Title: BOD:COD Ratio of Natural and Synthetic Chemicals Aims: To show the necessity of making dilutions for samples of unknown BOD.. To show that organic chemicals can exert a BOD and also have bactericidal and toxic effects at high concentrations. To calculate the BOD:COD ratio of various samples. Introduction: BOD determination is an empirical test in which standardised laboratory procedures are used to determine the relative oxygen requirements of wastewater effluents and polluted waters. The test measures the oxygen required for the biochemical degradation of organic material. It may also measure the oxygen used to oxidise reduced forms of nitrogen unless an inhibitor prevents their oxidation. The BOD was originally developed to stimulate conditions that occurred following the discharge of an organic effluent into a river. The test now has wider applications and in this practical the BOD’s of various organic chemicals will be determined Organic chemicals when in concentrated form can exert a considerable oxygen demand. For this reason dilutions of the samples need to be carried out. If no dilution of the samples took place then all the dissolved oxygen could be used up during the five day incubation period. The samples can be diluted in standard dilution water. This dilution water contains essential nutrients for microbial activity which are necessary for the breakdown of the sample. It is necessary to have a population of microorganisms present in the sample that are capable of oxidising the biodegradable matter present. Adding a population of microorganisms to the dilution water can seed samples that do not contain a sufficient microbial population. The seed to be used in this practical will be obtained from a local sewage treatment plant. In this practical the BOD of coke will be determined. The expected BOD of coke lies between 60,000 - 90,000. The sample will need to be diluted before incubation. A COD determination will also be carried out on the coke sample. The COD test measures the oxygen equivalent of that portion of the organic matter in a sample that is susceptible to oxidation by a strong chemical oxidant. The COD test is linked to the BOD test, but its major advantage is that it gives more rapid results. Because nearly all organics are oxidised in the COD test and only some are decomposed during the BOD test, COD values are usually greater than BOD values Materials: Winkler bottles, glass stoppered Various pipetts Volumetrics,4 Dissolved Oxygen meter Dilution water Seed material Method: Dilution water preparation - as per manual Seeding of dilution water - as per manual Sample dilution and preparation estimated BOD of coke sample 60,000 - 90,000 sample must be diluted to give BOD of between 2 - 8 mg/l D.O therefore dilutions carried out 1/100 1/10.000 RESULTS: 1/20.000 BOD RESULTS: Sample used - coke Dilution DO o DO 5 Difference BOD 5 mg/l d.o Blank 8.7 7.9 0.8 0.8 1/100 8.9 0.0 8.9 0.0 1/10.000 8.9 2.4 6.5 57,000 1/20.000 8.8 4.3 4.5 74,000 Calculation: BOD = (DO.o - DO. 5 sample) - (DO.o - DO. 5 blank) * Dilution factor BOD = (8.8 - 4.5) (8.7 - 7.9) * 20,000 = 74,000 Average BOD = 65,000 mg/l COD RESULTS: Dilutions COD mg/l 1/250 118,000 1/500 124,000 1/1000 117,000 Average COD = 119,667 mg/l BOD:COD Ratio = 1:1.82 CLASS RESULTS: BODS, BLANKS & EXPECTED RANGES SAMPLE BOD mg/l D.O BLANK BOD mg/l RANGES MILK 116,000 0.8 40,000 - 120,000 PLAX 897,000 --- >600,000 COKE -------- 5.3 60,000 - 90,000 PLAX 170,000 2.7 >600,000 ANTIFREEZE 220,000 0.0 0.5 - 2,000,000 COKE --------- 1.8 60,000 - 90,000 ETHANOL --------- 1.2 0.6 - 1,500,000 ETHANOL 1,600,000 1.8 0.6 - 1,500,000 TOOTHPASTE 51,000 1.2 10,000 - 100,000 ANTIFREEZE --------- 2.0 0.5 - 2,000,000 FORMALDEHYD 255,000 3.3 1.5 - 2,000,000 38,000 2.7 60,000 - 90,000 E COKE CLASS RESULTS FOR BOD:COD RATIO SAMPLE BOD COD BOD:COD RATIO Coke 65,000 119,667 1:1.82 Milk 116,000 212,250 1:1.83 Plax 1,500,000 295,000 ------- Coke --------- 973,333 ------- Plax 170,000 340,000 1:2 Antifreeze 1,340,000 1,132,500 1:.84 Coke ---------- 101,250 ------ Ethanol ---------- --------- ------ Milk 71,500 151,000 1:2.11 Coke 54,000 112,000 1:2.07 Ethanol 1,600,000 2,240,000 1:1.4 Toothpaste 51,000 18,750 1:.36 Antifreeze -------- 216,000 ------ Formaldehyde 255,000 579,200 1:2.27 Discussion: In this practical the BOD of a coke sample was determined. It was thought that the BOD of the coke sample was somewhere between 60,000 to 90,000 mg/l. Therefore before incubation dilutions needed to be carried out on the sample. The coke sample was diluted sufficiently so as to have a BOD of between 2 - 8 mg/l dissolved oxygen. Three different dilutions of the coke sample were carried out, a 1/100, 1/10,000 and a 1/20,000. The samples were diluted in seeded standard dilution water and the initial dissolved oxygen levels of each were recorded. The samples were then incubated at 20 c for five days. A blank comprising of the seed and the dilution water was also incubated under the same conditions as the samples. After the incubation period the dissolved oxygen levels of the samples and the blank were measured. The average BOD for the coke sample was determined to be 65,000 mg/l D.O. The blank had a D.O uptake of 0.8 mg/l which would indicate that the dilution water did not exert an excessive oxygen demand during the incubation period. It would also indicate that the correct amount of seed was added to the dilution water. All of the dissolved oxygen was used up in the 1/100 diluted sample because the dilution was too small. The small dilution resulted in too much organic matter being present in the sample for the microoganisms to break down aerobically. The 