Lecture 5: Feb 7th 2011 Reading: Griffiths Chapter 2, Perkins Chapter 2 handed out in class. Homework: Griffiths: 2.2, 2.4, 2.5, Perkins 2.4, Hints for homework See end 1) Details of the Weak interaction Examples: Same types of diagrams as for the other two forces but now the W (not the Z) changes particle types. The weak force involves a large number in interactions with all the quark and leptons since they all have flavor. When determining what sort of interactions are possible or probable the guiding rules are that the interactions should conserve momentum and energy, electric charge and various types of weak flavor when appropriate. Some example interactions are d-> uW- -> ue- anti e: seen for neutrons, n(ddu) -> p(duu) e- antie - -> W- -> e- anite d anti u -> W- -> e- anti e: seen for charged pions - -> e- anti e s -> uW- -> ue- anti e: seen for charged kaons, for K-(s anti u) -> 0(u anit u) e- antie changes generations. Flavor changing between the quark generations can be explained by the idea that the three down type particles d, s, and b and the three up type particles u, c, and t are eigenstates of the strong force, but that the eigenstates of the weak force are slightly different for the down type particles d’, s’ and b’ which can be expressed as a linear combination of the d, s and b strong eigenstates. These coefficients can be summed up in the 3x3 CKM rotation matrix. Consider the b quark. When the b quark is in a meson or baryon coupled to other particles by gluons so it is definitely in a strong eigenstate. Therefore, it is in some superposition of d’, s’, and b’. When it interacts with the W+ it might interact as any of the three with a probability governed by the components of the linier combination it is in (CKM matrix) The W particle would convert b’ to t’ type eigenstates(particles) b(-1/3) -> W- t(2/3) with highest probability, but this decay is forbidden since the t quark is much more massive than the b quark If it interacts as a d’ what you will see is -> W- u or if a s’ what you will see is -> W- c. Therefore there is a finite, but reduced, probability of decaying to a c or a u quark. t is forbidden by energy conservation. According to the CKM matrix constants c is much more likely. This is the only way a particle from second and third generation can decay to the lowest energy generation. These particles all have long lifetime and in fact hadrons with b quarks have very long lifetimes since the b transitions to the other generations have small probabilities. The superposition of b’, s’, d’ for the b quark is mostly b’. The neutral Z particles have scattering and annihilation or pair production interactions much like the photons. Though these interactions can also involve neutrinos. Flavor changing between the generations like B->Zd is not possible for the Z particle. This can be understood mathematically. The W an interaction can be written as <u|WUCKM|s>, where a s strong eigenstate has some probability of being in a d’ weak eigenstate and being converted to a u quark. The matrix U is unitary because it conserves probability. For the Z, <d|U+ZU|s>, where U+ is the complex transform of U. However, U doesn’t act on the Z since it isn’t a quark and U+ZU = Z, and <d|Z|s> has zero probability since d and s are orthogonal eigenstates. The idea of strong vs. weak eigenstates and the CMK matrix is designed to not allow flavor changing by the neutral Z interaction at tree level. These types of interactions were not observed and idea of the strong and weak eigenstates was a simple idea based on the well established concept of having multiple basis’s of eigenstates that would explain why these processes were not observed. Note FCNC, flavor changing neutral currents does happen at higher order at very low probability through higher order diagrams. Note that the weak boson couple to each other also but the interactions are very low probability so you don’t see them very often. They don’t lead to interesting new effects like in QCD. 2) Review Particles and Interactions Particles and charges electron: electric charge -1, weak lepton charge +1e anti electron neutrino: weak lepton charge(flavor) -1e, near 0 mass anti-electron: electron charge +1, weak lepton charge -1e electron neutrino: weak lepton charge(flavor) +1e, near 0 mass 3 generations of leptons: electrons, muons, and taus. 2nd and 3rd generations have substantially more mass charged leptons can’t convert between generation. neutrinos can convert between generations via the non SM process of neutrino mixing. up quark: electric charge +2/3, weak flavor, color r g or b down quark: electric charge -1/3, weak flavor, color r g or b anti up quark: electric charge -2/3, weak flavor, color anti r g or b anti down quark: electric charge +1/3, weak flavor, color anti r g or b 3 generations of quarks c,s and t,b. 2nd and 3rd generations have substantially more mass. Can convert between generations via the weak force with low probability. EM interaction Mediated by massless, electric charge 0 photon. Couples to all particles with electron charge. Infinite range. Can form bound states. Scattering and annihilation/pair production diagrams possible. Strong interaction Mediated by mass less, electric charge 0, bicolored gluon. Gluon can self interact which results in short range nature of force, confinement of quarks, and formation of colorless bound states. Scattering and annihilation/pair production diagrams possible. Weak interaction Mediated by massive W+, W- and Z bosons. Interacts with objects with weak flavor charge and self interacts. No bound states possible. For scattering and annihilation/pair production diagrams possible. For W a large number of diagrams are possible including ones that cross generations. Violates many discreet symmetries that the other forces respect. Coupling constants: Strong s = 1.3 (1.3 at 0.217GeV low energy, 0.3 at 1 GeV mid energy, 0.1 at 100 GeV high energy) EM: = 1/137 Weak W = 10-5 Cross section: Strong 10-30 m2 EM 10-33 Weak 10-44 m2 Lifetime: Strong 10-23 sec EM 10-20 sec Weak 10-8 sec or longer 3) Unification A milestone toward the standard model was the Z particle, the third quanta of the weak force. This particle was neutral and had similar interactions