Calculation of receiver area To determine the possible area where each fish was detected, initially the percentage of detections for each receiver was calculated. Receivers with percentage detections fewer than 5% were considered negligible and were excluded from area calculations. For receiver locations where the number of detections was greater than 5% of the total detections, the overall area can be calculated. The positioning of the receivers allows perfect coverage of the outer reef flat, reef crest and base in Pioneer Bay, Orpheus Island. This coverage causes the range of each receiver to intersect with the receivers adjacent to its position. Therefore, for the case where two receivers, i and j for example, have their detection range areas intersect, if detections were shown for receiver i and not receiver j, the detection area for receiver i is not simply the area of a circle of equal receiver radius, r (m). Instead, the middle area between the two intersections, Ei,j (m2), should be determined and subtracted from this area to calculate the detection area based solely around receiver i, Ai (m2), receiver j, Aj (m2) and the combined area of receivers i and j, Ai,j (m2) (Fig S1). Fig. S1 Intersection of two receiver detection ranges for receivers i and j: a) schematic showcasing intersection area, b) constructed geometry to determine the intersection area. To determine the respective areas of receivers i and j, first the centre-centre distance, di,j (m), between the receivers is approximated using global positioning system (GPS) coordinates. As the range radius is identical for all receivers, the angle, θi,j, created by a radial line generating from the centre of the receiver to the intersection with the adjacent receiver is calculated using the principles of an isosceles triangle such that. ππ,π = cos−1 ππ,π 2π (1) The resulting area of the intersection between the two receivers can then be calculated as, πΈπ,π = π 2 (2ππ,π − sin 2ππ,π ) With the areas of receivers i and j separately being, (2) π΄π = ππ 2 − πΈπ,π (3) π΄π = ππ 2 − πΈπ,π (4) and the combined area if a detection was detected at receivers i and j is, π΄π,π = π΄π + π΄π + πΈπ,π = 2ππ 2 − πΈπ,π (5) Although these equations hold true for intersections of two receivers, due to their positioning, some cases create intersections between three receivers for example, i, j and k (Fig S2). In this instance, a number of possible outcomes are present. These include, detections at only receiver i, receiver j or receiver k, detections at either receivers i and j, receivers i and k or receivers j and k, or detections at all receivers i, j and k. In either of these circumstances, the area for all segments must be calculated. This is achieved by first generating a polygon consisting of a number of triangles that form when drawing lines between each intersection and centre points of the receivers (Fig S2b). Fig. S2 Intersection of three receiver detection ranges for receivers i, j and k: a) schematic showing intersection areas, b) constructed geometry to determine the inner polygon area, c) showcased angles to determine the outer circular areas not included in the inner polygon’s geometry. The distances between each centre point, di,j (m), di,k (m) and dj,k (m), are again determined through GPS coordinates. The polygon area, Pi,j,k (m2), can then be calculated by summating the areas of the four triangles drawn with Heron’s formula. For the three outer triangles, their respective areas, pi,j (m2), pi,k (m2) and pj,k (m2), can be calculated by, π π₯,π¦ = 2π + ππ₯,π¦ 2 ππ₯,π¦ = π π₯,π¦ (π π₯,π¦ − ππ₯,π¦ )(π π₯,π¦ − π) (6) 2 (7) where x and y are the respective possible combinations of receivers i, j and k. The inner triangle area, pi,j,k (m2), is determined by, π π,π,π = ππ,π + ππ,π + ππ,π 2 ππ,π,π (8) (9) = π π,π,π (π π,π,π − ππ,π )(π π,π,π − ππ,π )(π π,π,π − ππ,π ) Thus, the overall inner polygon area is, ππ,π,π = ππ,π + ππ,π + ππ,π + ππ,π,π (10) The remaining area of the circle can be determined by finding the outer angle, φ, for the various receivers i, j and k as shown in Fig S2c. For all angles shown by α and γ, these can be calculated using a modified eqn (1) with α and γ replacing θ, and the centre-centre distance di,j replaced with the corresponding centre-centre distances (Fig S2). The inner angle β is determined using the cosine rule for all receivers i, j and k. Therefore, the outer angle is calculated for each receiver as, ππ₯ = 2π − πΌπ₯ − π½π₯ − πΎπ₯ (11) where subscript x is replaced with i, j and k for each corresponding receiver. The outer area for each receiver, Oi (m2), Oj (m2) and Ok (m2), not considered by the inner polygon is then, ππ₯ = 1 2 π ππ₯ 2 (12) Again with subscript x being replaced with i, j and k for each corresponding receiver. The total combined area, Ai,j,k (m2), of receivers i, j and k can now be found using eqn (13). π΄π,π,π = ππ + ππ + ππ + ππ,π,π (13) The individual areas of each receiver, Ai (m2), Aj (m2) and Ak (m2), are determined by considering the intersection of only each pair of receivers within the group, and subtracting this combined area of the two intersecting receivers from the total combined area. This summarizes to, π΄π = π΄π,π,π − π΄π,π (14) π΄π = π΄π,π,π − π΄π,π (15) π΄π = π΄π,π,π − π΄π,π (16) Throughout the process of calculating the areas for each pair of receivers, the lens areas Ei,j (m2), Ei,k (m2) and Ej,k (m2) are determined. Therefore, the middle area, mi,j,k (m2), of the intersection can be determined, as this area, dependent on the positioning of the receivers, must be subtracted or added to each receiver area based on a number of combinations. This area can be found using simple geometry such that, ππ,π,π = π΄π,π,π − π΄π − π΄π − π΄π − πΈπ,π − πΈπ,π − πΈπ,π (−2) (17) Conducting these calculations for each receiver allows for the calculations of a number of areas. These calculations form a tedious process, and a MATLAB code was generated to conduct these calculations, and given appropriate percentage detections at each receiver, this code displays the total detection area of the reef fish where total detections exceeded 5% of all detections.