Following is the errata for Shigley`s Mechanical Engineering Design

advertisement
Following is the errata for Shigley’s Mechanical Engineering Design, 8th edition. Some
of these corrections will already be reflected in the book, depending if the book came
from the original print run or one of the reprints.
02/06/08
Changes made in the 2nd printing of Shigley’s Mechanical Engineering Design, 8e
Page 159: First line, change “Example 4-8” to “Example 4-9”
Page 276: Equation below Eq. (6-9). Change 2.103 to 2∙103
Page 466: Table 9-1. Third throat case. Change A  0.707h  2b  d  to
A  0.707h  b  d 
Page 831: Equation (16-39). Denominator of last term, change ro2  ri3 to ro2  ri 2
Page 861: Figure 17-1 (a) and (b). Change the dimension
4C 2   D  d  to
2
1
2
4C 2   D  d 
2
Page 865:
(1) In Eqs. (f) and (g) change D to d
(2) In 4th line after Eq. (g) change D to d
(3) Equation (h) should read:
F1  F2 
2T
d
(4) In Fig. 17-7, change D to d (3 places)
Page 866: Change D to d (4 places): Equation below Eq. (i) and Eqs. (17-9) to (17-11)
Page 867: Change D to d (3 places) on fourth line and Fig. 17-8 (2 places)
Page 868: Change D to d in Step 4
Page 872:
(1) Equation (17-13) should read:
12  C /12  w C 2 w
dip 

8Fi
96 Fi
2
(2) Two lines following Eq. (17-13) should read:
where
dip = dip, in
C = center-to-center distance, in
(3) Last line, change 270.6-lb to 270.6 lbf
(4) Last equation should read:
 96  0.393  0.14 in
dip 
2
96  270.6 
(5) Figure 17-11 ©. Change L to C, and d to dip
Page 874: Last equation should read:
C 2 w 16 12  0.0655 10 
dip 

 0.470 in
96 Fi
96  535
2
Page 880: Line after Eq. (17-17). Delete the following term: “, Table 17-12”
Page 908: Problem 17-26. Change item © to read:
© Estimate the allowable horsepower for a 20 000-h life.
Page 914: Figure 18-1. Right view of gear train. Delete the two internal solid horizontal
shaft lines going through gear 2
Page 940: Equation (19-5). Change the braces { } for 3×3 stiffness (k) matrix to square
brackets [ ]
Page 941:
(1) In sentence before Eq. (1) change Eq. (19.5) to Eq. (19-5)
(2) Equation (1). Change the braces { } for 3×3 stiffness matrix to square
brackets [ ]
Page 1041: Problem 9-8. Change 49.2 to 49.7
Changes made in the 3rd printing of Shigley’s Mechanical Engineering Design, 8e
Page 726: In definition of Pd (8th line), change “diameteral” with “diametral”
Page 739: Heading for section 14-11.
(1) 14-11 should not be bold font
(2) Change Km and KH with Km and KH
Page 922:
(1) 7th equation should read:  c  2300
24311.181.21
 161 700 psi
2.67  2  0.1315
(2) Delete lines 6 and 7 “Choose a Grade 1------------, Sc = 110 000 psi.” Replace
with ”Choose Grade 2 carburized and hardened, the same as gear 4”
Page 923:
(1) 3rd equation should read:  c  2300
539.7 1.37 1.19 
 94 000 psi
2.67 1.5 0.1315 
(2) 1st line after 1st four equations, change 200 HB to 300 HB
(3) 2nd line after 1st four equations, change:
“St = 28 000 psi” to “St = 36 000 psi”
“Sc = 90 000 psi” to “Sc = 126 000 psi”
(4) 2nd box, equations for nc and n should read:
nc 
n
126 000  0.9 
 1.21
94 000
 all 36 000  0.9 

 3.77

8584
(5) In last box, for Gear 3 change “200 HB, Sc =90 000 psi and St = 28 000 psi” to
“300 HB, Sc =126 000 psi and St = 36 000 psi”
(6) In last box, for Gear 5 change “Grade 1 through-hardened to 250 HB,
Sc =110 000 psi and St = 31 000 psi” to “Grade 2 carburized and hardened,
Sc =225 000 psi and St = 65 000 psi”
Page 1040: Problem 6-12, change ny = 1.18 to ny = 1.67
Changes for the next (4th) printing of Shigley’s Mechanical Engineering Design, 8e
Page 197: Problem 4-62 should read:
The steel beam ABCD is supported at C as shown and supported at B and D by
steel shoulder bolts each having a diameter of
5
16
in. The lengths of BE and
DF are 2 and 2.5 in, respectively. The beam has a second area moment of
0.050 in4. Prior to loading, the members are stress-free. A force of 500 lbf is
then applied at point A. Using procedure 2 of Sec. 4-10, determine the stresses
in the bolts and the deflections of points A, B, and D. For steel, let E = 30
Mpsi.
Page 278: Example 6-2. The equation for a should read:
0.86  90  
a 
 133.1 kpsi
45
2
Page 361:
(1) 3rd paragraph, last sentence. Change ”Kt = 2.2” to ”Kt = 2.14”
(2) Bottom of page, Table 7-1. In third row, under the column for bending.
Change ”Kt = 2.2” to ”Kt = 2.14”
Page 365:
(1) 2nd equation. Change “(Fig. A-15-18)” to “(Table 7-1)”
(2) 4th equation. Change “(Fig. A-15-19)” to “(Table 7-1)”
Page 865:
(1) Equation (f) change F  to F  2
(2) Equation (g) change F  to F  2
(3) Third line below Eq. (g) change F  to F  2
(4) Figure 17-7, change F  to F  2 in two places
Page 404: Equation (8-8) should read:
 
F
4F
 2
A
 dr
Page 423: Equation (b), change the l in the denominator to 1
Page 470: Table 9-2, third case, change the area to read:
A = 1.414 hb
Page 875: In Fig. 17-12, change F to F  2 in two places
Page 883: In Fig. 17-14, change F to F  2 in two places
Page 997: Case 10, last equation, change yc to yC
(8-8)
Download