide (protein) molecules. © Learning and Teaching Scotland 44 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Copying and Translating Genes The amino acids that join together to form a polypeptide chain are known as the primary structure of a protein. In a cell this polypeptide chain folds again into a secondary, then again into a tertiary structure (a three dimensional (3D) shape). The 3D shape is the most compact, stable structure that the protein can form. This 3D shape is held in place by weak hydrogen bonds. A protein must be in its correct 3D shape for it to work (function) properly in the cell. Anything that causes a change in the 3D shape of the protein (such as a change in temperature or a change in pH) can affect the function of the protein. Before proteins can be made by a cell, another type of nucleic acid is needed, called RNA. The structure of RNA Ribonucleic acid (RNA) is the second type of nucleic acid found in the cell. It consists of nucleotides polymerised together, although the structure of an RNA nucleotide is slightly different to a DNA nucleotide. An RNA nucleotide consists of the following: a phosphate group a ribose sugar group an organic base In RNA, the organic bases are Adenine (A), Cytosine (C), Guanine (G) and Uracil (U). Copying and Translating Genes The ribose sugar group from one RNA nucleotide joins to the phosphate group of a second RNA nucleotide, forming a single polymerised chain. RNA does not exist as a double stranded molecule, instead it is single stranded. The differences between the structures of DNA and RNA are shown in Table 7. © Learning and Teaching Scotland 45 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------Table 7 Feature DNA RNA Number of nucleotide strands present in one molecule Two One Bases found in the nucleotides A, G, C, T A, G, C, U Sugar present in the nucleotides Deoxyribose Ribose The synthesis of RNA RNA is made in the nucleus of the cell, using one of the strands of DNA as a template. The strand that is used as the template is known as the sense strand. Thus, the information that is coded for in the DNA molecule is transferred to the RNA molecule which is then exported from the nucleus to the cytoplasm. The synthesis of RNA is called transcription. There are several types of RNA transcribed from DNA. One type of RNA is called messenger RNA (mRNA) and another type of RNA is called transfer RNA (tRNA). Both types of RNA are involved in the synthesis of protein. The synthesis of mRNA In eukaryotes, the genes from the DNA strand that are used to synthesise mRNA are not continuous. This means that the DNA contains nucleotide sequences that do not appear in the mature mRNA. These intervening sequences are called introns and they are cut out of newly formed mRNA molecules in a process known as splicing. This is shown in Fig. 21. © Learning and Teaching Scotland 46 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Copying and Translating Genes Figure 21 GENE (DNA) Exon 1 Intron 1 Exon 2 Intron 2 Exon 3 RNA Synthesis RNA Exon 1 Intron 1 Exon 2 Intron 2 Exon 3 Introns are removed Mature mRNA Exon 1 Exon 2 Exon 3 The mature mRNA molecule is exported from the nucleus consisting only of exon sequences and is then used to synthesise protein. Protein synthesis Each protein in the cell of an organism is coded for by a gene found in the chromosomes of that organism. The gene (DNA) is used to synthesise a mRNA molecule which, in turn, is used to direct the synthesis of the protein molecule. The information on the DNA is known as the genetic code. The sequence of bases along a DNA strand represents a code for making proteins. DNA contains 4 bases (ACGT) yet proteins contain about 20 amino acids. The relationship cannot be that 1 base represents (codes) for 1 amino acid as this would allow only 4 amino acids to be coded. Even 2 bases coding for 1 amino acid is insufficient as this allows for only 16 amino acids. It has been found that 3 bases in the DNA code for 1 amino acid. The triplet of 3 bases is known as a codon. There are 64 codons and some amino acids have more than one codon. The codons are arranged in a specific order to code for a specific protein. Remember that the DNA is transcribed into mRNA. The mRNA that is produced contains the complementary sequence of codons to the sense strand of DNA. Remember also that RNA has uracil (U) instead of thymine (T). © Learning and Teaching Scotland 47 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Copying and Translating Genes For example: DNA { TTTCTTTAGGGT { AAAGAAATCCCA (sense strand) The sense strand is used as the template to make mRNA mRNA UUUCUUUAGGGU (this sequence is complementary to the sense strand of DNA) Table 8 shows some of the codons that specify different amino acids. Table 8 Codon Amino acid Codon Amino acid UAG Tyrosine GUG Valine UUU Phenylalanine CCA Proline AGU Serine UGG Tryptophan CUU Leucine AGA Arginine GGU Glycine UCA Serine Using this table we can work out the sequence of amino acids that would be produced using the mRNA (UUUCUUUAGGGU) from the above example: Phenylalanine-Leucine-Tyrosine-Glycine This table can also be used to show that a mutation in the gene can cause a change in the sequence of the protein. If there was a mutation such that the first U in the sequence was replaced by a C (look back to the previous section to find out the name of such a mutation), then the sequence of amino acids would change to: Leucine-Leucine-Tyrosine-Glycine Sometimes a change in the amino acid sequence has no effect on the function of the protein but in some cases, the protein may become inactive. mRNA is not the only RNA molecule involved in making protein, tRNA is needed too. tRNA is a small molecule that