1 Introduction: The stars are huge gas spheres, hundreds of thousands or millions of times more massive than the Earth. A star such as the Sun can go on shining steadily for thousands of millions of years. This is shown by studies of the prehistory of the Earth, which indicate that the energy radiated by the Sun has not changed by much during the last four thousands years. The equilibrium of a star must remain stable for such period. The simplest picture of a star is that of an isolated body of gas sufficiently massive that the only significant forces are self-gravity and internal pressure. In the simplest case, we can assume spherical symmetry and neglect the influence of rotation, magnetic fields and external gravitational influences. Analysis the light of stars, collected from ground-based and orbital telescopes, allows astronomers to determine a variety of quantities related to their outer layers, such as effective temperature, luminosity, and composition. However with the exception of the detection of neutrinos from the Sun and supernova 1987A, no direct way exists to observe the central regions of stars. To deduce the detailed internal structure of stars requires the generation of computer models that are consistent with all known physical laws and that ultimately agree with observable surface features. Despite all of the successes of such calculations, however, numerous questions remain unanswered. The solution of many of these problems requires a more detailed theoretical understanding of the physical processes in operation in the interiors of stars. Mathematically the conditions for the internal equilibrium of a star can be expressed as four differential equations governing the distribution of mass, gas pressure and energy production and transport in the stars. These equations will now be derived. Consider a spherical system of mass M and radius R. Surface: r=R The internal structure of this system is described by the distribution of various quantities, including radius (r), mass M(r) contained within spherical shell of radius r, luminosity r Centre: r=0 X,Y,Z 0,0,Pc,Tc m,l,P,T L(r) passing through spherical shell of radius r, temperature M,L,0,Teff T(r), pressure P(r), and density (r). Although these are expressed as a function of radius r, running from r = 0 at the stellar centre to r = R at the stellar surface, we could have equally chosen a different independent variable, for example mass, M. The problem of stellar structure is to determine the run of these quantities throughout the star, hence we must derive equations relating these quantities throughout the star. 2 3.1) Mass conservation equation (Mass continuity equation) For a spherically symmetric star, consider a shell of mass dM r and thickness dr , located a distance r from the center. Assuming that the shell is sufficiently thin (i.e. dr r ), the volume of the shell is approximately dV 4r 2 dr . If the local density of the gas is ρ, the shell’s mass (mass = volume x density) is given by dM r (4r 2 dr ) . We can write the previous equation as a differential equation: dM r 4r 2 dr (3.1) This is the first fundamental equation of stellar structure, which states how the interior mass of a star must change with distance from the center. Problem 1: Calculate the average density of the Sun. 3.2) Hydrostatic equilibrium equation Stellar evolution is the result of a constant fight against the strong pull of gravity. Because the gravitational force is always attractive, an opposing force must exist if a star is to avoid collapse. This force is provided by pressure. To calculate how the pressure must vary with depth, consider a cylinder of mass dm whose base is located a distance r from the center of a spherical star (Fig 3.3). The areas of the top and bottom of the cylinder are each A and the cylinder’s height is dr . The radial forces acting on the cylinder are: (1) Gravity (inward): Fg = - G M r dm . r2 (3.2) (2) Pressure (net force due to difference in pressure between upper and lower faces): FP ( FP ,b FP ,t ) (3.3) Because the pressure force is always normal to the surface, the force exerted on the top of the cylinder must necessarily be directed toward the center of the star, while the force on the bottom is 3 directed outward. Writing FP , t in terms of FP , b and a correction term dFP that accounts for the change in force due to a change in r results in FP ,t ( FP ,b dFP ) (3.4) The net force due to difference in pressure between upper and lower faces is FP dFP . Applying Newton’s second law ( F ma ) to the cylinder: dm d 2r Fg FP Fg dFP dt 2 (3.5) Pressure is defined as the amount of force per unit area exerted on a surface ( P º F / A ). Allowing for a difference in pressure dP between the top and the bottom of the cylinder due to the different amount of force exerted on each surface dFP AdP . Substituting by the previous equation and Eq. (3.2) into Eq. (3.5) gives dm d 2r GM r dm AdP 2 dt r2 (3.6) Assuming that the density of the cylinder of gas is ρ, its mass is just dm Adr , where Adr is the cylinder’s volume. Using this expression in Eq. (3.6) and dividing both sides by the volume of the cylinder, yields GM r dP d 2r =2 dt r2 dr (3.7) If we assume further that the star is static, then the acceleration must be zero. In this case Eq. (3.7) reduces to dP GM r dr r2 (3.8) dP g , dr where g GM r / r 2 is the local acceleration of gravity at radius r. Equation (3.8) is the condition of hydrostatic equilibrium, and represents the second fundamental equation of stellar structure. Equation (3.8) indicates that: 1- In order for a star to be static, a pressure gradient dP / dr must exist to counteract the force of gravity. It is not the pressure that supports a star, but the change in pressure with radius. 