Name:
Class:
Date:
Midterm Review
Indicate the answer choice that best completes the statement or answers the question.
1. Evaluate the given expression if w = 13, x = 34, y = 42, and z = 26. Round to the nearest hundredth if necessary.
a. 89.04
b. 26.13
c. 13.09
d. 47.06
2. Evaluate the given expression if x = 25, y = 10, w = 35, and z = 1.
a. 575
b. 1575
c. –125
d. 365
3. Name the sets of numbers to which the given number belongs.
a. N, W, Z, R
b. N, W, Z, Q, R
c. N, W, Z, I, R
d. W, Z, R
4. Name the sets of numbers to which the given number belongs.
a. W, Z, R
b. N, W, Z, Q, R
c. N, W, Z, R
d. N, W, Z, I, R
Simplify the given expression.
5. 4(0.6x + 0.2y) + 15(0.4x – 0.8y)
a. 2.4x – 11.9y
b. 8.4 + 12.8y
c. 8.4x + 0.8y
d. 8.4x – 11.2y
Write an algebraic expression to represent the following verbal expression.
6. eight more than the product of a number and 100
a.
b.
c.
d.
7. the cube of the difference of a number and 43
a.
b.
c.
d.
8. the cube of the quotient of a number and 24
a.
b.
c.
d.
Write a verbal expression to represent the given equation.
9.
a. A number is equal to 4 multiplied by the sum of that number and 3.
b. A number divided by 12 is equal to 4 multiplied by the sum of that number and 3.
c. A number divided by 12 is equal to the sum of that number and 3.
d. A number divided by 2 is equal to 4 multiplied by the sum of that number and 3.
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10. Evaluate the given expression if k = –95.
a. 805
b. –45
c. –10
d. 45
Solve the given equation. Check your solution.
11. 5 |2s + 5| = 50
a. {2.5, 7.5}
12. |m – 1| = 21
a. {22, 29}
b. {22.5, –7.5}
b. {–22, –20}
c. {–2.5, –7.5}
c. {22, 20}
d. {2.5, –7.5}
d. {22, –20}
Solve the given inequality. Describe the solution set using the set-builder or interval notation. Then, graph the solution set
on a number line.
13.
a. The solution set is
b.
c.
d.
.
The solution set is
.
The solution set is
.
The solution set is
.
14.
a.
The solution set is
.
b.
The solution set is
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.
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Midterm Review
c.
The solution set is
.
d.
The solution set is
.
15.
a.
b.
c.
d.
The solution set is
.
The solution set is
.
The solution set is
.
The solution set is
.
16.
a.
b.
The solution set is
.
The solution set is
.
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Name:
Class:
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c.
d.
The solution set is
.
The solution set is
.
Mrs. Lobo earns a salary of $50,000 per year plus a 4% commission on her sales. The average price of a share she sells
is $50.
17. Write an inequality to describe about how many shares Mrs. Lobo must sell to make an annual income of at least
$70,000.
a.
b.
c.
d.
Solve the given inequality. Graph the solution set on a number line.
18.
or
a.
b.
c.
d.
19.
and
a.
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b.
c.
d.
20.
a. The solution set is {p | –5 < p < 13}.
b. The solution set is {p | p > –5 or p < 5}.
c. The solution set is {p | p > 13 or p < –5}.
d. The solution set is {p | p > 9 or p < 4}.
21.
a.
The solution set is
or
.
b. The solution set is
or
.
c.
The solution set is
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or
.
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d.
The solution set is
22. If
or
.
what is the value of
Which property is used for calculating
23. Daniel pays $389 in advance on his account at the athletic club. Each time he uses the club, $7 is deducted from the
account. Write a linear function to calculate the value remaining in his account after x visits to the club. Use the linear
function to find the value remaining in the account after 11 visits.