attaches to an amino acid in the cytoplasm of the cell. There is a different tRNA molecule for each amino acid. At the opposite end to where the amino acid is attached to tRNA, there is a triplet of bases called the anticodon. The anticodon corresponds to a particular amino acid. The tRNA carries the amino acid to the ribosome, where proteins are made. © Learning and Teaching Scotland 48 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Copying and Translating Genes © Learning and Teaching Scotland 49 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Copying and Translating Genes The interaction between mRNA, tRNA and the ribosome is shown in Fig. 22. When two tRNA molecules are present within a ribosome, a peptide bond forms between the amino acids. Ribosomes are small spherical structures found in the cytoplasm of the cell. They are the site of protein synthesis. Each ribosome contains all the components (proteins and RNA) required to make new proteins in the cell. In prokaryotes, ribosomes are free in the cytoplasm whereas in eukaryotes they are often found attached to internal membranes, forming the organelle known as the rough endoplasmic reticulum. The rough endoplasmic reticulum is involved in transporting the newly made protein to another organelle, the Golgi apparatus. Proteins are modified, then packaged by this organelle before being secreted out of the cell. Control of gene action Some proteins are required by a cell only under certain conditions, e.g. E.coli require the enzyme β-galactosidase only where the bacteria are growing on lactose. When E.coli are growing on a different medium, such as glucose, the genes that code for β-galactosidase are switched off. The advantage of this control is that resources within the bacterial cell are not wasted. Three areas of bacterial DNA are involved in the control of β-galactosidase activity: The structural gene codes for the enzyme The regulator gene codes for a protein known as the repressor The operator is where the repressor binds. These three areas are found together on the DNA in an area known as the lac operon as shown in Fig. 23. Copying and Translating Genes © Learning and Teaching Scotland 50 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Regulator gene Operator Structural gene In the absence of lactose When no lactose is present in the culture medium, E.coli does not need the βgalactosidase enzyme. Therefore the gene coding for this enzyme is switched off. The gene is switched off due to the presence of the repressor protein (coded for by the regulator gene). The repressor protein binds to the operator and switches off the structural gene. This is shown below: © Learning and Teaching Scotland 51 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Copying and Translating Genes Figure 24: The lac operon in the absence of lactose © Learning and Teaching Scotland 52 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Copying and Translating Genes In the presence of lactose When E.coli is grown in culture medium containing lactose, β galactosidase is produced. The enzyme breaks down lactose into glucose and galactose and the bacteria use the glucose for growth: Lactose glucose + galactose Lactose is called an inducer as it switches the structural gene on, so producing the enzyme. This is shown in Fig. 25. Figure 25: The lac operon in the presence of lactose Regulator gene Operator Structural gene Lactose binds to the repressor molecule, which prevents the repressor from binding to the operator. Therefore RNA is produced from the structural gene. If RNA is made, then it can be used to synthesise the enzyme. © Learning and Teaching Scotland 53 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Copying and Translating Genes Test yourself on DNA structure and protein synthesis Before you move onto the next part of this unit, spend time reviewing your notes on the above section. It contains a lot of information. 1. Give two differences between the structure of DNA and RNA. 2. The sense strand of a piece of DNA has the following sequence: 5´ AGTGGTACCGAACAC 3´ (a) Write down the sequence of the corresponding antisense strand. (b) Write down the sequence of mRNA that would be produced if the sense strand was transcribed. (c) Use Table 8 to find out the sequence of amino acids that would be produced using the mRNA from (b). 3. A DNA molecule consists of 24% cytosine bases. Calculate the percentage number of thymine bases that would be present in this DNA molecule. 4. Describe the steps involved in the replication of a DNA molecule. 5. Complete Table 9, which is about mutations: Table 9 Type of mutation Description of mutation Substitution When an extra nucleotide is inserted into a DNA molecule Inversion When a nucleotide is removed from a DNA sequence © Learning and Teaching Scotland 54 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Copying and Translating Genes 6. Describe the process of splicing in the synthesis of mRNA. 7. What is the role of the following types of RNA in the synthesis of protein: (a) mRNA (b) tRNA. 8. Describe the functions of the following organelles in the cell in protein synthesis: (a) ribosome (b) rough endoplasmic reticulum (c) Golgi apparatus. 