HO 6 LIMITING REAGENT ICF (Initial Change Final ) Chart
1. Consider the following reaction: NH4NO3 + Na3PO4 (NH4)3PO4 + NaNO3
Which reactant is limiting, assuming we started with 30.0 grams of ammonium nitrate and 50.0 grams of
sodium phosphate. What is the mass of each product that can be formed? What mass of the excess reactant(s)
is left over?
Initial moles
Which is the
Limiting
reactant?
3 NH4 NO3
0.3747
Na 3PO4 
0.3049
Comes from
30.0/80.052
Comes from
50.0/163.94
0.3747/3 =
0.1249
0.3049/1
=0.3049
(NH4 )3 PO4
Zero
3 Na NO3
Zero
Smaller than 0.3049,
Hence
Na 3PO4 is in
excess
DO NOT USE THESE answers in the division in any subsequent calculations !!!!!!!
They are only to be used to determine the LR.
NH4 NO3 is LR
In all the following steps use initial moles of LR and mole
ratios to find the desired moles
Changed moles
(used or
produced)
-0.3747
(all of initial LR)
Final moles
Zero
- 0.1249
(calculate from
initial moles of
LR and the
mole ratio)
0.30490.1249=
0.180
+ 0.1249
+0.3747
0.1249
0.3747
Changed moles:
0.3747 moles (LR) NH4 NO3 used x 1mol Na 3PO4 used
3mole NH4 NO3 used
0.3747 moles (LR) NH4 NO3 used x 1mol (NH4 )3 PO4 formed
3mole NH4 NO3 used
0.3747 moles (LR) NH4 NO3 used x 3mol Na NO3formed
3mole NH4 NO3 used
= 0.1249 mol Na 3PO4 used
= 0.1249 mol (NH4 )3 PO4 formed
= 0.3747 mol Na NO3formed
Products: (NH4 )3 PO4 : 0.1249 (149.09) = 18.6 g ; Na NO3 : 0.3747 (84.99) = 31.8 g
Left over excess reactant Na 3PO4 = 0.180 (163.94) = 29.5 g
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HO 6 LIMITING REAGENT ICF (Initial Change Final ) Chart
2.
In this reaction: CaCO3 + FePO4 Ca3(PO4)2 + Fe2(CO3)3
Which reactant is limiting, assuming we start with 100. grams of calcium carbonate and 45.0 grams of iron
(III) phosphate. What is the mass of each product that can be formed? What mass of the excess reactant(s) is
left over?
?
2 Fe(PO4) 
?
?
?
?
?
3 CaCO3 +
Initial moles
Ca 3(PO4) 2
Zero
Fe2(CO3)3
Zero
Which is the
Limiting reactant?
Changed moles
(used or produced)
Final moles
Ca 3(PO4) 2 46. 3 g ; Fe2(CO3)3 = 43.8 g
3) In the balanced reaction :
Page 2 of 3
?
CaCO3 = 54.0 g left at the end of reaction
CuCl2 + NaNO3  Cu(NO3)2 + NaCl
HO 6 LIMITING REAGENT ICF (Initial Change Final ) Chart
a) If 15 grams of copper (II) chloride react with 20. grams of sodium nitrate,
how much sodium chloride can be formed? b) What is the name of the limiting reagent?
c) How much of the excess reagent is left over in this reaction?
Page 3 of 3