24. A monthly phone bill, , in dollars, consists of a $28 service fee plus $0.14 per minute, , for long distance calls.
Write the amount of the bill as a function of the minutes used. How much will the monthly bill be when 70 minutes of
long distance calls were made in a month?
Find the x-intercept and the y-intercept of the graph of each equation. Then graph the equation.
25.
26. Use the table below to draw a scatter plot and a line of fit.
Indicate the answer choice that best completes the statement or answers the question.
27. Graph the given relation or equation and find the domain and range. Then determine whether the relation or equation
is a function.
(3.3, 5.3), (–1.7, 5.3), (–4.7, 3.3), (–4.7, –2.7)
a.
b.
Domain: {–2.7, 3.3, 5.3}
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Domain: {–4.7, –1.7, 3.3}
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Range: {–4.7, –1.7, 3.3}
The equation is a function.
c.
Range: {–2.7, 3.3, 5.3}
The equation is a function.
d.
Domain: {–4.7, –1.7, 3.3}
Range: {–2.7, 3.3, 5.3}
The equation is not a function.
Domain: {–4.7, 5.3, 3.3}
Range: {–2.7, 3.3, –1.7}
The equation is not a function.
28. Graph the given relation or equation and find the domain and range. Then determine whether the relation or equation
is a function.
(3.2, 5.2), (–1.8, 5.2), (–4.8, 3.2), (–4.8, –2.8)
a.
b.
Domain: {–4.8, 5.2, 3.2}
Range: {–2.8, 3.2, –1.8}
The equation is not a function.
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Domain: {–4.8, –1.8, 3.2}
Range: {–2.8, 3.2, 5.2}
The equation is not a function.
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c.
d.
Domain: {–4.8, –1.8, 3.2}
Range: {–2.8, 3.2, 5.2}
The equation is a function.
Domain: {–2.8, 3.2, 5.2}
Range: {–4.8, –1.8, 3.2}
The equation is a function.
29. Graph the given relation or equation and find the domain and range. Then determine whether the relation or equation
is a function.
a.
b.
The domain is {x | x > 5} and the range is all real
numbers.
The equation represents a function.
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The domain is {x | x < 5} and the range is all real
numbers.
The equation is not a function.
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c.
d.
The domain and the range are all real numbers.
The equation is not a function.
The domain and the range are all real numbers.
The equation represents a function.
30. Find the value of f(–8) and g(8) if f(x) = –7x + 4 and g(x) = 6x + 22x–4.
a. f(–8) = 60
b. f(–8) = –56
g(8) = 48.01
g(8) = –47.99
c. f(–8) = –3
d. f(–8) = 52
g(8) = 70
g(8) = 47.99
31. Find the value of f(8) and g(–3) if f(x) = –3x – 3 and g(x) = 7x2 – 21x.
a. f(8) = –6
b. f(8) = –21
g(–3) = 9
g(–3) = –185
c. f(8) = –27
d. f(8) = 9
g(–3) = 126
g(–3) = 56
32. State whether the given equation or function is linear. Write yes or no. Explain your reasoning.
8x4 + 5y = 11
a. Yes, the equation is in linear form. It is in the form xy = C.
b. Yes, the equation is linear.
c. No, the equation is not linear. It is not in the form Ax + By = C.
d. No, the equation is not linear. It is in the form x + y = c.
33. Write the equation 2y = 15x + 0.1 in standard form. Identify A, B, and C.
a. 20x – 150y = 1 where A = 20, B = –150, and C = –1
b. 20x – 1y = 1 where A = 20, B = –150, and C = 1
c. 150x + 20y = –1 where A = 150, B = 20, and C = 1
d. 150x – 20y = –1 where A = 150, B = –20, and C = –1
34. Write the equation 7y =
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x – 0.5 in standard form. Identify A, B, and C.