9. Fig. 26 shows the lac operon found in bacteria such as E.coli. (a) Name protein Y and protein Z. (b) State whether protein Y and protein Z are produced: (i) in the absence of lactose (ii) in the presence of lactose. Figure 26 Regulator gene Protein Y © Learning and Teaching Scotland Operator Structural gene Protein Z 55 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- SECTION 5 Genetic Engineering Genetic engineering may be defined as the deliberate change of the genetic makeup of an organism. This can be achieved by the introduction of genes from another organism. In this way, organisms with new characteristics are produced in a way that is not possible using conventional breeding methods. Genetic engineering is a rapidly growing technology and it is thought that it will have profound effects on our everyday lives. Some examples of how it may affect us are given below. In the field of medicine it may improve the diagnosis and cure of hereditary defects and disease. It is being used for the development of new drugs and vaccines for use by humans and animals. In agriculture it is being used to improve food production. It is being used to monitor and reduce environmental pollution. In Scotland, one of the fastest growing industries is biotechnology. Numerous biotechnology companies have been set up, many using the techniques of genetic engineering. In this section of the unit you will be introduced to some of the techniques used in genetic engineering. The most basic technique associated with genetic engineering is gene cloning. Gene cloning itself involves several techniques including: the isolation and purification of DNA cutting DNA into smaller fragments with enzymes separating fragments of DNA using electrophoresis introducing fragments of DNA into organisms using cloning vectors. The end result of gene cloning is the production of an organism that is able to make many copies of the newly introduced DNA. Purification of DNA The first step in many genetic engineering processes is the isolation of DNA from cells. There are several steps involved in DNA purification and these are outlined below. © Learning and Teaching Scotland 56 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Genetic Engineering Firstly, the cells must be disrupted to release the soluble intracellular components, including the DNA. This can be done mechanically by putting the cells into a liquidiser/blender – similar to the one in your kitchen! Alternatively, cells can be disrupted using enzymes. The soluble intracellular components are separated from insoluble cellular debris by centrifugation, a technique that separates components using high speed centrifugal forces. The second step in DNA purification involves separating the DNA from proteins. This is achieved by extracting the proteins into an organic solvent and/or using enzymes that degrade the proteins, leaving purified DNA. Finally, the DNA is precipitated using alcohol and then resuspended in a suitable buffer. Restriction endonucleases After DNA has been purified, it is cut into smaller fragments using restriction endonucleases. These are enzymes that are found naturally in bacteria. These enzymes recognise and cut short specific sequences (between 4 and 8 base pairs) within DNA. Biotechnologists have isolated many of these enzymes and they are now routinely used in genetic engineering for cutting DNA. One of the most commonly used restriction enzymes is called EcoR1. It recognises the following 6-base pair DNA sequence: 5´ GAATTC 3´ 3´CTTAAG 5´ EcoR1 then cuts the DNA sequence as follows: 5´G 3´ CTTAA AATTC 3´ G 5´ When EcoR1 cuts DNA it produces two double stranded fragments, but the cuts do not occur at the same position. Instead the cut is staggered by four nucleotides, so that the DNA fragments have single stranded overhangs (known as sticky ends). If another piece of DNA is cut with the same enzyme and so has the same sticky ends, the pieces of DNA can be joined together by base pairing between the sticky ends. Other restriction endonucleases cut in the middle of their recognition sequence so producing blunt ends. © Learning and Teaching Scotland 57 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Genetic Engineering Agarose gel electrophoresis This is a technique used to separate fragments of DNA according to their size. It is often used to separate fragments of DNA after digestion with restriction endonucleases. A solution of warm agarose is poured into a casting tray. A comb is inserted in one end of the tray and the gel is allowed to cool causing the agarose to set. After it has set, the comb is removed forming a number of wells. Different concentrations of agarose can be used, the higher the concentration of agarose, the slower the rate of movement of the DNA fragments. The agarose gel has very small pores that act as a molecular sieve and causes DNA of different sizes to separate from each other as follows: Small fragments of DNA move fastest through the gel Large DNA fragments move slowly through the gel. The DNA fragments to be separated are mixed with a tracking dye and loaded into the wells. DNA is negatively charged and, when a voltage is applied to the gel, the DNA migrates towards the positively charged anode. The power supply is switched off when the tracking dye reaches the end of the gel. After electrophoresis the DNA fragments can be visualised by staining the gel with a dye that binds to the DNA. Fig. 27 shows an agarose gel with DNA fragments that have been stained and so can be easily seen. © Learning and Teaching Scotland 58 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Genetic Engineering Lanes 1 and 7 contain DNA fragments of known size. Lanes 2–6 contain plasmid DNA of different sizes. Locating a fragment of DNA separated by electrophoresis After separating DNA fragments on an agarose gel, one particular DNA fragment may need to be located. For example, if chromosomal DNA is cut up into smaller fragments, one of the smaller fragments may contain a gene that a biotechnologist is interested in. How is this fragment located? Firstly, the DNA is transferred from the agarose gel to a membrane filter. This step is needed because the double stranded DNA must be