1/10,00 and the 1/20,000 dilutions did give a BOD and they also fulfilled the criteria necessary when conducting a BOD test using seeded dilution water which states that at least 2 mg/l of D.O must be used up and there must be at least 1 mg/l D.O remaining after incubation A COD determination of the coke sample was also carried out. Dilutions of the sample also needed to be carried out for this test. High range Hack tubes which measure up to 1500 mg/l were used. The dilutions used were 1/250, 1/500 and 1/1000. The viles were allowed to reflux for two hours and after cooling thier absorbance was measured using a Hack meter. The COD readings were multiplied by their dilution factor and the average COD of the coke sample was found to be 119,667 mg/l. When this value is compared to the BOD for coke a ratio of 1:1.82 is found. The COD value is greater than that of the BOD because the oxygen in the COD sample is subjected to more severe oxidising conditions. In the class results some interesting points can be noted. Firstly the oxygen uptake in the blanks ranged from 0.8 mg/l O2 to 5.3 mg/l O2. When seeded dilution water is used, as was the case in this practical the oxygen uptake should be between 0.6 - 1.0 mg/l O2. The high oxygen uptake in some of the blanks might be indicating that there was organic matter present in the dilution water which exerted an excessive oxygen demand. It may also be a sign that there was dirty or contaminated glassware used. However because of the wide variation in the results for the blanks it is more likely that too much seed was added by some of the groups. If the seed concentration is too high, it can exert a significant oxygen demand. One of the groups had no oxygen uptake in their blank. This result is very unlikely and it is possible that no seed was added to the dilution water. A coke sample was analysed by four groups. The expected BOD for coke is between 60,000- 90,000. Although the BOD of the sample worked well for group one, (65,000) two of the other groups were unable to get a BOD, while the fourth group got a BOD of 38,000 (average). None of these three groups fulfilled the criteria for BOD analysis, i.e 2 mg/l used up and 1 mg/l remaining. In one of the groups a 1/60,000 dilution of the coke sample was carried out but still all the oxygen was used up during incubation. For this to be the case the BOD of the coke sample would need to be in excess of 250,000 mg/l. This is not correct, it is likely a mistake was made when making up the dilutions. For the COD an average value of 119,667 mg/l was found. Two of the other groups had CODs in this range but one group had a COD of 973,333 mg/l. Once again this result is too high. Two plax samples were also examined. The BODs of the two groups varied, one got a BOD of 170,000 mg/l (average), while the other got 879,000 mg/l (average). The anticipated BOD of plax was greater than 600,000, so from these results it would appear that the results of the second group are more accurate. The second group got a COD of 295,000 mg/l which was far lower than their reported BOD of 1,500,000 mg/l. This group didn’t average their BOD results so this is why the result is greater than the one stated above (879,000). The first group got a COD of 340,000, which gave a BOD:COD ratio of 1:2. Two groups tested an ethanol sample. The BOD range for ethanol was expected to be between 600,000 - 1,500,000. One of the groups did not get any BOD or COD result, while the other group got a BOD of 1,600,000, and a COD of 2,240,000. This gave a BOD:COD ratio of 1:1.4. Two groups also examined a milk sample and their results were very similar. One group examined a toothpaste sample. They got a BOD of 51,000 mg/l (average), and their COD result was18,750 mg/l. This gave a BOD:COD ratio of 1:.36. The expected BOD for formaldehyde was 1,500,000 - 2,000,00 mg/l. The group that analysed formaldehyde got a BOD of 255,000 mg/l. This result would appear to be out by a factor of ten. There was probably an error in the dilutions to blame for this. The COD for formaldehyde was found to be 579,000 mg/l. This result gave a BOD:COD ratio of 1:2.27. Two ethanol samples were also examined. One group failed to get a BOD or a COD. This may be because the initial D.O of the samples before incubation was low, about 7.5 mg/l. The second group did get a BOD and a COD result. The initial D.O of the samples was higher, about 8.7 mg/l, so this probably helped to get a BOD. The BOD:COD ratio was found to be 1:1.4. From an examination of the class results it can be seen that there was no toxic or bactericidal effects shown in the samples. This is probably because the dilutions used were too great to show any effects. For example it known that ethanol in high concentrations is bactericidal, but in the practical the lowest dilution used was a 1/10,000. This dilution was not low enough to show the bactericidal effect. From the results it can also be seen that reproducibility of BODs is very difficult. Some of the results were misreported. Some groups did not average their BOD and COD results before they calculated their BOD:COD ratios. This may have been a deliberate attempt to obtain a BOD:COD ratio in the region of 1:2. Some groups were under the impression that their ratio should have been 1:2, whereas in reality this ratio applies to sewage Conclusion: In this practical it was shown that it is necessary to make dilutions of some samples when determining BOD. It was also shown that many chemicals are biodegradable and can exert a high BOD. It can also be seen that reproducibility of BOD results is difficult. BOD:COD ratios were also determined for most of the samples.