Name ____________________ Period ______ Recipes in Chemistry The “recipe” for making ammonia is: N2 + 3H2 2NH3 There are 3 different ratios in this recipe, using the coefficients: 1N2 : 3H2 or 1N2 3H2 1N2 : 2NH3 or 1N2 2NH3 3H2 : 2NH3 or 3H2 2NH3 These ratios are called molar ratios. In mole to mole problems, one might be asked how many moles of one chemical are needed to react with/or produce another chemical. For instance, how many moles of nitrogen would be needed to react with 9 moles of hydrogen? 9 mol H2 x 1 mol N2 = 3 mol N2 1 3 mol H2 How many moles of ammonia would be produced from 16 moles of nitrogen and excess hydrogen (When it says excess something, that means you don’t need to worry about it)? How many moles of hydrogen would be needed to produce 17 moles of ammonia? How many moles of nitrogen would be needed to react with 0.6 moles of hydrogen to produce ammonia? Name ____________________ Period ______ The “recipe” for making ammonia is: N2 + 3H2 2NH3 There are 3 different ratios in this recipe, using the coefficients: 1N2 : 3H2 or 1N2 3H2 1N2 : 2NH3 or 1N2 2NH3 3H2 : 2NH3 or 3H2 2NH3 The molar masses of the three substances are: N2 H2 NH3 In mass to mole problems, a mass is given which must be changed into moles and then changed to the moles of the other substance. For instance, how many moles of nitrogen would react with 6 grams of hydrogen gas? 6 grams H2 x 1 mol H2 x 1 mol N2 = 1 mole N2 1 2 grams H2 3 mol H2 How many moles of hydrogen are needed to produce 85 grams of ammonia? How many moles of ammonia would be produced from 84 grams of nitrogen and excess hydrogen? How many moles of nitrogen would be needed to react with 27 grams of hydrogen? Name ____________________ Period ______ The “recipe” for making ammonia is: N2 + 3H2 2NH3 There are 3 different ratios in this recipe, using the coefficients: 1N2 : 3H2 or 1N2 3H2 1N2 : 2NH3 or 1N2 2NH3 3H2 : 2NH3 or 3H2 2NH3 The molar masses of the three substances are: N2 H2 NH3 In mole to mass problems, a number of moles is given which must be changed into moles of the other substance and then changed into mass. For instance, how many grams of nitrogen would react with 6 moles of hydrogen gas? 6 moles H2 x 1 mol N2 x 28 g N2 = 56 grams N2 1 3 mol H2 1 mol N2 How many grams of hydrogen are needed to produce 5 moles of ammonia? How many grams of ammonia would be produced from 14 moles of nitrogen and excess hydrogen? How many grams of nitrogen would be needed to react with 33 moles of hydrogen? Name ____________________ Period ______ The “recipe” for making ammonia is: N2 + 3H2 2NH3 There are 3 different ratios in this recipe, using the coefficients: 1N2 : 3H2 or 1N2 3H2 1N2 : 2NH3 or 1N2 2NH3 3H2 : 2NH3 or 3H2 2NH3 The molar masses of the three substances are: N2 H2 NH3 In mass to mass problems, a mass is given which must be changed into moles and then changed to the moles of the other substance, and then mass. For instance, how many grams of nitrogen would react with 6 grams of hydrogen gas? 6 grams H2 x 1 mol H2 x 1 mol N2 x 28 grams N2 = 28 grams N2 1 2 grams H2 3 mol H2 1 mol N2 How many grams of hydrogen are needed to produce 68 grams of ammonia? How many grams of ammonia would be produced from 128 grams of nitrogen and excess hydrogen? How many grams of nitrogen would be needed to react with 21 grams of hydrogen?