denatured into single strands. This is almost impossible to do while the DNA is in agarose. The DNA is transferred to the membrane by a process known as blotting. Then the DNA is denatured. The membrane containing the single stranded DNA is incubated with either single stranded DNA or RNA (known as a probe) that contains some bases complementary to the fragment of DNA to be located. The complementary bases in the probe and the desired fragment of DNA join together, forming double stranded DNA. © Learning and Teaching Scotland 59 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Genetic Engineering The fragment of DNA located by the probe is visualised because the probe is labelled either with radioactivity or with a chemiluminescent label, making it easy to see. The production of complementary DNA from RNA Sometimes biotechnologists do not want to work with genes because they contain introns that are not used to make protein. (Look back at Section 4 to remind yourself about introns and exons.) Instead, some biotechnologists work with messenger RNA (mRNA) which is the expressed form of the gene. However, working with RNA is difficult because it is single stranded and so it cannot easily be inserted into a cloning vector such as a plasmid. Also, RNA is degraded very easily and so can be difficult to use. However, these problems working with RNA can be overcome by converting RNA into DNA (known as complementary DNA or cDNA) using an enzyme called reverse transcriptase. cDNA is a direct copy of the mRNA but, unlike the original gene, it does not contain introns. cDNA can be inserted easily into a cloning vector and cloned in the usual manner. Fig. 28 shows the steps taken to make cDNA from a mRNA template. © Learning and Teaching Scotland 60 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Genetic Engineering Firstly the mRNA is used by reverse transcriptase as a template to synthesise the first strand of DNA. A DNA-RNA hybrid is formed. The RNA in the DNA-RNA hybrid is removed using alkali. The remaining single stranded DNA is used as a template by the enzyme DNA polymerase to make a second complementary strand of DNA. The cDNA can now be inserted into a cloning vector, such as a plasmid and cloned to produce many identical copies of the cDNA. Transformation and cloning Transformation is the name used to describe the process when a foreign sequence of DNA (such as a gene or cDNA) is introduced into micro-organisms such as bacteria and yeast. Two micro-organisms that are commonly used in transformations are the bacterium E.coli and the yeast, S. cerevisiae. Both micro-organisms are single celled (unicellular) organisms that have fast reproduction rates and thus are quick growing. This makes them ideal for large scale production in industrial fermenters (bioreactors). E.coli This is a prokaryote that is often used as a recipient for foreign DNA. Large sequences of foreign DNA can be inserted into E.coli using a plasmid. The DNA is transcribed and translated and it is possible for the protein coded for by the foreign DNA to account for 60% of the total protein produced by the bacterial cell. E.coli are relatively easy to transform. While there are many advantages of using E.coli, there are some disadvantages – mainly due to the fact that it is a prokaryote and the foreign protein produced may originally have come from a eukaryote. The disadvantages are outlined below. The foreign protein produced is not always secreted easily from E.coli. This may be due to E.coli not being able to carry out modifications to the protein after it is made, for example addition of sugar groups. If the protein is not secreted by the bacterium, it causes problems for the biotechnologist as E.coli must be harvested, the bacterial cells broken open (lysed), and the protein purified. This increases the production costs. E. coli does not always fold the foreign protein into its natural 3D shape. This causes the protein to be inactive. © Learning and Teaching Scotland 61 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Genetic Engineering S. cerevisiae This is a eukaryote (it is a yeast) that can be used instead of E.coli as the recipient for foreign DNA. Since it is eukaryotic, it can fold proteins into their 3D shape which allows the proteins to be active. Foreign proteins made by S. cerevisiae are secreted from the cell as S. cerevisiae can carry out post-translational modifications (e.g. it can add sugar groups to proteins) which allows the proteins to cross the cell wall. Thus proteins secreted by S. cerevisiae can be extracted from the culture medium. The disadvantages of using yeast include the following: It can be difficult to transform, this means that it can be difficult to introduce the foreign DNA into the yeast It produces less protein, so yields of the foreign protein are smaller Plasmid vectors may be lost from yeast if there is no advantage to the yeast in having the plasmid. Cloning vectors Cloning vectors are used to introduce foreign DNA into micro-organisms such as E.coli and S. cerevisiae. Cloning vectors must be able to replicate within these host cells. Two types of cloning vectors used to introduce foreign DNA sequences into micro-organisms are plasmids and bacteriophages. Both of these cloning vectors have been mentioned previously. Plasmids are discussed in the section on bacteria and bacteriophages are mentioned in the section on viruses. You might find it helpful to read these sections again before continuing. Both occur naturally in bacteria but biotechnologists have genetically engineered them so that they can be used as cloning vectors. Cloning vectors have been manipulated so that they have the following characteristics: 1. They can be cut with restriction enzymes and foreign DNA sequences (cut with the same restriction enzymes) can be inserted into them using an enzyme called DNA ligase. 