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a. 140x + 3y = –10 where A = 140, B = 3, and C = 100
b. 140x – 3y = –10 where A = 140, B = –3, and C = 100
c. 3x – 140y = 10 where A = 3, B = –140, and C = 100
d. 3x + 140y = 10 where A = 3, B = –140, and C = 0.5
35. Find the x-intercept and the y-intercept of the graph of the equation 9x + 16y = 17. Then graph the equation.
a.
b.
The x-intercept is – .
The x-intercept is .
The y-intercept is –
c.
.
The x-intercept is
.
The y-intercept is
.
The y-intercept is
d.
.
The x-intercept is –
.
The y-intercept is –
.
36. The table shows the distance traveled by a truck over different as a function of time. Find the rate of change for the
data.
Time (hr)
Distance (mi)
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2
116
4
232
6
348
8
464
10
580
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a. 116 miles/hour
c. 116 hours/mile
b. 58 miles/hour
d. 58 hours/mile
37. The graph shows the value of a stock (to the nearest dollar) over an 8-hour period. Find the average rate of change in
the stock from hour 5 to hour 7. Round to the nearest cent if necessary.
b. –$1.00/hr
d. –$1.50/hr
a. $1.50/hr
c. $2.00/hr
38. Find the slope of the line that passes through the pair of points (2, 21) and (11, 8).
a.
b.
–
–
c.
d.
39. Write an equation in slope-intercept form for the line that satisfies the following condition.
slope 9 and passes through (2, 22)
a. y = 9x – 22
b. y = 22x – 2
c. y = 22x + 4
d. y = 9x + 4
40. Write an equation in slope-intercept form for the line that satisfies the following condition.
slope and passes through (3, –19)
a. y = 3x –20.5
b.
c.
d.
y = x –19
y = x –20.5
y = –19x +
41. Write an equation in slope-intercept form for the line that satisfies the following condition.
passes through (11, –3), parallel to the graph of y =
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x+4
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a.
c.
b.
y = 3x –
y=
d.
x–
y = 16x +
y=
x+
42. Write an equation in slope-intercept form for the line that satisfies the following condition.
passes through (3, 14), parallel to the line that passes through (10, 2) and (25, 15)
a.
b.
y= x+
y= x+
c.
y=
x+3
d.
y = 13x +
43. Write an equation in slope-intercept form for the line that satisfies the following condition.
passes through (24, –4), perpendicular to the graph of y = x + 17
a.
c.
y=
x+
y= x+
b.
d.
y=
x+
y=
x+(
)
44. Write an equation in slope-intercept form for the line that satisfies the following condition.
passes through (8, 9), perpendicular to the graph of 6x + 12y = 23
a. y = x +
b. y = x –
c. y = 8x +
d. y = 8x + 12
45. The ideal weight (in stones) of people of varying heights is given in the table below. Draw a scatter plot for the data.
Height (meters)
Weight (stones)
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1.52
9.1
1.55
9.5
1.57
9.8
1.60
10
1.63
10.4
1.65
10.8
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a. Graph I
c. Graph III
b. Graph II
d. Graph IV
46. The data below represents the relationship between the total fat (in grams) and the total calories in fast food. Use the
first and fifth ordered pairs shown below to write a prediction equation. Use the prediction equation to predict the missing
value.
Total Fat (grams)
Total Calories
a.
c.
9
260
13
320
; 614.64
; 349.40
21
420
b.
d.
30
530
31
560
35
?
; 914.67
; 650.00
Identify the domain and range of each function.
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47.
a. domain:
range: all real numbers
c. domain:
range:
b. domain: all real numbers
range: all real numbers
d. domain: all real numbers
range:
Write the function shown in the graph.
48.
a.
c.
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b.
d.
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49.
a.
b.
c.
d.
50.
a.
b.
c.
d.
51. Graph the given inequality.
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Date:
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a.
b.
c.
d.
52. Graph the given inequality.
a.
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b.
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Class:
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c.
53. Graph the given inequality.
y≤1–|x|
a.
c.
d.
b.
d.
54. Graph the given inequality.
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Name:
Class:
Date:
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a.
b.
c.
d.
