TMcComb L1 Template for Practice Set B

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Practice Exercises
Name__________________________
6.RP.1
Date___________________________
Set B
This is the mixture of paint that Ethan will use to get the shade of green he wants to
paint his bedroom.
1. Describe the relationships between the blue and yellow paint cans in three
different ways using the words ‘for every’.
2. If Ethan uses 6 cans of blue paint, how many cans of yellow paint will he need to
use to yield the same shade of green as his original mixture? Show and explain your
thinking.
3. Nick decided he did not need so much paint, so he thought to himself:
Will his new mixture yield the same shade of green? If not, how can he make the
same shade of green using less total paint? Show and explain your thinking.
Practice Exercises
6.RP.1
Set B
Answer Key
1. This is the mixture of paint that Ethan will use to get the shade of green he
wants to paint his bedroom.
a. Describe the relationship between the blue and yellow paint cans in three
different ways using the words ‘for every’.
For every 2 cans of blue paint there are 4 cans of yellow paint.
For every 4 cans of yellow paint there are 2 cans of blue paint.
There are 2 blue cans for every 6 total cans.
There are 4 yellow cans for every 6 total cans.
b. If Ethan uses 6 cans of blue paint, how many cans of yellow paint will he
need to use to yield the same shade of green as his original mixture? Show
and explain your thinking.
If Ethan uses 6 cans of blue paint he will need 12 cans of yellow paint. I know this
because for every 2 cans of blue there are 4 cans of yellow. If there are 6 blue cans,
there will be three groups of 2 blue cans (6 ÷2 = 3), and so there will need to be
three groups of 4 yellow cans, for a total of 12 yellow cans (4 X 3 = 12).
3. Nick decided he did not need so much paint, so he thought to himself:
Will his new mixture yield the same shade of green? If not, how can he make the
same shade of green using less total paint? Show and explain your thinking.
No, the new mixture will not be the same shade of green. If Ethan buys one less can
of blue paint and one less can of yellow paint, he will then have 3 cans of yellow
paint for every can of blue paint.
The original shade was 2 cans of blue paint for every 6 cans of yellow paint. If Ethan
uses only one can of blue paint, that is half the original amount of blue paint. He
would therefore only need to use half the original amount of yellow paint, or 2 cans
of yellow (4 ÷2 = 2). He can make the same shade of green using less total paint by
mixing 1 can of blue paint and 2 can yellow paint.
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