CHML212 Exp. 13: Calculation, Chromatographic, and Spectral Applications in the Laboratory IN-LAB ASSIGNMENT: (EACH STUDENT will show full calculations listed below for Reaction 1 and Reaction 2 in his/her laboratory notebook in a well organized manner. Full calculation must be shown to receive full credit. Final answer must be clearly indicated with a circle. Yellow carbon copies will be submitted for grading along with Post-Lab assignment.) …..max score = 20 pts. Reaction 1: Acid Catalyzed Dehydration of an Alcohol OH H2SO4(cat) 2-methyl-2-pentanol MW: 102.17 g/mol d: 0.835 g/mL cost: $67.20/12 mL Amount used: 2.0 mL sulfuric acid cost: $25.00/500 mL Amount used: 0.5 mL + H2O + H2SO4 2-methyl-1-pentene MW: 84.16 g/mol d: 0.682 g/mL cost: $129.50/25 mL Product mass: 1.20 g Calculations: a. Theoretical yield based on alcohol b. Percent yield for reaction c. Atom economy d. Experimental atom economy e. “E” product f. Cost per synthesis g. Cost per gram h. Cost per 25 mL bottle i. Adjusted area percent of 2-methyl-1-pentene j. Adjusted area percent of 2-methyl-2-pentanol Reaction #2: Ester Synthesis O O + OH HO acetic acid MW: 60.05 g/mol d: 1.049 g/mL cost: $33.10/500 mL Amount used: 2.0 mL isoamyl alcohol MW: 88.15 g/mol d: 0.809 g/mL cost: $53.60/100 mL Amount used: 2.0 mL Calculations: a. Theoretical yield based on alcohol b. Theoretical yield based on acid c. Percent yield for reaction d. Atom economy e. Experimental atom economy f. “E” product g. Cost per synthesis h. Cost per gram i. Cost per 100 mL bottle j. Adjusted area percent of isoamyl acetate k. Adjusted area percent of isoamyl alcohol H2SO4(cat) sulfuric acid cost: $25.00/500 mL Amount used: 0.5 mL + H2O + H2SO4 O isoamyl acetate MW: 130.18 g/mol d: 0.876 g/mL cost: $64.10/100 mL Product mass: 2.00 g POST-LAB ASSIGNMENT: (EACH LAB GROUP will submit one copy of a typewritten, paragraph style report addressing all of the points listed below based on REACTION 2 only. All tables for BOTH reactions must be completed and copied into the document. Must be written using PAST TENSE, PASSIVE VOICE.) …..max score = 80 pts. Reaction 1: Acid Catalyzed Dehydration of an Alcohol OH H2SO4(cat) 2-methyl-2-pentanol MW: 102.17 g/mol d: 0.835 g/mL cost: $67.20/12 mL Amount used: 2.0 mL sulfuric acid cost: $25.00/500 mL Amount used: 0.5 mL 2-methyl-1-pentene MW: 84.16 g/mol d: 0.682 g/mL cost: $129.50/25 mL Product mass: 1.20 g Table 13.1 Experimental Results Theoretical Yield (g) Actual Yield (g) Percent Yield Table 13.2 Green Chemistry Results Atom Economy (%) Experimental Atom Economy (%) “E” product Cost per Synthesis ($) Cost per Gram ($/g) Cost per 25 mL bottle Table 13.3 GC Results GC Retention Times (min) Standard Sample 2.533 3.054 4.324 Compound methanol 2-methyl-1-pentene 2-methyl-2-pentanol Area Percent Adjusted Area Percent X Table 13.4 1H NMR Spectral Analysis 1a OH 4 5 2 4 5 1b H# 1a 1b 2 (OH) 3 4 5 (ppm) 2.04 2 1a 3 Int. 1 Mult. s H# 1a 1b 2 3 4 5 1b 3 (ppm) 4.66 Int. 4.70 X 1 Mult. 1 X s s X Table 13.5 13C NMR Spectral Analysis 1a OH 4 5 2 4 3 5 1b C# 2 1a (ppm) 1a 1b 2 3 4 5 1b 3 (ppm) 22.34 C# 1a 1b 2 3 4 5 20.91 Table 13.6 IR Spectral Analysis Functional Group Base Values (cm-1) OH stretch C-O stretch sp3 CH stretch sp2 CH stretch C=C stretch 3200-3600 1000-1300 2800-3000 3000-3100 1600-1680 2-methyl-2pentanol Frequency (cm-1) 2-methyl-1pentene Frequency (cm-1) X