55. Graph the given inequality.
a.
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b.
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c.
d.
56. The table below shows the study times and test scores for a number of students. Create a scatter plot, a line of fit and
describe the correlation for the given data.
57. The table below shows the height of a plant over a given period of time.
a) Draw a scatter plot and a line of fit.
b) Describe the correlation.
c) Use two ordered pairs to write a prediction equation.
d) Use your prediction equation to predict the missing value.
Graph each function. Identify the domain and range.
58.
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Describe the transformation in each function. Then graph the function.
59. y = |x + 2|
60. Julie owns a hair salon and she sells two hair products. She earns a profit of $0.30 per unit when she sells product X
and a profit of $0.40 per unit when she sells product Y. Write and graph an inequality to describe the number of units she
should sell in order to make a profit of at least $120. If she sells 10 units of the hair product X and 24 units of the hair
product Y, will she reach her goal?
Indicate the answer choice that best completes the statement or answers the question.
Graph the system of equations. Then determine whether the system has no solution, one solution, or infinitely many
solutions. If the system has one solution, name it.
61.
a. no solution
b. infinitely many
c. one solution; (–1, 0)
d. one solution; (0, –1)
Use substitution to solve each system of equations.
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62. y = 4x + 22
4x – 6y = –32
a. (–5, 2)
b. (2, –5)
c. (–8, 1)
d. (4, 7)
63. x – 5y = –3
–7x + 8y = –33
a. (2, 7)
b. (–5, 1)
c. (7, 2)
d. (1, –5)
Use the elimination method to solve each system of equations.
64. –2x – 3y = –39
–2x – 6y = –54
a. (5, 12)
b. (12, 5)
c. (6, –1)
d. (–1, 6)
Solve the system of inequalities by graphing.
65. x > 1
y > 10
a.
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b.
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c.
d.
Find the coordinates of the vertices of the figure formed by each system of inequalities.
66. y + x ≥ –4
y≥x–6
3y + x ≤ 10
a. (1, –5), (–14, 8), (–11, 7)
b. (1, 5), (7, 1), (11, 7)
c. (1, 7), (–11, 1), (7, –5)
d. (1, –5), (7, 1), (–11, 7)
Given below are some inequalities. Plot the feasible region graphically.
67.
a.
b.
vertices: (4, –5)
max: f(4, –5) = –1
min: f(4, –5) = –1
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vertices: (4, –5), (4, 0), (–1, –5)
max: f(4, 0) = 4
min: f(–1, –5) = –6
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c.
d.
vertices: (4, –5), (4, 0), (–1, –5)
max: f(4, 0) = 4
min: f(–1, –5) = –6
vertices: (4, –5), (4, 0), (–1, –5)
max: f(4, 0) = 4
min: f(–1, –5) = –6
68.
a.
b.
vertices: (5, –2), (5, 5), (1.5, –2)
max: f(5, 5) = 10
min: f(1.5, –2) = –0.5
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vertices: (5, –2), (5, 5), (1.5, –2)
max: f(5, 5) = 10
min: f(1.5, –2) = –0.5
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c.
d.
vertices: (5, –2), (5, 5), (1.5, –2)
max: f(5, 5) = 10
min: f(1.5, –2) = –0.5
vertices: (5, –2)
max: f(5, –2) = 3
min: f(5, –2) = 3
Perform the indicated matrix operation.
69.
5
8
–3
–2
+
a.
0
8
–6
–10
b.
5
12
2.5
8
–6
–7
–4.5
–6
5
12
2.5
12
–9
–12
–7.5 –11
c.
d.
70.
If A =
–8
10
–4
2
5
8
, find –6A.
a.
b.
48
–60
24
48
–60
24
–12
–30
–48
2
5
8
c.
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d.
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–48
–60
–24
–48
60
–24
–12
–30
–48
12
30
48
Perform the indicated matrix operation.
71.