2. Antibiotic resistance marker genes have been added to them. These genes code for proteins that breakdown antibiotics. If a cloning vector is inserted into a micro-organism, the micro-organism gains the antibiotic resistance gene and so is able to grow in the presence of this antibiotic. The micro-organism becomes resistant to the antibiotic. 3. Some cloning vectors contain part of the lac operon. This is used to control the expression of the foreign DNA sequences. The foreign DNA is transcribed and translated only when the lac operon is switched on. © Learning and Teaching Scotland 62 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- After a foreign sequence of DNA has been inserted into a cloning vector using DNA ligase, the cloning vector is mixed with the micro-organism into which it is to be transformed. Some of the micro-organisms will take up the cloning vector, some will not. To separate the transformed micro-organism from those that are not, the micro-organism is grown in media containing the antibiotic to which the transformed micro-organism has acquired resistance. The transformed microorganism has the cloning vector that has the antibiotic resistance gene, so it is able to grow in the presence of the antibiotic. Any micro-organism that does not possess the cloning vector is unable to grow in this medium. The transformed micro-organism is isolated from the medium and transferred to another medium where it is allowed to reproduce and grow in large quantities. Each new micro-organism that is produced is genetically identical to the original transformed micro-organism. Each genetically identical micro-organism is called a clone. The process of producing lots of genetically identical micro-organisms is known as cloning. This is shown in Fig. 29. © Learning and Teaching Scotland 63 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Genetic Engineering © Learning and Teaching Scotland 64 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Genetic Engineering Test yourself on genetic engineering Before you move onto the next part of this unit, spend a little time reviewing your notes on genetic engineering, then see if you can answer the questions below. 1. Fig. 30 represents a human chromosome showing the possible position of the human insulin gene. (a) Name the type of enzyme that can be used to break the chromosome into smaller fragments. (b) The above chromosome is broken into smaller fragments with the following sizes: Table 10 Fragment Size of fragment (base pairs) W 250 X 345 Y 400 Z 750 Fragments were separated by agarose gel electrophoresis. © Learning and Teaching Scotland 65 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Genetic Engineering Complete the diagram to identify which band corresponds to which fragment. (c) One of the bands is known to contain the gene for insulin. Describe how you might use a probe to find out which band contains the gene. 2. Given the following components, describe how you could obtain clones of an insulin gene: Components available: Insulin gene plasmid vector with ampicillin resistant gene Bacterial cells restriction enzymes Ligase nutrient medium containing ampicillin (Note: ampicillin is an antibiotic) 3. State 2 advantages of using yeast rather than bacteria in producing clones of a gene. 4. The following questions refer to the making of cDNA. (a) Name the enzyme used to convert RNA into DNA. (b) What is the purpose of incubating the RNA/DNA hybrid with alkali? (c) Name the enzyme that is used to make the second complementary strand of DNA. © Learning and Teaching Scotland 66 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- SECTION 6 Infection and Immunity Micro-organisms as pathogens Micro-organisms such as bacteria and fungi can be advantageous to man in that they can be used to produce useful substances such as yoghurt, cheese, beer, wine and antibiotics, to name but a few. However, it must be remembered that not all micro-organisms are beneficial, some are harmful and cause disease. Micro-organisms that cause disease are known as pathogens. Many species of bacteria, fungi and viruses are pathogenic. However, your body has developed an immune system that removes pathogens and provides you with natural immunity if the pathogen should enter your body again. Production of antibodies and the role of blood cells When a pathogen enters your body, your immune system responds by producing antibodies. Any substance that causes your immune system to produce antibodies is known as an antigen. So a pathogen is also an antigen. An antigen is generally anything that is foreign to (or not normally part of) your body. Antibodies are protein molecules that have the following basic structure: Figure 31 © Learning and Teaching Scotland 67 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Infection and Immunity There are generally two sites on each antibody molecule that bind specifically to a particular antigen. The production of antibody molecules is part of your natural immunity. You are constantly being exposed to pathogens (and other antigens) and so you produce antibodies to build up a natural immunity to them. There are two main cells that are involved in natural immunity: B-lymphocytes and T-lymphocytes. Each of these different cell types is discussed below: B-lymphocytes and the humoral response When a pathogen enters your body, a group of cells known as B-lymphocytes bind to the pathogen. This causes the B-lymphocytes to multiply into two different types of B-lymphocytes. The first type of B-lymphocyte produces antibodies