Developing a Lens of Structure to Build Mathematical Meaning Casey Hawthorne San Diego State University caseyhawthorne@yahoo.com CCSS.MATH.PRACTICE.MP1 CCSS.MATH.PRACTICE.MP2 CCSS.MATH.PRACTICE.MP3 CCSS.MATH.PRACTICE.MP4 CCSS.MATH.PRACTICE.MP5 CCSS.MATH.PRACTICE MP6 CCSS.MATH.PRACTICE.MP7 CCSS.MATH.PRACTICE.MP8 Beth Rackliffe La Mesa Spring Valley SD beth780@gmail.com Make sense of problems and persevere in solving them. Reason abstractly and quantitatively. Construct viable arguments and critique the reasoning of others. Model with mathematics. Use appropriate tools strategically Attend to precision Look for and make use of structure. Look for and express regularity in repeated reasoning Mathematically proficient students look closely to discern a pattern or structure. Young students, for example, might notice that three and seven more is the same amount as seven and three more, or they may sort a collection of shapes according to how many sides the shapes have. Later, students will see 7 × 8 equals the well remembered 7 × 5 + 7 × 3, in preparation for learning about the distributive property. In the expression x2 + 9x + 14, older students can see the 14 as 2 × 7 and the 9 as 2 + 7. They recognize the significance of an existing line in a geometric figure and can use the strategy of drawing an auxiliary line for solving problems. They also can step back for an overview and shift perspective. They can see complicated things, such as some algebraic expressions, as single objects or as being composed of several objects. For example, they can see 5 – 3(x -y)2 as 5 minus a positive number times a square and use that to realize that its value cannot be more than 5 for any real numbers x and y. Components of Structural Sense a) Seeing a mathematical expression as an entity, not as a process b) Recognizing connections among different mathematical forms and ideas-identifying an expression as a familiar structure c) Dividing an entity into a variety of sub-structures according to context d) Stopping to look at an expression to choose an appropriate manipulation that makes best use of the structure, instead of automatically applying a set procedure. Cover Up Method Solve the following for x in two different ways 50 11 − =6 đĨ−2 Seeing Structure in Notation What do you see in the number 23? What are the different ways one might see the number of tens in 347? 4 tens? 34 tens? 34.7 tens? 87 + 35 Algorithm Base 10 structure Number line structure Compensation Number Line Structure Compensation Structure Algorithm 8 7 +3 +5 Base 10 Structure (80 + 30 )+ (7 + 5) 3 87 90 90 + 40 = 130 130 – 8 = 122 22 10 100 122 Number Strings a) 6 x 25 b) 16 x 25 c) 16 x 35 Algebra Strings Knowing that x = 16 is a solution to 2x + 5 = 37, what are the solutions to a) 2(x – 3) + 5 = 37 b) 2x2 + 5 = 37 My Number/Algebra String Problem Relational Thinking Solve the following for â a) 37 + 54 = â + 55 b) 98 + 48 – 48 = â c) 98 + 74 + 2 = â Jacobs, V. R., Franke, M. L., Carpenter, T. P., Levi, L., & Battey, D. (2007). Professional development focused on children's algebraic reasoning in elementary school. Journal for research in mathematics education, 258-288. Equation 1 1 1 (1 − đ+2) − (1 − đ+2) = 132 1 1 1 1 − đ+2 − 1 + đ+2 = 72 1 đĨ 1 đĨ (4 − đĨ−1) − đĨ = 6 + (4 − đĨ−1) 1 4 đĨ 1 đĨ − đĨ−1 − đĨ = 6 + 4 − đĨ−1 Advanced Intermediate 23% (3/13) 12.5% (2/16) 0% (0/16) 0% (0/15) 25% (4/16) 11.8% (2/17) 18.8% (3/16) 6.3% (1/16) Hoch, M., & Dreyfus, T. (2004). Structure sense in high school algebra: The effect of brackets. In Proceedings of the 28th Conference of the International Group for the Psychology of Mathematics Education (Vol. 3, pp. 49-56). My Relational Thinking Problem Attending to structure allows you to see connections Simplification Are any of the following equal to 1? Why or why not? đĄ+3 a) đĄ+2 = 1 b) đĄ+3 đĄ−3 =1 c) đĄ−3 3−đĄ =1 There is no simplest form. Each form has different meanings and should