X X X Table 13.7 Mass Spectral Analysis OH m/z Cation fragment formula Structure m/z Cation fragment formula Structure 102 (M+) Molecular Ion 84 (M+) Molecular Ion 59 (base) Cationic Fragment 69 (base) Cationic Fragment Reaction #2: Ester Synthesis O O H2SO4(cat) OH HO isoamyl alcoholl MW: 88.15 g/mol d: 0.809 g/mL cost: $53.60/100 mL Amount used: 2.0 mL acetic acid MW: 60.05 g/mol d: 1.049 g/mL cost: $33.10/500 mL Amount used: 2.0 mL O sulfuric acid cost: $25.00/500 mL Amount used: 0.5 mL isoamyl acetate MW: 130.18 g/mol d: 0.876 g/mL cost: $64.10/100 mL Product mass: 2.00 g Table 13.8 Experimental Results Theoretical Yield (g) Actual Yield (g) Percent Yield Table 13.9 Green Chemistry Results Atom Economy (%) Experimental Atom Economy (%) “E” product Cost per Synthesis ($) Cost per Gram ($/g) Cost per 100 mL bottle Table 13.10 GC Results GC Retention Times (min) Standard Sample 1.890 2.211 2.748 Compound methanol Isoamyl alcohol Isoamyl acetate Area Percent Adjusted Area Percent Table 13.11 1H NMR Spectral Analysis 6 6 O 3 3 5 6 H# 1 2 (OH) 3 4 5 6 5 OH 4 6 2 (ppm) X 1.57 Int. Mult. H# X 1 X s 1 2 3 4 5 6 O 4 Int. Mult. X X X 6 O 3 3 5 6 C# 1 2 3 4 5 6 4 OH 2 (ppm) X X 5 6 C# 1 2 3 4 5 6 4 1 (ppm) Table 13.12 13C NMR Spectral Analysis 6 2 O 2 (ppm) 1 Table 13.13 IR Spectral Analysis Functional Group Base Values (cm-1) OH stretch C-O stretch sp3 CH stretch C=O stretch 3200-3600 1000-1300 2800-3000 1700-1725 Isoamyl alcohol Frequency (cm-1) Isoamyl acetate Frequency (cm-1) Table 13.14 Mass Spectral Analysis O OH m/z Cation fragment formula O Structure m/z 88 (M+) Molecular Ion 130 (M+) 70 Cationic Fragment 43 (base) Cation fragment formula Cation fragment structure Molecular Ion Cationic Fragment Discussion (Write 1-2 paragraphs including the following.) What was the theoretical yield for this reaction? What was the actual yield? What was the calculated percent yield for this reaction? What was the atom economy for this reaction? What was the experimental atom economy for this reaction? Based on these values, propose one specific way the efficiency of this reaction could be improved. What was the cost per bottle of the product synthesized compared to the manufacturer’s cost? How could the cost of the student’s product be lowered to make it more marketable as compared to the manufacturers? What was the adjusted area % for the product based on GC analysis? Does this indicate that the product was pure or impure? Give names of any compounds which appear in your chromatogram. How can IR spectroscopy be used to differentiate between the reactant and the product in this experiment? Give the identity of one type of absorption and how it could be used to determine whether or not the conversion took place. Include the typical frequency and the actual frequency for this type of bond in your statement. How can NMR spectroscopy be used to differentiate between the reactant and the product in this experiment? Give the identity of one type of proton and how it could be used to determine whether or not the conversion took place. Include the typical chemical shift and the actual chemical shift for this type of proton in your statement. What was the m/z value of the molecular ion of the product based on mass spectrometry? Does this make sense based on the molecular weight of the reactant, and the chemistry which took place? Briefly explain.