Chapter 15 answer keys packet
Page 1 notes
Page 2 notes
Page 3 WS Intro to Solutions
1. solute-smaller portion solvent-larger portion
2. 5 mL alcohol in 95 mL water solvent
5mL water solute in 95 mL solvent
3. increase temp causes increase in solubility of solid
increase temp cause increase in KE to break crystal lattice and make part of
solution
4. saturated solution can’t hold any more solute at the given temperature.
Unsaturated can hold more
5. 1. make a saturated solution. 2. increase heat 3. add more solute 4. allow to
cool undisturbed
6. solubility-amount of solute that can be held in a set amount of solvent at a certain
temperature g solute/100 g of water at a certain temp
7. one of the particles on the bottom dissolves and one of the particles that is
dissolved sinks back down
8. salvation is the chemical reaction between a solute and a solvent and causes
dissociation and a solution to be formed.
9. unlimited ability to mix with one another.
10. try to dissolve more solute. If all you add settles to the bottom, it was saturated.
11. Try to add more solute. If any that you add dissolves, it was unsaturated.
12. Try to add more solute. If more than you added drops to the bottom, it is
supersaturated.
13. CaCl2 (s) ---- Ca+2 (aq) + 2 Cl- (aq)
SnF2 (s) ---- Sn+2 (aq) + 2 F- (aq)_
Al2 S3 (s) ---- 2Al+3 (aq) + 3 S-2 (aq)_
Page 4 Continued
14. homo, homo, hetero, homo, hetero, hetero, homo, homo, hetero, hetero, hetero,
homo, homo, homo
15. solute=sugar solvent tea
solute= silver solvent= gold
solute= zinc, tin, copper solvent=iron
solute=oxygen, argon, carbon dioxide
solvent=nitrogen
solute= chocolate syrup solvent = milk
solute= coke syrup and carbon dioxide solvent= water
Page 5
WS Solubility Curves 1
1. 54-55 degrees Celcius
2. NH3 and Ce2(SO4)3
3. KNO3 steepest slope
4. NaCl least steep slope
5. 130 g
6. at 70 = 130 g at 50 = 80 g 130 - 80 = 50 g
7. at 50 = 49 g at 70 = 59 g 59 - 49 = 10 g
8. KI
9. Ce2(SO4)3
10. at 90 = 70 g 70g/100g water = x/1000g water
x = 700 g
11. at 40 = 104 g 104g/100g water = x/250g water
x = 260 g
12. supersaturated at 50, it should hold 80 g. since it is holding 100 g, it is holding
excess. It is supersaturated.
Page 6 Graph Potassium Nitrate
1.
2.
3.
4.
5.
6.
7.
decrease
65 g to 69 g
171 g
supersaturated
supersaturated
27 to 30g
5g
Page 7
Graph Lab Solubility of Solutes
1.
2.
3.
4.
5.
20 degrees celcius
135 g
supersaturated 117g -88g = 29g
45 g KCl/x g KCl = 100 g water/250 g water
Li2CO3
Page 8 and 9 notes
Page 10 notes
Page 11
Notes
Page 12
Molarity Ws
1. 13.1 g
2. .337 M
3. .128 L
4. .400 moles
5. 3.89 M
6. 342 g/mol
= 112.5 g KCl
7. 4.52 x 1023 molecules
8. 4.29 M
Page 13 WS Molarity and Molality -1
1. 100. mol NaCl
2. 2100 g NaCl
3. 100. mol CaCl2
_
4. 4000 g CaCl2
5. .115 m
6. .3333 m
7. .07000m
8. .4667 m
Page 14 Continued
9. 8.07 x 1025 FU
10. 1.23 x 1026 FU
11. .225 M
12. .01540 M
13. .169 m
14. 6.67 x 10-4 m
15. 3.23 g
16. 1.86 m
17. 1.41 M
Page 15 notes
Page 16
WS Net Ionic Equations 1
1. a.
3CuSO4 (aq) + 2FeCl3(aq) ---- 3CuCl2(aq) + Fe2(SO4)3 (aq)
b. 3Cu+2(aq) + 3SO4-2(aq) + 2Fe+3(aq) +6Cl-1(aq) ---- 3Cu+2(aq) + 6Cl-1(aq) +
2Fe+3(aq) + 3SO4-2(aq)
c. NR
2. a.
FeSO4 (aq) + (NH4 )2S(aq) ---- FeS(S) + (NH4)SO4 (aq)
b. Fe+2(aq) + SO4-2(aq) + 2 NH4+(aq) + S-2(aq) ---- FeS(S) + 2 NH4+(aq) +
SO4-2(aq)
c. Fe+2(aq) + S-2(aq) ---- FeS(S)
3. a.
K2CO3 (aq) + Sr (NO3)2(aq) ---- 2KNO3(aq) + SrCO3 (s)
+
b. 2K (aq) + CO3-2(aq) + Sr+2(aq) + 2NO3-1(aq) ---- 2K+(aq) + 2NO3-1(aq) +
SrCO3(s)
c. CO3-2(aq) + Sr+2(aq) ---- SrCO3(s)
4. a.
NaI (aq) + AgNO3(aq) ---- AgI(s) + NaNO3 (aq)
b. Na+(aq) + I-1(aq) + Ag+1(aq) + NO3-1(aq)
----- 2AgI(s) + Na+1(aq) +
-1
NO3 (aq)
c. Ag+1(aq) + I-1(aq) ---- AgI(s)
5. a.
Al2 (SO4)3 (aq) + 3CaCl2 (aq) ---- 2AlCl3 (aq) + 3CaSO4 (s)
+3
b. 2Al (aq) + 3SO4-2(aq) + 3Ca+2(aq) + 6Cl-1(aq) ---- 2Al+3(aq) + 6Cl-1(aq) +
3CaSO4 (s)
c. 3SO4-2(aq) + 3Ca+2(aq) ---- 3CaSO4 (s)
page 17 chart
page 18 notes
page 19 notes
page 20 WS Boiling Point Elevation and Freezing Point Depression -1
1. -1.86 0C
2. -1.86 0C
3. -1.86 0C
4. 100.13 0C
5. 100.39 0C
page 21WS Boiling Point Elevation and Freezing Point Depression -1 continued
6. 100.71 0C
7. -3.65 0C
8. 1.9 moles
9. .897 mol
10. 72.1 g
Page 22 WS Colligative Properties
1. 100.575 0C
2. 101.323 0C
3. -7.19 0C
4. 101.10 0C
5. -3.94 0C
6. -3.72 0C
7. 75.22 g/mol
Page 23 Colligative properties of solutions
1. 2000g
2. 625 g
3. .00666 m
4. -.545 0C
5. -.465 0C
6. .23 m
7. .215 m
8. 172 g