The Law of Cosines

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The Law of Cosines
Law of Sines and Cosines
The entire trigonometry that has been done thus far has dealt with the indirect
measurement of sides and angles of right triangles. The calculations were carried out
using Pythagorean Theorem and/or Trigonometric Ratios.
hyp 2  s1 2  s 2 2
sin  
opp
hyp
cos  
adj
hyp
tan  
opp
adj
This process can now be expanded to include oblique triangles. An oblique triangle is one
that has no right angle. The three angles can be acute (all angles less than 900) or one
angle can be obtuse (greater than 900) and the remaining two angles acute. Regardless of
what scenario exists, the measure of unknown angles and the lengths of unknown sides
can be determined by using either the Law of Sines or the Law of Cosines. Let us look
first at the Law of Cosines.
The Law of Cosines can be used to find the length of an unknown side if we know the
length of two sides of the triangle and the measure of the angle they form. This angle is
called the included angle. Knowing two sides and the included angle is referred to as
SAS. Another way to refer to this is a “V”. The lines of the letter “V” represent the sides
and the vertex of the “V” is the included angle. Students can use their fingers to
determine if these measurements are known.
Example 1:
Given ABC with b = 9cm, c = 12cm, and  A = 620, calculate the length of
side ‘a’.
Solution 1:
When the triangle has been sketched, it is obvious that SAS does exist.
To determine the length of side ‘a’ the following formula is used:
a  b 2  c 2  2bcCosA
a
92  122  2912(Cos62 0 )
a  123.5941424
a  11.1cm.
Notice that the lower case letters are used to name the sides of the triangle. These lower
case letters, used for the sides, are those of the corresponding angles. Once the values
have been substituted into the formula, the calculations can be done on the calculator by
typing in exactly what is written under the radical sign.
Example 2:
Given ABC with a = 15m, c = 28m and  B = 1120, calculate the length of
side ‘b’.
Solution 2:
When the triangle has been sketched, it is obvious that SAS does exist.
To determine the length of side ‘b’ the following formula is used:
b  a 2  c 2  2acCosB
b
152  282  21528Cos112 0 
b  1323.669538
b  36.4cm
Notice that the letter of the side that is being calculated only appears once in the formula
and that is for its corresponding angle. The remainder of the formula consists of the
letters of the other two sides – the sum of their squares minus twice their product
times the cosine of the included angle. If this highlighted statement is repeated when
the formula is used in class, the students will adapt it when using the formula themselves.
The Law of Cosines is also used to determine the measure of an unknown angle when the
lengths of all the sides of the triangle are known. This is referred to as SSS. Students
should be reminded of the fact that the longest side of a right triangle, the hypotenuse, is
located opposite the right angle which is the largest angle of the triangle. The same will
follow for an oblique triangle – longest side opposite largest angle and shortest side
opposite smallest angle. This formula for determining the measure of an angle is the
result of solving a 2  b 2  c 2  2bcCosA in terms of CosA.
Example 3: Given ABC with a = 18 cm, b = 21 cm, and c = 27 cm, calculate the
measure of the smallest angle (nearest tenth)
Solution 3:
The shortest side is side ‘a’ which makes  A the
smallest angle. This is the angle we must find.
b2  c2  a2
2bc
2
2
(21)  27 2  18
CosA 
22127 
846
CosA 
1134
CosA  .7640
CosA 
 
cos 1 CosA  cos 1 .7640 
A  41.8 0
Notice that the answer was determined by working with the formula as a fraction –
result of the numerator over result of the denominator. The other option is to use
brackets (numerator) / (denominator). However, students must be very careful
when using the brackets since failure to open and close all brackets will result in an
error. To err on the side of caution, the first option will not result in an error.
Example 4: Given ABC with a = 118 cm, b = 55 cm, and c = 65 cm, calculate the
measure of  A (nearest tenth).
Solution 4:
The triangle was sketched as being
an obtuse triangle because side ‘a’
was much longer than the other two
sides.
b2  c2  a2
2bc
2
2
2
55  65  118
CosA 
25565
 6674
CosA 
7150
CosA  .9334
CosA 
 
cos 1 CosA  cos 1  .9334
A  159 0
CosA is a negative value. This indicates that the angle is greater than 900 since the
cosine function is negative in the second quadrant. 90 0  A  180 0
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