Chapter 4---Section 1 Definitions and Examples Chapter 4 Linear Transformations In this chapter, we introduce the general concept of linear transformation from a vector space into a vector space. But, we mainly focus on linear transformations from Rn to R m . §1 Definition and Examples New words and phrases Mapping 映射 Linear transformation 线性变换 Linear operator 线性算子 Dilation 扩张 Contraction 收缩 Projection 投影 Reflection 反射 Counterclockwise direction 反时针方向 Clockwise direction 顺时针方向 Image 像 Kernel 核 1.1 Definition ★Definition A mapping (映射) L: VW is a rule that produces a correspondence between two sets of elements such that to each element in the first set there corresponds one and only one element in the second set. ★Definition A mapping L from a vector space V into a vector space W is said to be a linear transformation (线性变换)if Chapter 4---Section 1 Definitions and Examples (1) L(1v1 2 v2 ) 1L(v1 ) 2 L(v2 ) for all v1 , v2 V and for all scalars 1 and 2 . (1) is equivalent to (2) L(v1 v2 ) L(v1 ) L(v 2 ) for any v1 , v2 V (3) L( v) L(v) for any v V and scalar . and Notation: A mapping L from a vector space V into a vector space W is denoted L: VW When W and V are the same vector space, we will refer to a linear transformation L: VV as a linear operator on V. Thus a linear operator is a linear transformation that maps a vector space V into itself. 1.2 Linear Operators on R2 1. Dilations(扩张) and Contractions Let L be the operator defined by L(x)=kx then this is a linear operator. If k is a positive scalar, then the linear operator can be thought of as a stretching or shrinking by a factor of k. k 0 x1 L(x) Ax 0 k x2 2. Projection (投影)onto the coordinate axes. Chapter 4---Section 1 Definitions and Examples L(x)= x1e1 1 0 x1 L(x) Ax 0 0 x2 L(x)= x2 e 2 0 0 x1 L(x) Ax 0 1 x2 3. Reflections (反射) about an axis Let L be the operator defined by L(x)= ( x1 , x2 )T , then it is a linear operator. The operator L has the 1 0 x1 Ax 0 1 x2 effect of reflecting vectors about the x-axis. L(x) Reflecting about the y-axis L(x)= ( x1 , x2 )T , 1 0 x1 L(x) Ax 0 1 x2 4. Rotations L(x)= ( x2 , x1 )T , L has the effect of rotating each vector by 90 degrees in the counterclockwise direction(逆时针方向). 0 1 x1 L(x) Ax 1 0 x2 1.3 Linear Transformations from Rn to Rm If A is an mxn matrix, then we can define a linear transformation LA from Rn to R m by LA ( X ) AX It is easy to verify that the mapping above is linear. In the next section, we will see that any linear transformation from Rn to R m must be of this form. Chapter 4---Section 1 Definitions and Examples 1.4 The Image and Kernel ★ Definition Let L: Rn R m is a linear transformation. The kernel (核)of L denoted ker(L), is defined by ker(L)= v V | L(v) 0W ★Definition Let L: Rn R m is a linear transformation and let S be a subspace of V. The image (像)of S, denoted L(S), is defined by L(S)= w R m | w L(v) for some v R n The image of the entire vector space, L(V), is called the range(值域)of L. Theorem 4.1.1 If L: Rn R m is a linear transformation and S is a subspace of Rn , then (i) ker(L) is a subspace of Rn . (ii) L(S) is a subspace of R m . Assignment for section 1, chapter 4 Hand in: 3, 4, 17, 20, Not required : 8, 10, 11, 15, 16, 19, 25 Chapter 4---Section 2 Matrix Representations §2 Matrix Representations of Linear Transformations New words and phrases Matrix representation 矩阵表示 Formal multiplication 形式乘法 Similarity 相似性 2.1 Matrix Representation of Linear Transformations In section 1 of this chapter, the examples of linear transformations can be represented by matrices. In general, a linear transformation can be represented by a matrix. If we use the basis E=[ u1 , u 2 , F=[ v1 , v2 , , vm ] for V, and , u n ] for U and the basis L: U V. If u is a vector in U, then u x1u1 x2 u 2 xn u n (in U) | L(u) y1v1 y2 v2 ym vm (in V) The linear transformation L is determined by the change of the coordinate vectors: x1 y1 x 2 y2 x n ym Assume that L(u j ) a1 j v1 a2 j v 2 Formally, amj v m , j=1, 2, …, n Chapter 4---Section 2 Matrix Representations , L(u n )] = [v1 , v2 , [ L(u1 ), L(u 2 ), a11 a , vm ] 21 am1 a12 a22 am 2 a1n a2 n amn Write [ L(u1 ), L(u 2 ), , L(u n )] as linear combinations of [v1 , v2 , , vm ] , then consequently, A is obtained. Then L(u) = L( x1u1 x2 u 2 xn u n ) = [v1 , v2 , y1 y , vm ] 2 ym (formal multiplication) x1L(u1 ) x2 L(u 2 ) n xn L(u n ) = x j L(u j ) j=1 [L(u1 ), L(u 2 ), n m j =1 i 1 x1 x , L(u n )] 2 (formal multiplication) xn = x j ( aij vi ) m n i=1 j 1 = ( aij x j )vi = [v1 , v2 , a11 a , vm ] 21 am1 a12 a22 am 2 a1n x1 a2 n x2 amn xn Hence y1 a11 y2 = a21 ym am1 a12 a22 am 2 a1n x1 a2 n x2 amn xn