Section 5.3 Class Exercises Math 400 – Actuarial Models NAME:_____________________________ 1. Let T0 be a lifetime random variable having a uniform distribution on the interval from 0 to . (a) Find a formula for each of the following: S0(t) = f0(t) = 0(t) = t = E(T0) = 1 Section 5.3 Class Exercises 1.-continued (b) For a given value x, let Tx be the remaining lifetime random variable given that T0 = x. Find a formula for each of the following: t px = t qx = fx (t) = x (t) = x + t = E(Tx) = 2 Section 5.3 Class Exercises 2. Let T0 be a lifetime random variable with survival function S0(t) = 1 (t / )k for 0 t where k is a positive constant. (a) Find a formula for each of the following: F0(t) = f0(t) = 0(t) = t = E(T0) = 3 Section 5.3 Class Exercises 2.-continued (b) For a given value x, let Tx be the remaining lifetime random variable given that T0 = x. Find a formula for each of the following: t px = t qx = fx (t) = x (t) = x + t = E(Tx) = 4 Section 5.3 Class Exercises 3. Let T0 be a lifetime random variable with survival function S0(t) = (1 t / )k for 0 t where k is a positive constant. (a) Find a formula for each of the following: F0(t) = f0(t) = 0(t) = t = E(T0) = 5 Section 5.3 Class Exercises 3.-continued (b) For a given value x, let Tx be the remaining lifetime random variable given that T0 = x. Find a formula for each of the following: t px = t qx = fx (t) = x (t) = x + t = E(Tx) = 6 Section 5.3 Class Exercises 4. Let T0 be a lifetime random variable having an exponential distribution with mean . (a) Find a formula for each of the following: F0(t) = S0(t) = f0(t) = 0(t) = t = E(T0) = 7 Section 5.3 Class Exercises 4.-continued (b) For a given value x, let Tx be the remaining lifetime random variable given that T0 = x. Find a formula for each of the following: t px = t qx = fx (t) = x (t) = x + t = E(Tx) = 8 Section 5.3 Class Exercises 5. Let T0 be a lifetime random variable with survival function S0(t) = 1 / (1 + t)k for 0 t where > 0 and k > 1 are constants. (a) Find a formula for each of the following: F0(t) = f0(t) = 0(t) = t = E(T0) = 9 Section 5.3 Class Exercises 5.-continued (b) For a given value x, let Tx be the remaining lifetime random variable given that T0 = x. Find a formula for each of the following: t px = t qx = fx (t) = x (t) = x + t = E(Tx) = 10 Section 5.3 Class Exercises 6. Let T0 be a lifetime random variable having a uniform distribution on the interval from 0 to (i.e., the same distribution as in #1). Suppose = 80. (a) Find the p.d.f. for K0 and the p.d.f. for K0* . (b) Find the mean and variance for each of K0 and K0* . (c) Find the p.d.f. for K30 and the p.d.f. for K30* . (d) Find the mean and variance for each of K30 and K30* . 11 Section 5.3 Class Exercises 6.-continued (e) Let x be an integer such that 0 < x < 80. Find the p.d.f. for Kx, the p.d.f. for Kx* , the mean and variance for Kx, and the mean and variance for Kx* . (f) Let be an integer greater than 1, and let x be an integer such that 0 < x < . Find the p.d.f. for Kx , the p.d.f. for Kx* , the mean and variance for Kx , and the mean and variance for Kx* . 12 Section 5.3 Class Exercises 7. Let T0 be a lifetime random variable with survival function S0(t) = 1 (t / ) for 0 t where is an integer greater than 1, and is a positive constant (i.e., part of the family of distributions in #2). (a) Suppose = 6 and = 2. In the table below, complete the column which defines the p.d.f. for K0 and the column which defines the p.d.f. for K0* . Then, find E[K0] and E[K0*]. Possible Possible Values Values for K0 for K0* Probability ____________________________________________________ 0 1 13 Section 5.3 Class Exercises 7.-continued (b) Suppose = 6 and = 2. In the table below, complete the column which defines the p.d.f. for K2 and the column which defines the p.d.f. for K2* . Then, find E[K2] and E[K2*]. Possible Possible Values Values for K2 for K2* Probability ____________________________________________________ 0 1 14 Section 5.3 Class Exercises 7.