5
8
–6
+
7
–5
–8
–18
12
–
7
a.
24
b.
21
–74
29
–34
62
50
c.
d.
41
–42
41
–26
34
–10
72. Consider the quadratic function f(x) = –2x2 + 5x – 4. Find the y-intercept and the equation of the axis of symmetry.
a. The y-intercept is 4.
The equation of the axis of symmetry is x =
b.
.
The y-intercept is .
The equation of the axis of symmetry is x = –4.
c. The y-intercept is –4.
The equation of the axis of symmetry is x = .
d.
The y-intercept is
.
The equation of the axis of symmetry is x = 4.
73. Graph the quadratic function
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.
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Name:
Class:
Date:
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a.
b.
c.
d.
Determine whether the given function has a maximum or a minimum value. Then, find the maximum or minimum value of
the function.
74. f(x) = x2 – 6x + 6
a. The function has a maximum value. The maximum value of the function is –3.
b. The function has a maximum value. The maximum value of the function is 33.
c. The function has a minimum value. The minimum value of the function is –3.
d. The function has a minimum value. The minimum value of the function is 33.
Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are
located.
75.
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a.
b.
The solution set is
.
The solution set is
c.
.
d.
The solution set is
.
The solution set is
.
76.
a.
b.
The solution set is
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.
The solution set is
.
Page 27
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c.
d.
The solution set is
.
The solution set is
.
Solve the equation by factoring.
77. x2 + 10x – 24 = 0
a. {–2, 12}
b. {–12, 2}
c. {2, 12}
d. {–2, –12}
78. 4x2 + 7x + 2.5 = 0
a.
b.
{2, }
{
c. {2, 5}
d.
{
,
}
, 5}
Simplify.
79.
a. 14i
b. –7i
c. 7i
d. –7
80. (3i)(–4i)(5i)
a. –60
b. –60i
c. 60i
d. 60
81. i3
a. –i
c. i
b. –1
d. 1
82. (6 + 8i) + (2 – 15i)
a. –9 + 10i
b. 14 – 13i
c. 8 – 7i
d. 8 + 23i
83. (6 – 20i) – (23 – 10i)
a. –43 + 16i
b. –17 – 30i
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c. –17 – 10i
d. 33i – 14i
84. (4 + 8i)(10 – 5i)
a. 40 + 60i – 40i2
b. 40 + 60i + 40
c. 44 + 80i
d. 80 + 60i
85.
a.
c.
+
i
+
i
b.
d.
–
i
–
i
Write the following quadratic function in vertex form. Then, identify the axis of symmetry.
86. y = x2 + 6x – 2
a. The vertex form of the function is y = (x + 3)2 – 11.
The equation of the axis of symmetry is x = –3.
b. The vertex form of the function is y = (x – 3)2 – 11.
The equation of the axis of symmetry is x = –3.
c. The vertex form of the function is y = (x + 3)2 – 11.
The equation of the axis of symmetry is x = –11.
d. The vertex form of the function is y = (x + 3)2 + 11.
The equation of the axis of symmetry is x = –11.
87. y = –3x2 + 42x
a. The vertex form of the function is y = 3(x + 7)2 + 147.
The equation of the axis of symmetry is x = –147.
b. The vertex form of the function is y = (x + 147)2 + 7.
The equation of the axis of symmetry is x = –7.
c. The vertex form of the function is y = –3(x – 7)2 + 147.
The equation of the axis of symmetry is x = 7.
d. The vertex form of the function is y = –3(x + 7)2 + 147.
The equation of the axis of symmetry is x = 147.
88. Graph the quadratic function
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.
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a.
b.
c.
d.
89. Graph the quadratic function
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.
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Name:
Class:
Date:
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a.
b.
c.
d.
90. Graph the quadratic function
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.
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Class:
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a.
b.
c.
d.
Write a quadratic equation with the given roots. Write the equation in the form
integers.
91.