that then bind to the pathogen and help to remove it from your body. The production of antibodies by this type of B-lymphocyte is known as the humoral response. It takes about two weeks for antibodies to be produced and a pathogen cleared from your body. The second type of B-lymphocyte circulates in your blood for many years after the pathogen has first entered your body and been destroyed. If the pathogen enters your body again at a later date, these B-lymphocytes produce and secrete many antibodies very quickly and these help to destroy the pathogen before it can do harm to your body and before any symptoms of the disease appear. T-lymphocytes and the cell-mediated response When a T-lymphocyte is involved in immunity, it is known as the cell-mediated response. There are several different types of T-lymphocytes. The first type of T-lymphocyte is one of the most important cells in the immune system because it has a regulatory role. It activates and controls B-lymphocytes, other T-lymphocytes and other cells of the immune system. The second type of T-lymphocyte destroys any body cell that has been infected by a pathogen. © Learning and Teaching Scotland 68 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Infection and Immunity The function of macrophage B- and T-lymphocytes are not the only cells involved in pathogen removal. The antibodies produced by B-lymphocytes bind to the pathogen but the antibody does not directly remove the pathogen. Instead, the antibody acts as a chemical tag informing other cells in the immune system that the pathogen is foreign and must be removed from your body. One of the cells of the immune system that is involved in removing the pathogen is called a macrophage and the process by which it removes the pathogen from your body is known as phagocytosis. This process uses the organelle called the lysosome. Lysosomes are sacs that contain digestive enzymes. The process of phagocytosis is shown in Fig. 32 and the steps are outlined below: Firstly the macrophage recognises and binds to the pathogen A vacuole then forms around the pathogen and it is engulfed within the macrophage Lysosomes within the macrophage move towards the engulfed pathogen and fuse with the vacuole surrounding the pathogen Enzymes are released into the vacuole from the lysosomes and the pathogen is digested. © Learning and Teaching Scotland 69 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- © Learning and Teaching Scotland 70 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Infection and Immunity Immunity The action of macrophage is considered to be part of the innate immune response. Innate immunity is a non-specific response to a pathogen. This means that a macrophage will digest any pathogen that it encounters. Other examples of innate immunity include: Skin which acts as a physical barrier against infection Acid in the stomach and in sweat. Pathogens are less likely to grow in these acidic environments Lysozyme which is an enzyme found in tears that kills bacteria Interferon which is a molecule that stops viruses from replicating in your body cells. Naturally acquired immunity When a pathogen enters your body naturally (for example, if you sit beside someone who has chickenpox and is coughing and you breathe in their chickenpox virus) your B-lymphocytes produce antibodies that help you to remove this virus from your body. Unfortunately, this takes about two weeks, so you get the symptoms of chickenpox too! However, remember when the humoral response was discussed previously, a second type of B-lymphocyte was mentioned. This other B-lymphocyte circulates in your blood for many years after you have first had chickenpox and if the chickenpox virus enters your body again, this other type of B-lymphocyte quickly produces many antibodies and the virus is removed before you get the symptoms of chickenpox again. It is because of this natural acquired immunity that someone who has had chickenpox as a child rarely gets chickenpox again. As you get older, your naturally acquired immunity to many pathogens increases. Artificially acquired immunity Immunity can also be acquired artificially by the process of vaccination. In the case of a vaccine, the pathogen (which has been weakened or killed in some way) is injected into a person. This means that the person has been artificially exposed to the pathogen. When the weakened or killed pathogen enters their body, the immune system sets to work. Antibodies are produced which help to remove the pathogen from their body. (Remember that the pathogen has been weakened or killed and so does not cause any symptoms in their body). Also, B-lymphocytes are produced that circulate in the blood and will produce many antibodies quickly if the natural pathogen enters their body at a later date. Thus the person has artificially acquired immunity to the pathogen. © Learning and Teaching Scotland 71 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Infection and Immunity An example of a vaccine is the tetanus vaccine. Tetanus is the uncontrolled contraction of muscles and can cause death in an individual. Tetanus is caused by a toxin produced by a bacterium. The tetanus vaccine is made by purifying the toxin and then inactivating it to produce a toxoid. The toxoid is injected into an individual who then makes antibodies against the toxoid to remove it from their body. The individual also produces B-lymphocytes that circulate in the blood and which will secrete antibodies if the naturally occurring toxin enters their body. The antibodies that are produced are called antitoxins. These antibodies are able to bind to and neutralise the naturally occurring toxin produced by the bacterium. Thus, if the individual