Multiple Choice Paper – June 08
UNIT 2 STAGE 1
Question 1 2 3 4 5 6 7 8 9 10
Answer
A D B E A C C D B
A
Question 11 12 13 14 15 16 17 18 19 20
Answer
E
E D E A E A C D D
Question 21 22 23 24 25
Answer
C E
E
E A
5383H/10
Question
Working
(3.4 + 2.1)2  5.7
= 5.5 2  5.7
= 30.25  5.7
1
Answer
Mark
172.425
2
2
(i)
(ii)
120
Corresponding angles
2
3
(a)
–4, (–1), 2, (5), 8
2
(b)
4
2
30
 450
100
135
2
Notes
121
M1 for 5.5 or 30.25 or
4
or 172. (…) seen
6897
A1 for 172.425 or
40
B1 cao
B1 for corresponding angles (or F angles) dep on
120 in (i)
or alternate angles (or Z angles) with angles on
a straight line = 180
or co-interior angles = 180
or any other fully correct reason
B2 for all 3 extra values correct
(B1 for 1 or 2 extra values correct)
for correct straight line for at least 2 ≤ x ≤ 2
(B1ft for at least two “points” correctly plotted)
(SC: if no marks scored in (b) then B1 for a line
of gradient 3 or a line through (0,2) )
30
 450 oe
M1 for
100
or any correct build up method,
ignoring arithmetical errors oe
A1
for 135
B2
(SC: B1 for an answer of
315 or 585)
5383H/10
Question
5
Working
Answer
Mark
(a)
3x – 6
1
B1
for 3x – 6
(b)
11x – 13y
2
B2
for 11x – 13y
(B1 for 11x or
(c)
6
½  12  8  15  0.85
Notes
3
x2
1
B1
612
3
M1 for ½  12  8  15
or 720 seen
M1 (indep) for their volume  0.85
A1 cao
SC:
7
(3  109)  (6  1011)
= 0.5  10–2
–13y seen)
5  10–3
2
B2
3
or 3
provided that answer
x2
x2
is not ambiguous
ie. denominator must be x + 2
for
If no marks scored, an answer of 1224
scores M0 M1 A0
for 5  10–3
(B1 for
0.5  10–2
or
0.005
or
5  10x
½ 10–2
1
or
200
provided x is an integer )
or
5383H/10
Question
8
Working
Answer
Mark
130
2
25
3
180 – 90 –
Notes
M2
for a complete correct method
130
eg 180 – 90 –
oe
2
or ½(360 – 90 – 90 – 130)
or angle BAO marked as 25° on the
diagram or angle BAO worked out as 25°
(M1
for angle OBA or angle OCA = 90o
or angle BOA or angle COA = 65o
or both angles ABC and ACB = 65o
(these could be marked on the diagram
or implied by calculation))
A1 cao
SC
9
6 x 2  3x
3x(2 x  1)

2
4 x  1 (2 x  1)(2 x  1)
3x
2x 1
3
Award M2 A0 for angle A = 50o indicated
on the diagram or implied by the working
or 360 – (90 + 90 + 130 oe) = 50
M1 for 3x(2x + 1)
M1 for (2x – 1)(2x + 1)
A1 cao