to the electromagnetic force such as e+e- -> Z -> e+e-. However it took a long time to find this particle since no one expected it! Any type of interaction involving the Z had an equivalent higher probability EM interaction, except for the neutrino interactions, which are very difficult to observe. Later it was seen that as you observed interactions such as particle-particle annihilation at higher and higher energies the constants that governed the electromagnetic and weak interactions changed and eventually unified at a high value. At energies well above the Z mass(91 times the proton mass) the mass of the carrier becomes irrelevant to the interaction. This was the first strong hint that there had to be some unifying theory behind all the diverse quantum field theories that had existed. Another way to put this is the both interactions have the same coupling constant and it’s just the extra factor of the mass of the gauge boson in the denominator that makes that gives the difference between the strengths of the interaction. Doing that calculation using the measured strength of the weak and electromagnetic interactions in similar configurations involving photons and Zs gives mZ=91GeV. Exactly what was later measured. Also a milestone for theory since it was predicted before it was found! In addition the strong force is seen to weaken at higher energies so it may also unify. One mystery in this picture is still present. Why do the W and Z have large mass. To explain this you need to introduce an additional field and particle that by coupling with particles can give them mass. This is the Higgs particle. The Higgs may also gives mass to all the other massive particles. In fact the b, s and d states can be considered eigenstates of the Higgs interaction and the strong interaction. As before the b’, s’ and d’ states are still the Weak eigenstates. The Higgs particle interacts with any particle that has mass. Since these particles have mass they are in eigenstates of the Higgs particle (for instance when in a configuration where they have definite mass, such as a hadron). The neutrinos, if they had no mass would be pure eigenstates of the Weak force. But since they do have some mass you can have interactions change lepton flavor generation just like with the quarks. These quantum field theories including the unified electroweak theory with the Higgs particle to explain the mass of the W and Z make up the standard model (SM). 4) New physics The above set of quantum field theories account for every process we have observed and measured in collider experiments. So why would be we interested in new theories of particle physics. The answer is that we have observed a number of phenomena that can’t be explained by the SM. Also the Higgs piece of the SM is undiscovered 0)The Higgs particle - This is the subject of my current research. 1) Neutrinos have mass. Not in original SM. Also why is the scale for neutrino masses so different from the other fermions. 2) Dark matter. Observations of galactic rotation curves, the expansion of the Universe and gravitational lensing indicate that there is some sort of particle out there that doesn’t interact via any of the forces except gravity. This matter would not radiate so we call it dark matter. 3) Dark energy. The universal expansion rate is bigger than expected given the amount of matter and dark matter. Something is pushing it apart. We call this dark energy 4) Why is everything in the Universe made of matter? CP violating processes can result in antimatter decaying slightly more often than matter, but nothing like the observed rate.(A part of my research is investigating CP violating and matter antimatter conversion processes) There are a number of other problems as well that involve the theory, results of calculations, and complexity of the standard model. 1) We would like the forces to unify at high energy. If you try to calculate the strengths of the interaction at very high energies, like those at the big bang, you find that they get very close to each other but don’t match up. 2) Some diagrams in the SM have divergent contributions at high energy. Probabilities greater than 1 or 100%. WW scattering is the main example. 3) Why three generations, why all the masses we observe including such a large range, why the coupling constants we measure and why so complex? 4) Why are some of the coupling constants as large or small as they are. To be precisely the values we observe there has to be a near complete cancelation between some contributions to the observed processes from loop diagrams. This is known as the Hierarchy and/or fine tuning problem. However, even though we know the SM has to be wrong it’s very important to understand it in detail so we can understand how our particle detectors work and when we have seen something new that we need to pursue it to start understanding the new physics. Like Newton’s laws compared to relativity the SM should be considered a valid low energy effective theory consistent with the full theory in the correct energy range. Our particle detectors generally function in this lower energy range. 0) Hints for homework Griffiths 2.4: A key elements in many high energy physics relativity problems is energy and momentum conservation. You should choose a frame, rest frame of a particle or lab frame as appropriate and then equate energy and momentum before and after the process. Also remember that m2 = E2 +p2 and since E = mc2 and p = mv then v = pc2/E = p/E. In almost all cases you can avoid velocity transformations when considering different frames, which can make the problem quite complex. Griffiths 2.5: How likely a process is will be determined by how many vertices there are in the process, what coupling constants are present at each vertex, and whether there are any additional multiplicative factors such as CKM matrix factors which make it less likely to change flavor between generations. The best way to approach a problem like this is to write down the starting and ending quarks on either end of your diagram and then try to figure out what goes on in-between. An interesting example related to the problem is D0 -> pi+pi compared to D0 -> K+K-. We will go over this on Thursday.