is infected by the bacterium that causes tetanus, they can quickly produce antitoxins that prevent the effects of the toxin. Active immunity This refers to the production of antibodies by an individual. The antibodies can be made by the individual in response to a naturally occurring infection or to the artificial injection (vaccination) of a pathogen or toxoid. Passive immunity This refers to an individual receiving ready-made antibodies. These ready-made antibodies can be gained either by natural or by artificial means. Natural passive immunity This refers to someone receiving ready-made antibodies naturally. A baby receives antibodies from its mother through the placenta and through breast milk. Artificial passive immunity This refers to someone receiving ready-made antibodies through a vaccine. For example, if someone cuts themselves badly and if they do not have any natural antitoxins against tetanus in their blood (they may not have kept up to date with their tetanus vaccines), then they can be given ready-made antitoxins in a vaccine that allows them to fight the bacteria that causes tetanus, if it has entered their body through the cut. Generally, natural and artificial passive immunity do not last long as the readymade antibodies are removed from the body within a few months. © Learning and Teaching Scotland 72 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Infection and Immunity Test yourself on infection and immunity Spend time reviewing your notes on infection and immunity, then see if you can answer the questions below. 1. What do the following terms mean? (a) pathogen (b) antigen (c) antibody (d) humoral response (e) cell-mediated response 2. White blood cells (wbc) are involved in the immune response. Some of these wbc are listed below: B-lymphocytes T-lymphocytes macrophage Use the list to complete the following sentences: (a) The wbc involved in humoral immunity is______________________ (b) The wbc involved in regulating the immune response is ______________________ (c) The wbc involved in phagocytosis is __________________________ 3. Put the following statements into the correct order to describe phagocytosis: (a) Digestive enzymes are released from the lysosomes into the vacuole. (b) The pathogen is digested. (c) The phagocyte recognises and binds to the pathogen. (d) Lysosomes within the phagocyte move towards the engulfed pathogen. (e) A vacuole forms around the pathogen and it is engulfed within the phagocyte. (f) Lysosomes fuse with the vacuole surrounding the pathogen. 4. Describe what is meant by the terms ‘active’ and ‘passive’ with reference to immunity. 5. Describe two ways that a person may acquire natural passive immunity. © Learning and Teaching Scotland 73 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- BIBLIOGRAPHY Some suggested staff reading materials The following is a commentary on some published reading materials that may be useful when delivering Higher Biotechnology. This list is in no way exhaustive and is meant only as a starting point for any tutor delivering the units for Higher Biotechnology for the first time. Foundations in Microbiology (3rd edition) by Kathleen Park Talaro and Arthur Talaro Published by WCB/McGraw-Hill ISBN: 0-697-35452-0 This is a general introductory microbiology book that is a good teacher’s resource, especially if you do not have a microbiology background. The book is aimed at undergraduates, so it is too detailed and advanced to be used as a student resource. But it is easy to read and has lots of good illustrations and diagrams. There is an interactive CD-ROM that can be purchased to accompany the book. It provides lots of detailed background knowledge on many of the topics in all of the three units that comprise Higher Biotechnology. Fundamentals of Microbiology (5th edition) by I Edward Alcamo Published by Benjamin/Cummings Publishing Company ISBN: 0-8053-0532-7 This is another general microbiology book that is a good teacher’s resource. Again, it is easy to read with lots of diagrams and anecdotes (although they are all American). This book is a good source of graphs that could be the basis for problem-solving questions. It also provides lots of detailed background information for all three units of Higher Biotechnology. Micro-organisms and Biotechnology (1st and 2nd editions) by Jane Taylor Published by Nelson Thornes ISBN: 0-17-448255-8 (second edition) This book is now into its second edition and may be used as a teacher and student resource. Both the first and second edition provide background knowledge for all three units comprising Higher Biotechnology and the book is especially good for the enumerating micro-organisms section in Unit 2 (Microbiological Techniques). The second edition also covers some ethical issues surrounding some biotechnology processes. Basic Biotechnology (2nd edition) Edited by Colin Ratledge and Bjorn Kristiansen Published by Cambridge University Press ISBN: 0-521-77917-0 This is a book for teachers who are enthusiasts and want to have a detailed knowledge of biotechnology. It provides all the background knowledge (and more!) required for delivering Unit 3 (Biotechnology). © Learning and Teaching Scotland 74 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- Bibliography Some suggested websites www.Biotechinstitute.org This is an American website that has lots of biotechnology information. It has links to biotechnology-related news stories from a range of sources e.g. ‘Nature’, Yahoo and the BBC. There are teachers’ resources and links to other websites. Also, you can download back copies of the magazine Your World; this is aimed at post-16 students. Each issue covers one particular biotechnology topic and so can be used