Computer Output WS ANS

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Computer Data for Linear Regression Answers

AP Statistics

1. The decline of salmon fisheries along the Columbia River in Oregon has caused great concern among commercial and recreational fishermen. The paper “Feeding of Predaceous Fishes on Our-Migrating Juvenile

Salmonids in the John Day Reservoir, Columbia River” (Trans. Amer. Fisheries Soc. (1991): 405-420) gave the accompanying data on y = maximum size of salmonids consumed by northern squaw fish (the most abundant salmonid predator) and x = squawfish length, both in mm. Use the computer output to answer the questions.

LSRL: size = -89.09 + .73 length r = s = t =

.981

12.56

s r 2 = .963

b

= .04778

15.26

df = 9

Predictor

Constant

Length s = 12.56 R-sq = 96.3%

Analysis of Variance

Source

Coef

-89.09

0.72907

Regression

Error

Total

DF

1

9

10

Stdev

16.83

0.04778 t-ratio

-5.29

15.26

R-sq(adj) = 95.9%

SS MS F p

36736 36736 232.87 0.000

1420 158

38156 p

0.000

0.000 p-value = .000

Calculate a 95% confidence interval for the slope of the true regression line: (-.62, .84)

What is the maximum size for salmonids consumed by a squawfish whose length is 375 mm, and what is the residual corresponding to the observation (375,165)?

184.295 mm, -19.295

2) Below is the computer output for the appraised value (in thousands of dollars) and number of rooms for houses in East Meadow, New York. Answer the following questions.

LSRL: r = s = value = 74.8 + 19.718 rooms

.661

29.05

r 2 = s b

=

.438

2.631

Predictor

Constant rooms s = 29.05

Coef

74.80

19.718

R-sq = 43.8%

Stdev

19.04

2.631

R-sq(adj) = 43.0% t-ratio

3.93

7.49 t = 7.49

p-value = 0.000

Interpret the slope. df = 72

Analysis of Variance

Source DF

Regression

Error

Total

1

72

73

SS

47398

60775

108173

MS

47398

844

There is an approximate increase of $19,718 in appraised value for an increase in one room.

Interpret the coefficient of determination.

Approximately 43.8% of the variation in appraised value is explained by the LSRL.

Predict the appraised value of a house with 13 rooms. $330,900

3) The manager of a chain of package delivery stores would like to predict the weekly sales (in $1000) for individual stores based on the number of customers. Find or calculate the related values for a two-sided test about the slope 

LSRL: r = s = t = sales = 2.423 + .0087 rooms

.9549

0.5015

13.64 r 2 = s b

= df =

.912

.0006397

18

Predictor

Constant

Customer

Coef

2.4230

0.0087293 s = 0.5015

Analysis of Variance

Source

Regression

DF

1

Error

Total

18

19

SS

Stdev

0.4810

0.0006397

R-sq = 91.2% t-ratio

R-sq(adj) = 90.7% p

46.834 46.834 186.22 0.000

4.527 0.251

51.360

MS F p-value = 0.000

90% confidence interval = (.00759, .00981)

4) A real estate agent would like to predict the selling price of a single-family house by predicting the price (in

$1000) based on the square footage (in 100 ft 2 ). Find or calculate the following answers.

LSRL: price = 18.35 + 3.87 footage r = s = t =

.805

12.9965

4.887

r 2 = s b

= df =

.648

.7936

13

Predictor

Constant

Customer

Regression

Error

Total

Coef

18.3538

3.8785 s = 12.9965

Analysis of Variance

Source DF

1

13

14

Stdev

14.8077

0.7936

R-sq = 64.8%

SS

4034.4144

2195.8215

6230.2360 t-ratio

R-sq(adj) = 62.0%

MS

4034.4144

168.9093

F

23.885 p-value = .0003

Interpret the slope & correlation coefficient.

S: For an increase of 100 square feet, there is an approximate increase of $3870 in the price of a house.

R: There is a strong, positive, linear association between square footage & price of a house.

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