-continued (c) Suppose = 6, = 2, and x is an integer such that 0 < x < 6. In the table below, complete the column which defines the p.d.f. for Kx and the column which defines the p.d.f. for Kx* . Then, find E[Kx] and E[Kx*]. Possible Possible Values Values for Kx for Kx* Probability ____________________________________________________ 0 1 . . . k1 k . . . E[Kx] = 6 x (k 1) k 1 6 x k k 1 S 0 ( x k 1) S 0 ( x k ) = S 0 ( x) S 0 ( x k 1) S 0 ( x k ) S 0 ( x) 6 x k 1 S0 ( x k 1) S0 ( x k ) = S 0 ( x) 15 Section 5.3 Class Exercises 6 x k( k 1 k 1 px k px ) 1 = ( j 1) j 1 k k 1 6 x 1 6 x 1 j px k k 1 6 x 6 x p k 1 x k k 1 6 x 1 k px = j j 1 px + 5 x 1 [( x j ) / 6] = 1 ( x / 6) 2 j 1 2 px 1 = j 1 6 (5 x) ( x j ) 2 2 5 x k j 1 2 6 x 2 E[Kx*] = 16 k k 2 p k 1 x 6 x 1 6 x 1 j 6 x 1 6 x j px k k 1 k k 1 k px = 6 x 1 k px = j 1 j px = Section 5.3 Class Exercises 7.-continued (d) Suppose is an integer greater than 1, is a positive constant, and x is an integer such that 0 < x < . In the table below, complete the column which defines the p.d.f. for Kx and the column which defines the p.d.f. for Kx* . Then, using work already done in part (c), find E[Kx] and E[Kx*]. Possible Possible Values Values for Kx for Kx* Probability ____________________________________________________ 0 1 . . . k1 k . . . E[Kx] = E[Kx*] = 17 Section 5.3 Class Exercises 8. Let T0 be a lifetime random variable with survival function S0(t) = (1 t / ) for 0 t where is an integer greater than 1, and is a positive constant (i.e., part of the family of distributions in #3). (a) Suppose = 6 and = 2. In the table below, complete the column which defines the p.d.f. for K0 and the column which defines the p.d.f. for K0* . Then, find E[K0] and E[K0*]. Possible Possible Values Values for K0 for K0* Probability ____________________________________________________ 0 1 18 Section 5.3 Class Exercises 8.-continued (b) Suppose = 6 and = 2. In the table below, complete the column which defines the p.d.f. for K2 and the column which defines the p.d.f. for K2* . Then, find E[K2] and E[K2*]. Possible Possible Values Values for K2 for K2* Probability ____________________________________________________ 0 1 19 Section 5.3 Class Exercises 8.-continued (c) Suppose = 6, = 2, and x is an integer such that 0 < x < 6. In the table below, complete the column which defines the p.d.f. for Kx and the column which defines the p.d.f. for Kx* . Then, find E[Kx] and E[Kx*]. Possible Possible Values Values for Kx for Kx* Probability ____________________________________________________ 0 1 . . . k1 k . . . (To find the following expected values, use the work done in #7(c)&(d).) E[Kx] = E[Kx*] = 20 Section 5.3 Class Exercises 8.-continued (d) Suppose is an integer greater than 1, is a positive constant, and x is an integer such that 0 < x < . In the table below, complete the column which defines the p.d.f. for Kx and the column which defines the p.d.f. for Kx* . Then, find E[Kx] and E[Kx*]. Possible Possible Values Values for Kx for Kx* Probability ____________________________________________________ 0 1 . . . k1 k . . . (To find the following expected values, use the work done in #7(c)&(d).) E[Kx] = E[Kx*] = 21 Section 5.3 Class Exercises 9. Let T0 be a lifetime random variable having an exponential distribution with mean (i.e., the family of distributions in #4). (a) Suppose k is a positive integer. Find a formula for P[K0 = k 1] = P[K0* = k], and then find a formula for each of E[K0] and E[K0*]. (b) Suppose 0 < x, and k is a positive integer. Find a formula for P[Kx = k 1] = P[Kx* = k], and then find a formula for each of E[Kx] and E[Kx*]. 22 Section 5.3 Class Exercises 10. Let T0 be a lifetime random variable with survival function S0(t) = 1 / (1 + t) for 0 t where > 0 and > 1 are constants (i.e., part of the family of distributions in #5). (a) Suppose = 1, = 2, and k is a positive integer. Find a formula for P[K0 = k 1] = P[K0* = k], and then find each of E[K0] and E[K0*]. 1 2 (Hint: To find the expected values, you will need to use 2 ). 6 n 1 n 23 Section 5.3 Class Exercises 10.-continued (b) Suppose = 1, = 2, and k is a positive integer. Find a formula for P[K3 = k 1] = P[K3* = k]; then find each of E[K3] and E[K3*]. 1 2 (Hint: To find the expected values, you will need to use 2 ). 6 n 1 n 24