as a classroom resource. www.biowise.org.uk This website provides downloadable case studies on industrial biotechnology that may be useful for Unit 3 (Biotechnology). The case studies highlight companies in the UK that actively use biotechnology; so they are a good introduction to students to show the practical relevance of what they are studying. www.sgm.ac.uk This is the Society for General Microbiology website which has links to current ‘hot’ topics and news items, so it is a good way of keeping up to date with issues in microbiology. It also has educational resources and links to online microbiology resources. www.ncbe.reading.ac.uk This website provides downloadable protocols for practical exercises, as well as online learning materials. It has a good section on safety issues to be taken into consideration when carrying out biotechnology practical exercises. It also provides information about the Scottish Centre for Biotechnology Education. http://www-saps.plantsci.cam.ac.uk This website has protocol information, details on how to purchase kits that can be used as learning activities, and details of biotechnology workshops for teachers and the annual biotechnology summer school. www.scottishbiotech.org This is the website of the Scottish Colleges Biotechnology Consortium who deliver technical training to industry and schools. Online courses are available. www.sserc.org.uk This website provides information about the Scottish Institute of Biotechnology Education (SIBE) who run workshops for teachers and pupils. www.sebiotech.org.uk This is the website of Scottish Enterprise that is dedicated to the Scottish biotechnology industry. It is very useful for keeping up to date with the biotechnology companies in Scotland. © Learning and Teaching Scotland 75 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------- APPENDIX Advice For Problem-Solving Outcomes Advice for problem-solving outcomes Unit 1: Microbiology, Outcome 3 and Unit 3: Biotechnology, Outcome 2 Candidates are required to produce one report on a problem-solving activity as part of the evidence for the achievement of Higher Biotechnology. The report can be used as evidence for Outcome 3 to achieve the unit ‘Microbiology’ and for Outcome 2 in the unit ‘Biotechnology’. The report must be the individual work of the candidate. One way that a problem can be solved is to carry out a practical investigation, either as an individual or as part of a group. This enables candidates to fulfil the required performance criteria (PC): (a) The problem to be solved is identified. (b) Resources required to solve the problem are identified and obtained. (c) Procedures appropriate to solving the problem are planned and designed. (d) The planned procedures are carried out. (e) The problem-solving procedure is evaluated. Alternatively, candidates can undertake a paper-based investigation by identifying a particular problem, obtaining data from other sources (for example biotechnology journals or the internet), then analysing, presenting and evaluating this data. Whichever method is used to solve the problem, it is essential to ensure that candidates produce sufficient evidence to fulfil all the required performance criteria. Suggestions to aid professional judgement in ensuring that performance criteria are covered are given in the support notes of both unit specifications. © Learning and Teaching Scotland 76 Biotechnology Higher Unit 1: Microbiology Student Materials ----------------------------------------------------------------------------------------------------Advice for Problem-Solving Outcomes A case study of practical investigation that was used to solve problems by candidates in a presenting centre is describe below: Title ‘Immobilisation of enzymes’ Introduction As a learning activity to demonstrate immobilisation, candidates entrapped yeast invertase within alginate beads, then assayed the immobilised enzyme by quantitatively measuring product formed using a standard curve. (Many experiments used as learning activities can form the basis of problem-solving exercises.) The problem Following this activity, several candidates started to identify potential problems associated with immobilisation. Some wanted to know if immobilisation changed the pH and temperature optima of the enzyme; others wanted to know how often the immobilised enzyme could be used before it stopped making product. Both groups realised that these problems may be genuine in the biotechnology industry if an enzyme is to be immobilised for commercial purposes. (Note that these problems have a real practical application that can help in the evaluation of the exercise.) The procedure These candidates used the knowledge and practical skills they had previously gained from immobilising enzymes to identify the resources and to plan and design their problem-solving activities. The evaluation The candidates found out that the pH optimum changed, the temperature optimum stayed the same and the immobilised enzyme could be used three times before the quantity of product decreased. Other learning activities that can be used as the basis of problem-solving activities are given in the support notes of each unit specification. They are as outlined below: Set up a small-scale laboratory fermenter and monitor and control various conditions such as pH and temperature Autolyse yeast and test viability at different stages in a downstream process Investigate the effect of pectinase, amylase, cellulose and RGase on the production and clarity of fruit juice Investigate the action of cellulase on cellulose Investigate methods of removing immobilised enzyme beads from the substrate Analyse data on DNA profiling. © Learning and Teaching Scotland 77