Lausn

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BYG301G – CONTINUUM MECHANICS 1
Homeworks 4 & 5 – Fall 2012
Assigned: Thursday, 20 September 2012
Due: Thursday, 4 October 2012 8:20
Problem 1
A two-dimensional state of stress in the x, y plane is given by 𝜎𝑧 = đœđ‘§đ‘„ = 𝜏𝑧𝑩 = 0:
đœŽđ‘„
[𝜎𝑖𝑗 ] = [𝜏
đ‘„đ‘Š
đœđ‘„đ‘Š
𝜎𝑩 ]
a) Using general principal value theory, establish the eigenvalue problem and the
characteristic equation, the stress invariants, and derive the following equations for the
principal stresses
𝜎1,2 =
đœŽđ‘„ + 𝜎𝑩
đœŽđ‘„ − 𝜎𝑩 2
± √(
) + đœđ‘„đ‘Š 2
2
2
Lausn:
b) Use the stress transformation equations to show that the maximum shear stress equals
đœŽđ‘„ − 𝜎𝑩 2
đœđ‘šđ‘Žđ‘„ = ±√(
) + đœđ‘„đ‘Š 2
2
Lausn:
c) Using the invariants from (a) demonstrate the invariant nature of the principal stresses
and maximum shear stresses by showing that
1
1
𝜎1,2 = đŒ1 ± √đŒ1 2 − 4đŒ2
2
2
and
1
đœđ‘šđ‘Žđ‘„ = √đŒ1 2 − 4đŒ2
2
Lausn:
d) Uncouple the stress tensor into isotropic and deviatoric components both for the
general đ‘„, 𝑩 state and principal state đ‘„P, 𝑩P. Show how the results in (c) relate to the
components of the uncoupled stress tensor
Lausn:
First we uncouple for general state in isotropic and deviatoric:
đœŽđ‘„ + 𝜎𝑩
đœŽđ‘„ − 𝜎𝑩
0
đœđ‘„đ‘Š
đœŽđ‘„ đœđ‘„đ‘Š
𝑆
𝜏
𝜎𝑚 0
đ‘„
đ‘„đ‘Š
2
2
=
+
=
+
[𝜎𝑖𝑗 ] = [𝜏
]
[
]
[
]
[
]
[
đœŽđ‘„ − 𝜎𝑩 ]
𝜎𝑩
đœŽđ‘„ + 𝜎𝑩
0 𝜎𝑚
đœđ‘„đ‘Š 𝑆𝑩
đ‘„đ‘Š
𝜏
−
0
đ‘„đ‘Š
2
2
Next to uncouple for principal state:
đœŽđ‘„
[𝜎𝑖𝑗 ] = [𝜏
đ‘„đ‘Š
đœđ‘„đ‘Š
𝜎𝑚
𝜎𝑩 ] = [ 0
đ‘†đ‘„
0
]+[0
𝜎𝑚
đœŽđ‘„ + 𝜎𝑩
0
2
𝑆𝑩 ] = [
0
0
đœŽđ‘„ + 𝜎𝑩
2
đœŽđ‘„ − 𝜎𝑩
]+[ 2
0
0
đœŽđ‘„ − 𝜎𝑩 ]
−
2
Now to see how the results in (c) relate to the components of these uncoupled stress tensor.