, where a, b, and c are
and –5
a. 4x2 + 17x – 15 = 0
b. 4x2 – 17x + 15 = 0
c. x2 + 17x – 15 = 0
d. x2 + 17x + 15 = 0
Solve the equation by completing the square.
92. x2 – 3x – 10 = 0
a. {–2, 5}
b. {–4, 10}
c. {–4, 5}
d. {–5, 2}
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93. 2x2 + 4x = 0
a. {–4, 0}
c. {0}
b. {0, 2}
d. {–2, 0}
Find the exact solution of the following quadratic equation by using the Quadratic Formula.
94. x2 – 8x = 33
a. {–11, 3}
c. {–6, 22}
b. {33, 41}
d. {–3, 11}
95. –x2 + 11x + 5 = 0
a. {(11
)/–2}
c. {(–11
)/–2}
b. {(–11
)/–2}
d. {(–11
)/–2}
Find the value of the discriminant. Then describe the number and type of roots for the equation.
96. –x2 – 20x + 3 = 0
a. The discriminant is 400. Because the discriminant is greater than 0 and is a perfect square, the two roots are
real and rational.
b. The discriminant is –412. Because the discriminant is less than 0, the two roots are complex.
c. The discriminant is 412. Because the discriminant is greater than 0 and is not a perfect square, the two roots
are real and irrational.
d. The discriminant is –388. Because the discriminant is less than 0, the two roots are complex.
97. x2 – 4x + 6 = 0
a. The discriminant is –40.
Because the discriminant is less than 0, the two roots are complex.
b. The discriminant is 16.
Because the discriminant is greater than 0 and is a perfect square, the two roots are real and rational.
c. The discriminant is –8.
Because the discriminant is less than 0, the two roots are complex.
d. The discriminant is 8.
Because the discriminant is greater than 0 and is a perfect square, the two roots are real and rational.
98. Write an equation for the parabola whose vertex is at (2, 8) and which passes through (4, –3).
a. y = (x + 2)2 – 8
b. y = 2.75(x – 2)2 + 8
c. y = –2.75(x – 2)2 + 8
d. y = –2.75(x + 2)2 – 8
99. Write an equation for the parabola whose vertex is at (3, 6) and which passes through (5, 18).
a. y = 3(x – 3)2 + 6
b. y = (x + 3)2 – 6
c. y = 3(x + 3)2 – 6
d. y = –3(x – 3)2 + 6
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Graph the quadratic inequality.
100.
a.
b.
c.
d.
Solve the inequality.
101. 2x2 + 10x < –12
a. {x |–2 < x –3 }
c. {x |–3 < x < –2 }
102. x2 + 7x > 8
a. {x | x < 8
c. {x | x < 8
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b. {x |
<x<
}
d. {x |
<x<
}
x > –1}
b. {x | x < –8
x > 1}
x > 1}
d. {x | x < –8
x > –1 }
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103. The height of a pebble dropped from a cliff 604 feet high is described by the formula
will the pebble take to reach a height of 348 feet?
. How long
104. A rocket is launched with an initial velocity of 107 feet per second from the top of a cliff 63 feet high. Its height is
described by
. How long will the rocket take to hit the ground?
Indicate the answer choice that best completes the statement or answers the question.
Simplify the given expression. Assume that no variable equals 0.
105. (19x–13y3)(–7xy7)
a. –133x–12y10
c. –133x10y–143
b. –133y10
x12
d. 12y10
x12
106. 13x(5xy13)(–12x–5y9)
a. –780x22y–60
b. 6y22
x3
c. –780x–3y22
d. –780y22
x3
107.
40x10y12
20x5y24
a. 4x10
b.
4x5
y24
c. 4x10y–24
y12
d. 2x5y24
Simplify the given expression.