be appreciated as such. Think of three forms of quadratic Factoring a) (2x + 3)2 – 12(2x + 3) + 36 d) Prove that đ(đ+1)(đ+2) 3 b) (2x – 3)(x2 – 4) + (đ + 1)(đ + 2) = c) (x + 3)2 – (x – 3)2 (đ+1)(đ+2)(đ+3) 3 Solving 6 a) Solve the following for x đĨ−6 đĨ 9 − đĨ−6 = 9−đĨ a) 3x + 6y = 4 b) 4y – 3(x – 2) = 7 2x – 3y = -5 2x – 4 = 5y 2 2 c) Solve the following for 2xy 12xy – 4x y = 34xy – 13 d) Solve the following for v v√đĸ = 1 + 2đŖ√1 + đĸ 2 e) Knowing the solutions to 6x – 2x = 17x – 13 are x = 1 and -6.5, what are the solutions to 12x2 – 4x4 = 34x2 – 26? b) Solve the following using substitution Chunking: How can we compare/relate the different compounding interest formulas? While the all look very different, each of these expressions have the same structure. P(1 + r)t đ(1 + đ⁄đ)đđĄ Pert P(1 + r)t đ((1 + đ⁄đ)đ )đĄ P(đ đ )đĄ Imagine a rate of 5% compounded daily, monthly and continuously 12 đĄ P(1 + .05)t đ ((1 + . 05⁄12) ) P(đ .05 )đĄ P(1.05)t P(1.05116)t P(1.05127)t Graphing What number makes sense to plug in, in order to see the y-value very easily? y = -2x + 4 when we plug in x = 0, then y = 4, giving us the y-intercept of (0, 4) y = 3(x – 2) + 1 when we plug in x = 2, then y = 4, giving us the point (2, 1) From this perspective, the slope intercept and point-slope forms of linear equations have very similar structure. Flexibility What other results can be deduced from the following product? 23 x 35 = 805 Connecting Algebra with Representation Consider the algebraic expressions below: (n+2)2 – 4 n2+4n a. Use the figures below to illustrate why the expressions are equivalent b. Use an algebraic method to verify the same result. c. Can you show that n2+4n = (n+4)n using the diagram? Add-Subtract-Multiply-Divide a) 3476 + 2456 – 1476 b) 99 – 17 c) 99 × 17 d) 165/15 e) 6 × 43 + 6 × 7 f)50 x 35 x 2 ÷ 5 g) 125 × 13 × 80 3 1 4 h) ī īĢ 7 9 7 5 i) 13 10 13 j) [ 1 (3 ī 2 ) īĢ 5 ī 4 ( 5 īĢ 2)]( 6 ī 18 ) 3 3 7 2 3 Mental Percentages a) 15% of 60 d) 40% of 35 g) 96% of 200 b) 25% of 320 e) 90% of 500 h) 96% of 150 c) 4% of 400 f) 120% of 50 i) 96% of 75 Sequences a) 1 ī´ 2 ī´ 3 ī´ 4 ī´ 5 ī´ 6 ī´ 7 ī´ 8 ī´ 9 2 3 4 5 6 7 8 9 10 īĨ c) b) (1 + 1 1 1 1 )(1 + )(1 + )…(1 + ) 2 3 10 1 1 1 ī (telescoping series) n nīĢ2 īĨ n īŊ1 Integration a) ∫ đĨ√đĨ 2 + 1đđĨ c) Given that i. ī˛ 3 1 ī˛ 3 1 b) ∫ đĨ √đĨ + 1đđĨ g ( x )dx = 10, deduce the value of 1 g ( x)dx; 2 ii. ī˛ 3 1 ( g ( x) īĢ 4)dx. Quadratics a) Can you see the vertex in the quadratic formula? −đ±√đ2 −4đđ 2đ b) Can you see in the quadratic formula that the sum of roots is –b/a, or product of roots is c/a (Vieta’s formula) c) Can you see the factors forming a rectangle with integer sides? a square? Neither? x2 + 2x + 1 = (x + 2)(x + 1) x2 + 2x + 1 = (x + 1)2 x2 + x + 1 Gurl, T., Artzt, A., Sultan, A., & Curcio, F. (2014). Implementing the Common Core State Standards through Mathematical Problem Solving: High School. Reston, VA: National Council of Teachers of Mathematics. Functional decomposition-Domain and Range 25 a) đ(đĨ) = 8√1 − đĨ 2 25 Domain: đĨ 2 cannot be bigger than 1, or the radical will be irrational. So x must be greater than 5 or less than -5. 25 Range: The biggest number that 1 − đĨ 2 can produce is 1. So the range will be less than or equal to 8. The smallest value will be 0 which occurs when 25 đĨ2 gets closer to 1. b) đ(đĨ) = √đĨ − 1 + 3 Domain: We know what’s inside a square root must be positive or zero. What is the largest number that x can be so that x – 1 is positive? 1 Range: we first have to identify that the square root only produces positive numbers (0 to infinity). If we increase the possibilities by 3, we get 3 to infinity. c) â(đĨ) = √đđđ3 đĨ Domain: We can only take the square root of positive numbers. So the output of the log can only be 0 to infinity. When will log’s be positive? When the argument is 1 or larger. Range: Logs will produce all positive numbers and zero. So the range greater than or equal to zero.