Name __________KEY_______________
Part I: Fill in the table.
Physical Science- Chapter 1 Measurements Review
MEASUREMENT
QUALITATIVE
IS A VERBAL DESCRIPTION OF A
SUBSTANCE
QUANTITATIVE
A MEASUREMENT THAT INCLUDES A
NUMBER
Quantity
Definition
Unit
Equipment
Base/
Derived
Unit
Volume
the amount of space an object takes up
L
mL = cm3
Beaker, graduated
cylinder
B
Mass
The quantity of matter in an object
g
balance
B
thermometer
B
Temperature Measure of the average kinetic energy
(vibration of molecules)
Length
Distance between two points
oC,
m, cm, mm
Meter stick or
metric ruler
B
Time
Duration of an event
sec
stopwatch
B
Energy
The ability to do work or produce heat
calorimeter
B
Density
the ratio of mass to volume (m/ v)
Joules,
calorie
g/ml or
g/cm3
1
K
Graduated
D
cylinder, balance,
ruler
Examples:
 Round
 Hot
 Color
 Shape
 Size (S,
L, M)

Part II: Metric Units
2. Fill in the following chart.
prefix
Kilo
hecto
deca
“Unit”
deci
centi
milli
Unit
k
h
da
Meter,
grams, Liters
d
c
m
mnemonic
KING
HENRY
DRINKS
Unique
DARK CHOCOLATE
MILK
3. Convert the following:
a. 65.20 cm = ____.6520___ m
d. 125.8 dg = ___.01258___kg
b. 0.0573 Mm = _57,300,000 mm
e. 64.9 L = ____.0649____hL
c. 49.68 cg = ___.4968___ g
f. 8.2 dam = _____.082________km
Part III: Density Problems
Problem Solving: For the following problems, you must Show your work and
include all units.
𝑀𝑎𝑠𝑠
Density
=
M
Density Equation
𝑉𝑜𝑙𝑢𝑚𝑒
:
D
V
1. An object has a mass of 35 grams and a volume of 22 cm3. Determine its
density.
Equation: D=m/v
Given: m= 35g v=22cm3
Find: D
D = 35g/22 cm3 = 1.59 g/ cm3
2
2. An object has a density of 11 g/cm3. If its volume is 6.5 cm3, what would be its
mass?
Equation: M = D·V
Given: D=11 g/cm3 V= 6.5 cm3
Find: m
m = (11 g/cm3)( 6.5 cm3) = 71.5 grams
3. A chunk of sulfur has a mass of 36 grams. If the density of sulfur is 2.1 g/cm3,
what would be the chunks volume?
Equation: V = m/D
Given: m=36 grams
Find: V
d=2.1 g/cm3
v = 36 grams/2.1 g/cm3 = 17.14 cm3
4. A cube has a density of 1.25 g/cm3 and has sides of 12 cm, 11 cm and 15 cm.
Calculate the mass of this solid.
Formula/equation to find volume: V= length x width x height
Equation: m= d * v
Given: d=1.25 g/cm3 , 12 cm, 11 cm and 15 cm
Finding: First find V
V = (12 cm) (11 cm)(15 cm) = 1980 cm3
Mass
m= (1.25g/cm3 )x (1980cm3)
5. The volume of water in a graduated cylinder is 150 mL. We drop a marker in,
and the water level rises to 221 mL. What is the volume of the marker?
Equation: displacement equation  final volume – initial volume
Given: initial v= 150mL final v= 221mL
Find: volume of marker
221mL – 150mL = 71mL
3