Gr 11 Physics - Forces at an Angle Assignment
Consider the problem: A 12.0 kg mass is being accelerated across a horizontal
plane (μs= 0.543, μk = 0.321,) with an applied force of 80.0 N from rest. Your task
is to find the acceleration of the mass as the angle of the applied force changes by
increments of 15º from 0-90º. *Remember that only the horizontal component of
the applied force (FAH) will accelerate the mass and when the angle of the applied
force is not 0º, the normal force will change thereby changing the force of
friction. For each scenario:
□ Draw all forces on the mass including components
□ Create four Fnet statements, (2 for horizontal and 2 for vertical)
□ Calculate FN and Ff
□ Calculate the acceleration
“Sled” Type
Scenario 1: 0º
12.0
Kg
FnetH =
FnetH =
FnetV =
FnetV =
FN = _______
a = _______
Scenario 2: 15.0º
12.0
Kg
FnetH =
FnetH =
FnetV =
FnetV =
FN = _______
a = _______
Scenario 3: 30.0º
12.0
Kg
FnetH =
FnetH =
FnetV =
FnetV =
FN = _______
a = _______
Scenario 4: 45.0º
12.0
Kg
FnetH =
FnetH =
FnetV =
FnetV =
FN = _______
a = ________
Scenario 5: 60.0º
12.0
Kg
FnetH =
FnetH =
FnetV =
FnetV =
FN = _______
a = _______
Scenario 6: 75.0º
FnetH =
FnetH =
FnetV =
FnetV =
12.0
Kg
FN = _______
a = _______
Scenario 7: 90.0º
FnetH =
FnetH =
FnetV =
FnetV =
12.0
Kg
FN = _______
a = _______
Applied Force
μ
μ
12
80
0.543
0.321
Angle (deg)
0
15
30
45
60
75
90
Fav
0.00
20.71
40.00
56.57
69.28
77.27
80
Fah
80.00
77.27
69.28
56.57
40.00
20.71
0
Fn
117.72
97.01
77.72
61.15
48.44
40.45
37.72
Mass (kg)
Static F
63.92
52.68
42.20
33.21
26.30
21.96
0
Kinetic F
37.79
31.14
24.95
19.63
15.55
12.98
0
Fneth
42.21
46.13
44.33
36.94
24.45
0.00
0
a
3.52
3.84
3.69
3.08
2.04
0.00
0
“Lawnmower” Type
Scenario 1: 0º
12.0
Kg
FnetH =
FnetH =
FnetV =
FnetV =
FN = _______
a = _______
Scenario 2: 5.0º
12.0
Kg
FnetH =
FnetH =
FnetV =
FnetV =
FN = _______
a = _______
Scenario 3: 10.0º
12.0
Kg
FnetH =
FnetH =
FnetV =
FnetV =
FN = _______
a = _______
Scenario 4: 15.0º
FnetH =
FnetH =
FnetV =
FnetV =
12.0
Kg
FN = _______
a = ________
Scenario 5: 20.0º
FnetH =
FnetH =
FnetV =
FnetV =
12.0
Kg
FN = _______
a = ________
Applied Force
μ
μ
12
80
0.543
0.321
Angle (deg)
0
5
10
15
20
Fav
0.00
6.97
13.89
20.71
27.36
Fah
80.00
79.70
78.78
77.27
75.18
Fn
117.72
124.69
131.61
138.43
145.08
Mass (kg)
LAWNMOWER
Static F
63.92
67.71
71.47
75.17
78.78
Kinetic F
37.79
40.03
42.25
44.43
0.00
Fneth
42.21
39.67
36.54
32.84
0.00
a
3.52
3.31
3.04
2.74
0.00