2
Start with general stress. We use invariants that we found in (a) đŒ2 = đœŽđ‘„ + 𝜎𝑩 and đŒ2 = đœŽđ‘„ 𝜎𝑩 − đœđ‘„đ‘Š
If we exchange 𝜎𝑚 =
đœŽđ‘„ +𝜎𝑩
2
1
= 2 đŒ1 and then we have the first part of the equation of (c), the second
2
part is a little bit difficaulter, rewrite for đŒ2 and have đœŽđ‘„ 𝜎𝑩 = đŒ2 + đœđ‘„đ‘Š
also we can rewrite
to
Then
đœŽđ‘„ +𝜎𝑩 2
√(
1
√đŒ12
2
2
đœŽđ‘„2 −2đœŽđ‘„ 𝜎𝑩 +𝜎𝑩2
) =√
4
1
1
đœŽđ‘„ +𝜎𝑩
2
in
= 2 √đœŽđ‘„2 + 𝜎𝑩2 − 2đœŽđ‘„ 𝜎𝑩 and change đœŽđ‘„2 + 𝜎𝑩2 = đŒ12 − đœŽđ‘„ 𝜎𝑩
2 )=
− 4đœŽđ‘„ 𝜎𝑩 = 2 √đŒ12 − 4(đŒ2 + đœđ‘„đ‘Š
1
√đŒ12
2
2 so
− 4đŒ2 − 4đœđ‘„đ‘Š
1
1
2
𝜎1,2 = đŒ1 ± √đŒ1 2 − 4đŒ2 − 4đœđ‘„đ‘Š
2
2
We do exactly the same for principal stress but there will đœđ‘„đ‘Š = 0 so the answer is
1
1
𝜎1,2 = đŒ1 ± √đŒ1 2 − 4đŒ2
2
2
e) Use the stress transformation equations to calculate the normal stresses and shear
stresses in the quadrilateral state (i.e., the stresses on a plane normal to an axis that
makes an equal angle to both principal axes xp , yp).
Lausn:
Snúum principal state um 45° til að fá quadrilatral state. Byrjum á normal stresses og notum jöfnur
4.11 bls 44 í nótum Ragnars:
𝜎′đ‘„ =
đœŽđ‘„ + 𝜎𝑩 đœŽđ‘„ − 𝜎𝑩
−
cos(2 × 45) + đœđ‘„đ‘Š sin(2 × 45)
2
2
𝜎′đ‘„ =
𝜎′𝑩 =
đœŽđ‘„ + 𝜎𝑩
+ đœđ‘„đ‘Š
2
đœŽđ‘„ + 𝜎𝑩 đœŽđ‘„ − 𝜎𝑩
−
cos(2 × 45) − đœđ‘„đ‘Š sin(2 × 45)
2
2
𝜎′𝑩 =
đœŽđ‘„ + 𝜎𝑩
− đœđ‘„đ‘Š
2
Að lokum finnum við lausn fyrir shear stresses:
𝜏′đ‘„đ‘Š = −
đœŽđ‘„ − 𝜎𝑩
sin(2 × 45) + đœđ‘„đ‘Š cos(2 × 45)
2
𝜏′đ‘„đ‘Š =
𝜎𝑩 − đœŽđ‘„
2
Problem 2
The stresses acting on a rectangular element along the đ‘„, 𝑩 axes are given as
đœŽđ‘„
[𝜎𝑖𝑗 ] = [𝜏
đ‘„đ‘Š
đœđ‘„đ‘Š
80
𝜎𝑩 ] = [30
30
] 𝑀𝑃𝑎
40
Part 1: Carry out calculations using equations resulting from the stress transformation
equations, the principal stress eigenvalue problem, and the quadrilateral stress state
Part 2: Carry out calculations using Mohr’s circle with the following convention
1.
𝜏 axis is positive down.
2.
Point X comprising of stress components on the đ‘„-side of the element is plotted as
(𝜎x, 𝜏xy) while point Y is plotted as 𝜎y, −𝜏xy .
In all cases, draw up the elements and the stress components in the new coordinate system,
relative to the original configuration in the đ‘„, 𝑩 coordinate system.
a)
Determine the principal stresses and the directions of principal axes.
Lausn:
b)
stresses.
Determine the maximum shear stresses and axis direction, and calculate the normal
Lausn:
c)
Calculate the quadrilateral normal and shear stresses i.e., those that occur on a plane
normal to an axis that makes an equal angle to both principal axes đ‘„P, 𝑩P.
Lausn:
d)
Resolve both the original and the principal tensor into their isotropic and deviatoric
components (For Part 2, show the isotropic and deviatoric components of normal
stress on the Mohr’s Circle).
Lausn:
e)
(For Part 1): Calculate the invariants of the stress tensor for both the original đ‘„, 𝑩
orientation and the principal đ‘„P, 𝑩P orientation (checking to make sure they are
actually the same in either system).
Lausn:
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