108. (8x2 + 10x + 18) + (2x2 – 19x – 3)
a. 10x2 + 29x + 21
b. 10x2 + 12x + 15
c. 10x2 – 9x + 15
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d. 27x2 – 9x + 15
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109. (–10x2 – 2x + 20) – (17x2 + 19x – 6)
a. –27x2 – 21x + 14
b. –27x2 – 21x + 26
c. –27x2 – 17x + 26
d. –27x2 – 19x + 14
110. –2xy(6xy3 – 9xy + 7y2)
a. –12x2y4 – 9x2y2 + 7x2y3
c. –12x2y4 + 18x2y2 – 14xy3
b. –12x2y4 + 18xy + 14y2
d. –12x2y4 – 9xy + 7y2
Simplify the expression using long division.
111. (8x2 – 17x + 2) ÷ (x – 2)
a. quotient 8x – 17 and remainder 2
c. quotient 8x – 1 and remainder –4
b. quotient 8x – 1 and remainder 0
d. quotient 8x + 1 and remainder 4
Simplify the expression using synthetic division.
112. (4x3 – 71x2 + 306x – 360) ÷ (x – 12)
a. quotient 4x2 – 119x – 1122 and remainder 13,104
b. quotient 52x2 + 553x – 6,942 and remainder 82,944
c. quotient 4x2 – 23x + 30 and remainder 0
d. quotient 48x2 + 505x + 6,366 and remainder 76,032
Simplify the expression using long division.
113. (8x2 – 37x – 6) ÷ (x – 4)
a. quotient 8x – 5 and remainder –26
c. quotient 8x – 5 and remainder –14
b. quotient 8x – 37 and remainder 4
d. quotient 8x + 5 and remainder 14
Simplify the expression using synthetic division.
114. (7x3 – 91x2 + 224x – 140) ÷ (x – 10)
a. quotient (77x2 + 679x – 7,014) and remainder 70,000
b. quotient (7x2 – 21x + 14) and remainder 0
c. quotient (70x2 + 609x + 6,314) and remainder 63,000
d. quotient (7x2 – 161x – 1386) and remainder 13,720
115. Find p(–3) and p(3) for the function p(x) = 8x4 + 4x3 – 8x2 + 11x + 2.
a. 437; 719
b. –427; 287
c. 481; 697
d. 435; 717
116. Find p(–3) and p(5) for the function p(x) = 7x5 – 7x4 – 6x2 + 11x – 12.
a. –2,323; 17,349
b. –99; –107
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c. –2,355; 17,405
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d. –2,367; 17,393
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Answer Key
1. c
2. a
3. b
4. b
5. d
6. a
7. b
8. c
9. b
10. d
11. d
12. d
13. c
14. c
15. d
16. b
17. a
18. c
19. a
20. a
21. c
22. 5; Associative
23.
24.
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; $312
; $37.80
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25.
26.
27. c
28. b
29. d
30. a
31. c
32. c
33. d
34. c
35. b
36. b
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37. d
38. b
39. d
40. b
41. c
42. a
43. b
44. b
45. a
46. a
47. d
48. d
49. a
50. a
51. c
52. a
53. b
54. b
55. b
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56. positive correlation
57. a)
b) positive correlation
c) Prediction equation using the ordered pairs (3, 4) and (2, 2) is
d) 6 in.
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.
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58.
59. The function represents the translation of the graph of y = |x| left 2 units.
60.
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, where denotes the units of hair product X and denotes the units of hair product Y; No
Page 42
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61. c
62. a
63. c
64. b
65. b
66. d
67. c
68. b
69. a
70. a
71. c
72. c
73. a
74. c
75. b
76. d
77. b
78. b
79. c
80. c
81. a
82. c
83. c
84. d
85. b
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86. a
87. c
88. b
89. c
90. a
91. a
92. a
93. d
94. d
95. d
96. c
97. c
98. c
99. a
100. a
101. c
102. b
103. 4 s
104. 7.2 s
105. b
106. d
107. a
108. c
109. b
110. c
111. b
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112. c
113. a
114. b
115. a
116. d
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