ASSIGNMENT 1: UNIT OPERATIONS Particle Size Average particle Screen Opening Mass Fraction Dpi (mm) Retained, xi Μ ππ mm π« 4 4.699 0.0000 - 6 3.327 0.0251 4.013 8 2.369 0.1250 2.845 2.007 Mesh 10 1.651 0.3207 14 1.168 0.2570 20 0.833 0.1590 diameter 1.409 < 1.5mm ππ Μ ππ π« ππ Μ ππ π π« 0 0 0.0063 0.0004 0.0439 0.0054 0.1598 0.0397 0.1824 0.0919 0.1588 0.1585 0.0757 0.1497 0.0418 0.1650 0.0287 0.2261 0.0306 0.4812 0.0326 1.0284 0.0325 2.0496 0.0348 4.3974 0.2027 148.0663 1.0305 156.8595 1.001 28 0.589 0.0538 0.711 35 0.417 0.0210 0.503 48 0.295 0.0102 0.356 65 0.208 0.0077 0.252 100 0.147 0.0058 0.178 150 0.104 0.0041 0.126 200 0.074 0.0031 0.089 Pan - 0.0075 0.037 Sample calculations of average particle diameter Μ ππ (ππππ π) = π« π π.πππ+π.πππ π = π. πππ 1. The size of 35 kg crushed rocks has been analyzed using sieving method. The results of the sieving process are tabulated in the Table 1. The density of the particle is 1550 kg/m3 and the shape factor are a =0.8 and Φ = 0.69 Calculate: (a) The specific area of particles ( Aw) (mm2/g) for the material between 4-mesh and pan. π΄π = 6 π₯π ∑ Μ Μ Μ Μ π·π ππ π·ππ π΄π = 6 (1.0305) = ππππ. ππ ππ2 /π 0.69(0.001550) (b) Number of particles in mixture (Nw) (particles/g) for the material between 4-mesh and pan ππ = 1 π₯π ∑ Μ Μ Μ Μ Μ Μ 3 πππ π· ππ ππ = 1 (156.8595) = ππππππ. π ππ2 /π 0.8(0.001550) (c) Volume surface mean diameter (Ds) (mm) Μ π = π· 1 1 = = 0.97ππ π₯π 1.0305 ∑ Μ Μ Μ Μ π·ππ (d) If 70% of the crushed glass must have size less than 1.5mm, please state whether or not the particles need to be crushed again? The particle need to be crushed again because, only 52.92% of the average particle size is less than 1.5mm Μ ππ > 1.5mm = (xi =0.0251+0.1250+0.3207= Refer to the table ο particle with π« Μ ππ < 1.5mm = (1-0.4708= 0.4708x100= 47.08%) whereas particle with π« 0.5292x100=52.92%).Thus it need to be crushed again to achieve 70%. Size Reduction 2. State four 4 types of equipments employed in particles size reduction. Elaborate the principles of those equipments. Crusher - Do the heavy work of breaking large pieces of solid material into small pieces - A slow speed machines for coarse reduction of large quantities of solids - Primary crusher can break the solids into 150-250mm size - Secondary crusher could reduced the particle from primary crusher to 6mm in size - Crusher reduces the solid size by compression Grinder ο Reduce crushed feed to powder ο Product from a crusher is often fed to a grinder for further reduction. ο The product from an intermediate grinder might pass a 40-mesh screen. ο Most products from a fine grinder would pass a 200- mesh screen with 74 μm opening. ο Reduce the solid size by impact and attrition, sometimes combine with compression Ultrafine grinder ο Reduce solids to fine particles ο Accepts feed particles not larger than 6 mm. ο The product size is typically 1 to 50 μm. ο Reduce the solid size by attrition Cutting machine ο Give particles of definite size and shape 2-10mm in length ο Reduce the size by cutting, dicing and slitting 3. 110 tons/h of trap rock is crushed in a gyratory crusher. The feed is nearly uniform 2-in spheres and produced the product of 0.08 in.size. Using the Bond method, estimate the work necessary for the crushing process. πΜ = 110 π‘ππ/βπ π·ππ = 2 ππ π₯ 25.4 = 50.8ππ π·ππ = 0.08 π₯ 25.4 = 2.032 ππ ππ (π‘πππ ππππ) = 19.32 Thus by using Bonds Law π πΎπ = πΜ √π·π πΎπ = 0.3162 ππΌ π 1 1 = 0.3162 ππΌ ( − ) πΜ √π·ππ √π·ππ π 1 1 = 0.3162 (19.32) ( − ) 110 √2.032 √50.8 π· = πππ. ππ ππΎ