2- Pressure always decrease with increasing radius (outward), the pressure is necessarily larger in the interior than it is near the surface. 4 3- Pressure gradient vanishes at r = 0. 4- Condition at surface of a star: P = 0 (to a good first approximation) If we use enclosed mass as the dependent variable, we can combine these two equations into one: dP dP dr Gm 1 x 2 x dm dr dm r 4r 2 dP Gm dm 4r 4 (3.9) This is an alternate form of hydrostatic equilibrium equation Problem 2: Estimate the central pressure of the Sun using the equation of hydrostatic equilibrium, by considering the whole Sun as one shell. Problem 3: Calculate the pressure at half the solar radius ( R / 2 ). Problem 4: Obtain a very crude estimate of the pressure at the center of the Sun, assume that M = 1 M , r = 1 R and = = 1.41g cm-3 is the average solar density. Assume the surface pressure is exactly zero (compare your result with problems 2&3). Problem 5: Show that the hydrostatic equilibrium, Eq. (3.8), can also be written in terms of the optical depth τ, as dP g = . This form of the equation is often useful in building model stellar d atmosphere. Use the relation between the opacity and the optical depth τ ( d = - dr ). Problem 6: Use hydrostatic equilibrium to compare the centetral pressure of the Sun and (a) B0V star, (b) G0III star, and (c) G0 Iab star (use appendix E). 3.3) Energy generation equation (conservation of energy) To determine the luminosity of a star, it is now necessary to consider all of the energy generated by stellar material. The contribution to the total luminosity due to an infinitesimal mass dm is simply dL = ε dm, where ε is the total energy released per gram per second by all nuclear reactions 5 and by gravity, or ε = εnuclear + εgravity. For a spherically symmetric star, the mass of a thin shell of thickness dr is just dm = 4πr2ρdr. Substituting and dividing by the shell thickness, we have dLr 4r 2 , dr (3.10) where Lr is the interior luminosity due to all of the energy generated within the star interior to the radius r. Equation (3.10) is the third fundamental stellar structure equation, it expresses the conservation of energy which require that energy produced in the star has to be carried to the surface and radiated away. The rate at which energy is produced (Eq. (3.10)) depends on the distance to the center. Essentially all of the energy radiated by the star is produced in the hot and dense core. In the outer layers the energy production is negligible and Lr is almost constant. 3.4) Energy transport equation We have already related the fundamental quantities P, M, and L to independent variable r through differential equations that describe hydrostatic equilibrium, mass conservations, and energy generation, respectively (see Eqs. 3.1, 3.8, and 3.10). However we have not yet found a differential equation relating the basic parameter of temperature, T, to r. Moreover, we have not explicitly developed equations that describe the processes by which energy is carried from the deep interior to the surface of the star. Three different energy transport mechanisms operate in stellar interiors: 1) Radiation allows the energy produced by nuclear reactions and gravitation to be carried to the surface via photons. 2) Convection can be a very efficient transport mechanism in many regions of a star, with buoyant, hot mass elements carrying excess energy outward while cool elements fall inward. 3) Conduction transports heat via collisions between particles. Although conduction can play an important role in some stellar environments (compact stars, white dwarfs and neutron stars, where the mean free path of photons is extremely short), it is generally insignificant in interiors of normal stars, since the electrons carrying the energy can only travel a short distance without colliding with other particles. First consider radiation transport. The gradient in the radiation pressure produces the slight net movement of photons toward the surface that carries the radiative flux, this process is described by dPrad Frad , where Frad is the outward radiative flux, is the average Rosseland mean dr c opacity. The radiation pressure gradient may also be expressed as 6 dPrad 4 3 dT aT . Equating the dr 3 dr two expressions, we have dT 3 Frad . Finally, if we use the expression for the radiative dr 4 ac T 3 flux, written in terms of radiative luminosity of the star at radius r, Frad Lr , the temperature 4r 2 gradient for radiative transport becomes dT 3 Lr dr 4 ac T 3 4r 2 (3.11) This is the fourth stellar structure equation. It gives the temperature change as a function of the radius. It depends on how the energy is transported. ------------------------------------------------------------------------------------------------------------------------Problem 7: Verify that the basic stellar structure equations are satisfied by 1 M๏ STATSTAR model found in Appendix I. This may be done by selecting two adjacent zones and numerically computing the derivates on the left-hand sides of the equations, for example dP dr Pi +1 - Pi , ri +1 - ri and compare your results with results obtained from the right-hand sides using average values of quantities for the two zones [e.g. M r = (M i + M i +1 ) / 2 ]. Carry out your calculations for the two shells at r = 1.27x1010 cm and r = 1.34x1010 cm and then compare your results for the right and left hand sides of each equation by determining relative errors. Note that the model in Appendix I assumes complete ionization everywhere and has the uniform composition X=0.7, Y=0.292, Z=0.008. Your results on the right and left hand sides will not agree exactly because STATSTAR uses a Runge-kutta numerical algorithm that carries out intermediate steps not shown in Appendix I. 7