Questions for home study and tutorial discussion: (1) How does the nature of the leaving-group affect SN2 reactions? (2) How does the nature of the solvent affect SN2 reactions? (3) How does the nature of the leaving-group affect SN1 reactions? (4) How does the nature of the solvent affect SN1 reactions? Revising SN2 Substitution Reactions: As the nucleophile approaches the reaction centre its own excess H Nu-: C Ph X sp3 CH3 sp2 H Nu X C Ph CH3 sp3 H Nu C Ph CH3 + X- electron density repels the electrons in the bonds at the central carbon forcing them back in the direction of the departing leaving group. In the transition state the hybridisation at carbon has now changed from tetrahedral sp3 to planar sp2 with both the nucleophile and the leaving group sharing an unhybridised p orbital. As the nucleophile moves even closer to the reaction centre - and the leaving group simultaneously moves off - the sp2 transition state collapses to sp3 again in the direction of the departing leaving group so that the substitution product forms with inverted configuration at carbon. Rate = k x [RX] x [Nucleophile] SN2 substitutions are inhibited by steric crowding at the reacting carbon Reactivity CH3X > 1° RX >> 2° RX >>> 3° RX (1) How does the nature of the leaving-group affect SN2 reactions? H C6 H 5 C Br + Nu- CH3 H Desirable ? Not Desirable CH3 C Nu + Br- C6H5 For an SN2 reaction to give the maximum yield of product the leaving group should be a much poorer nucleophile than the incoming (i.e. attacking) nucleophile - otherwise the substitution reaction would tend to go backwards leading to an equilibrium between starting material and substitution product. Good nucleophiles are usually also strong bases, hence poor nucleophiles are usually weak bases. Therefore good leaving groups (i.e. poor nucleophiles) will usually be weak bases i.e. the anions of strong acids. Conversely poor leaving groups (i.e. good nucleophiles) will usually be strong bases i.e. the anions of weak acids: HOH N- Cl- Br- I- TsO- 1 x 104 3 x 104 6 x 104 2 CH3O<< 1 Poor 2 x 102 Good Reactivity as leaving group Anion of strong acid = Good leaving group Acidity: H2O > HCl > HBr > HI > TsOH Leaving group ability: OH– < Cl– < Br– < I– < TsO– TsO- = p-toluenesulphonate = tosylate anion = O S CH3 - O O O CH3 S OH toluenesulphonic = tosic acid O Ts = toluenesulphonyl = tosyl (2) How does the nature of the solvent affect SN2 reactions? The nucleophile in an SN2 reaction is very commonly the anion of an ionic reactant - e.g. CN- from NaCN or OH- from KOH. Ionic compounds are insoluble in non-polar solvents such as alkanes, ethers or benzene. These solvents are not suitable for SN2 reactions which are usually carried out in polar solvents which dissolve the ionic reactant. The effect of solvent on an SN2 reaction depends on whether the solvent is a protic polar solvent or an aprotic polar solvent. Protic polar solvents - solvents having protons attached to electronegative atoms like oxygen or nitrogen, e.g. water, alcohols or amines - inhibit SN2 reactions of ionic nucleophiles: - OR + H RO H Nu H Solvation of an anionic H OR nucleophile by hydrogen bonding with a protic solvent. OR The nucleophile is stabilised - i.e. made less reactive - by solvation. The attached solvent molecules also make it more difficult for the nucleophile to approach the electrophile and this also inhibits SN2 reactivity. In contrast aprotic polar solvents - polar solvents without OH or NH groups - increase the reactivity of ionic nucleophiles and enhance the SN2 reaction. Among such solvents are: Acetonitrile, Me-CN: O N,N-Dimethylformamide (DMF), Me2 NCHO, H C NMe2 and - Dimethylsulphoxide (DMSO), Me2SO, Me2S O These solvents enhance SN2 reactions. Firstly the lack of acidic protons means no unhelpful solvation of the nucleophile. Secondly, the electron rich nitrogen (MeCN) or oxygen (HCONMe2 or Me2SO) atoms solvate the cation of ionic nucleophiles. As a result anion-cation interactions are removed and the reactivity of the anion is increased. M + Nu- Cation/nucleophile ion pair S S + S M Nu S S S Cation solvated by aprotic solvent with more reactive 'bare' anionic nucleophile Revising SN1 Substitution Reactions: H + Slow C Ph H Br C RDS CH3 Ph + Br - CH3 Planar sp2 hybridised CARBOCATION (R)-1-Bromo-1phenylethane N H Ph C _ _ C H + CN CH3 (R)-1-Cyano-1phenylethane C C Ph N H NC C CH3 RACEMISATION 50% CH3 (S)-1-Cyano-1phenylethane 50% Rate = k x [RX] Ph (3) How does the nature of the leaving-group affect SN1 reactions? Slow (CH3 )3C X Rate-determining step. + (CH3)3 C + X Rapid Nu- (CH3 )3C CARBOCATION intermediate Nu As the departure of the leaving group is involved in the RDS of SN1 substitution then the reaction will be enhanced by good leaving groups and inhibited by poor leaving groups. As with SN2 reactions: Good leaving groups (i.e. poor nucleophiles) will be weak bases i.e. the anions of strong acids. Poor leaving groups (i.e. good nucleophiles) will be strong bases i.e. the anions of weak acids. See Question (1) above for more details and some examples of good and poor - leaving groups. (4) How does the nature of the solvent affect SN1 reactions? Slow (CH3 )3C + (CH3)3 C + X X Rate-determining step. Rapid Nu- (CH3 )3C CARBOCATION intermediate Nu Since the RDS of the SN1 reactions produces two ions a solvent which can stabilise those ions will facilitate the reaction. Polar solvents - both protic and aprotic can do this - the negative end of the solvent dipole solvating and stabilising the carbocation (the most important effect) and the positive end doing the same for the anionic leaving-group: + H : O + + + X + + + + + + R + : H Comparison of SN1 and SN2 substitution reactions: Variable Substrate structure: Methyl or 1° Secondary Tertiary Stereochemistry Nucleophile Leaving group Solvent SN1 SN2 Does not occur except for 1° allyl and 1° benzyl - methyl or 1° carbocations are insufficiently stable. Yes - but mainly for allylic and benzylic systems Common - minimal steric hindrance to the rearward approach of nucleophile Yes - unless substrate is very sterically crowded. Common - highly stabilised tertiary carbocations Does not occur - too much steric hindrance to rearward approach by nucleophile Racemisation Inversion Rate independent of Rate dependent on concentration and concentration and nature of the nucleo- nature of the nucleophile since the latter is phile since the latter not involved in the is involved in the RDS. RDS- anionic nucleophiles especially favour SN2 Reaction favoured by As for SN1 reaction good leaving groups anions of strong acids Favoured by polar Favoured by aprotic solvents and inhibited polar solvents, by non-polar solvents. inhibited by protic polar solvents.