Molar conversions and Empirical Formulas steps

advertisement

Molar conversions:

Possible molar conversion ratios to use: 22.4L ?g 6.02 x10

23

molecules

1 mol 1 mol 1 mol

Ex: How many grams of rubidium phosphide are there in 4.37x10

18 atoms of the compound?

1.

Identify the known/given (in red) and the unknown (in blue) from the problem. Determine the formula of the compound in the problem, if not already given.

Known: 4.37x10

18 atoms Rb

3

P Unknown: grams Rb

3

P

2.

Start the equation for the conversion by writing the known (given) with the unit and label (formula)

3.

Identify the conversion ratio to use

4.37x10

18 atoms Rb

3

P 1mol Rb

3

P 287.5g Rb

3

P = 2.1x10

-3 g Rb

3

P

6.02x10

23 atoms Rb

3

P 1mol Rb

3

P

4.

Cancel like terms – do calculations OR identify the next conversion ratio to use and calculate answer

To determine Empirical Formulas:

Ex: A compound contains 17.6% sodium, 39.7% chromium, and 42.7% oxygen. What is the empirical formula?

1.

Change % to g (grams)

2.

Convert grams to moles, using molar mass, found on the periodic table

3.

Identify the smallest mole answer from step number 2 and divide all the answers by that smallest number a.

If the answer is not a whole number, you must multiply it by some number (2,3,4) to get a whole number

4.

Write the formula placing the number calculated from step 3 as a subscript

Step 1 Step 2 Step 3 step 3a Step 4

Na

2

Cr

2

O

7

17.6% Na = 17.6g Na 17.6g Na 1mol Na = 0.77 mol

23.0g Na

39.7% Cr = 39.7g Cr 39.7g Cr 1mol Cr = 0.76 mol

52.0g Cr

42.7% O = 42.7g O 42.7g O 1mol O = 2.67 mol

42.7g O

0.77 mol = 1 x2 =2

0.76

0.76 mol = 1 x2 =2

0.76

2.67 mol = 3.5 x2 =7

0.76

Download