Adyar – Adambakkam – Pallavaram – Pammal – Chromepet – Selaiyur +2 Mathematics Group theory - Solutions Q.No. 1 Solution : Binary operation is defined as x o y = x ; x, y S [ Meaning : (first element) o ( Second element) = First element ] Commutative Axiom : x o y = x ---- (1) y o x = y ----- (2) (1) ≠ (2) Commutative axiom is not satisfied Associative Axiom: x o ( y o z ) = x o y = x ------(3) (x o y ) o z = x o z = x ------(4) (3)=(4) Associataive axiom is satisfied Conclusion : The binary operation o is Associative but not commutative Q.No. 2 Solution : N = Set of all natural numbers Binary operation = x * y = Max ( x , y ) [ Example : 4 * 6 = 6 since 6 is highest ] Closure axiom : for all x, y N , x * y = Max(x,y) N Associative axiom : for all x, y , z N x * ( y * z ) = x * Max(y,z) = Max( x, y, z) N ( x * y ) * z = Max(x,,y) * z = Max ( x,y,z) N Identity axion : here for any x N 1 * x = x and x * 1 = x ( since 1 is the least natural number) identity element is 1 Identity element exists Therefore N is a monoid under the operation * Q. No 3 Solution : G = The set of all positive even integers Under addition Closure axiom : The sum of any two positive even integers is a positive even Integer. Closure axiom is true Associative axiom : Usual addition is always associative Identity axiom : Under addition, identity element is 0 , not belong to G Identity element does not exists The set G under addition is a semi-group but not a monoid Under multiplication Closure axiom : The product of any two positive even integers is also a positive even integer. Closure axiom is true Associative axiom : Usual multiplication is always associative Identity axiom : Under multiplication, identity element is 1, not belong to G Identity element does not exists The set G under multiplication is a semi-group but not a monoid Q.No. 7 Solution M = set of all complex numbers whose modulus is 1 Binary operation : Multiplication Closure axiom : for all z1 , z2 M => |z1| = 1 and |z2| =1 | z1 . z2| = | z1| | z2| = (1) (1) =1 Closure axiom is true Associative axiom : Usual multiplication is always associative Identity axiom : Under multiplication , Identity element is 1 M : Since | 1 | = 1 for all z M , such that | z| =1 Inverse axiom Under multiplication , inverse of z = 1/z M Since |1/z| = |1| / |z| = 1/1 = 1 Inverse of each element exists. M is a group with respect to multiplication Q.No. 12 Solution G Binary operation = { 2 n / n Z } i.e 2 to the power of any integer belong to the set G = Mulitplication Closure axiom : for all 2a . 2b G , a , b Z 2a . 2b = 2 a+ b G since a+b Z Closure axiom is true. Associative axiom : Usual multiplication is always associative Identity axiom : Under multiplication , identity element is 1 i.e 20 G , since 0 Z Identity element exists Inverse axiom : for all 2a G, inverse of 2a is 2 –a G since –a Z Also 2 a . 2 –a = 2 a –a = 2 0 Inverse of each element exists. G is a group under multiplication Commutative axiom : for all 2 a , 2 b G such a , b Z 2a . 2b = 2a+b = 2b+a = 2b . 2a Commutative axiom is true G is an abelian group under multiplication We offer The ULTIMATE intensive coaching for A complete crash course for the students of +2 aspiring for AIEEE Contact 9840448693