Thus, y=Ax is the coordinate vector of L(u) with respect to F=[ v1 , v2 , , vm ]. y=Ax is called the matrix representation of the linear transformation. A is called the matrix representing L relative to the Chapter 4---Section 2 Matrix Representations bases E and F. A is determined by the following equations. [ L(u1 ), L(u 2 ), , L(u n )] = [v1 , v2 , a11 a , vm ] 21 am1 a12 a22 am 2 a1n a2 n amn We have established the following theorem. Theorem 4.2.2 If E=[ u1 , u 2 , F=[ v1 , v2 , , u n ] is an ordered basis for U and , vm ] is an ordered basis for V, then corresponding to each linear transformation L:UV there is an mxn matrix A such that [ L(u )]F A[u ]E for each u in U. A is the matrix representing L relative to the ordered bases E and F. In fact, a j [ L(u j )]F . 2.2 Matrix Representation of L: Rn R m If U= Rn , V= R m , then we have the following theorem. Theorem 4.2.1 If L is a linear transformation mapping Rn into R m , there is an mxn matrix A such that L(x)=Ax for each x Rn . In fact, the jth column vector of A is given by A ( L(e1 ), L(e2 ), Proof , L(en )) If we choose standard basis [e1 , e2 , , en ] for Rn and the Chapter 4---Section 2 Matrix Representations standard basis [e1 , e 2 , , e m ] for R m , y1 y1 y y , em ) 2 = 2 ym ym L(x)= L( x1e1 x2e2 xnen ) = (e1 , e 2 , x1L ( e1 ) x 2 n L (2e ) xn n = L ( e x j)L(e j ) j=1 (L(e1 ), L(e 2 ), x1 x , L(e n )) 2 xn And let A= aij = a1 , a 2 , , a n (L(e1 ), L(e2 ), , L(en )) If x x1e1 x2e2 xnen , then L(x)=Ax. A is referred to as the standard matrix representation(标准矩阵表示) of L.( A representation with respect to the standard basis.) Example 1 (example 1 on page 186) Determine the standard matrix representation of L. Define the linear transformation L: R3 R2 by L(x) ( x1 x2 , x2 x3 )T for each x ( x1 , x2 , x3 )T in R 3 , find the linear standard representation of L. 1 1 0 0 1 1 Solution: Find L(e1 ), L(e2 ), L(e3 ) . Then A (L(e1 ), L(e2 ), L(e3 )) Example 2 rotation by an angle Let L be the linear transformation operator on R2 that rotates each vector by an angle in the counterclockwise direction. We can see that Chapter 4---Section 2 Matrix Representations e1 is mapped to (cos ,sin )T , and e2 is mapped to ( sin ,cos )T . L(e1 ) (cos ,sin )T , L(e 2 ) (sin , cos )T The matrix A representing the transformation will be cos A (L(e1 ), L(e2 )) sin sin cos To find the matrix representation A for a linear transformation L Rn R m w.r.t. the bases E=[ u1 , u 2 , , u n ] and F=[ b1 , b2 , must represent each vector L(u j ) a1 j b1 a2 j b 2 , b m ], we amj b m . The following theorem shows that determining this representation is equivalent to solving the linear system Bx= L(u j ) , where L(u j ) is regarded as a column vector in R m . Theorem 4.2.3 Let E=[ u1 , u 2 , , u n ] and F=[ b1 , b2 , , b m ] be ordered bases for Rn and R m , respectively. If L: Rn R m is a linear transformation and A is the matrix representing L with respect to E and F, then A B 1 ( L(u1 ), L(u 2 ), where B=( b1 , b2 , , L(u n )) , b m ). Proof L(u) = L( x1u1 x2 u 2 xn u n ) = (b1 , b2 , x1L(u1 ) x2 L(u 2 ) n y1 y , bm ) 2 ym xn L(u n ) = x j L(u j ) j=1 Chapter 4---Section 2 Matrix Representations x1 x , L(u n )) 2 xn (L(u1 ), L(u 2 ), y1 y , bm ) 2 (L(u1 ), L(u 2 ), ym (b1 , b2 , x1 x , L(u n )) 2 xn The matrix B is nonsingular since its column vectors form a basis for R m . Hence, A B 1 ( L(u1 ), L(u 2 ), ( L(u1 ), L(u2 ), [u1 , u 2 , , L(u n )) [e1 ,e2 , ,em ] B B1 [b1 , b2 , , bm ] , L(un )) , un ] A ( L(u1 ), L(u 2 ), [ u1 , u 2 , , L(u n )) is the matrix representing L relative to the bases , u n ] and [ e1 , e2 , , em ]. B is the transition matrix corresponding to the change of basis from [ b1 , b2 , [ e1 , e2 , , b m ] to , em ]. Corollary 4.2.4 If A is the matrix representing the linear transformation L: Rn R m with respect to the bases Chapter 4---Section 2 Matrix Representations E=[ u1 , u 2 , , u n ] and F=[ b1 , b2 , , bm ] then the reduced row echelon form of (b1 , b2 , , bm | L(u1 ), L(u 2 ), , L(u n )) is (I|A) Proof (b1 , b2 , , bm | L(u1 ), L(u 2 ), , L(u n )) =(B|BA), which is row equivalent to (I|A). Examples Finding the matrix representing L Example 3 on page 188 Let L be a linear transformation mapping R3 into R2 defined by L ( x) x1 1 the matrix A representing L with respect to b x 2( x 3 . )Find 2b 1 1 1 1 the ordered bases [e1 , e2 , e3 ] and [b1 , b2 ] , where b1 , b 2 Solution: Method 1. Represent [e1 , e2 , e3 ] in terms of [b1 , b2 ] Method 2. A (b1 ,b 2 )1 ( L(e1 ), L(e 2 ), L(e3 )) 1 1 1 1 1 1 1/ 2 1/ 2 1 1 1 1 0 0 A 1 1 1 1 1 1/ 2 1/ 2 1 1 1 0 1 1 Method 3 Applying row operations. (b1 ,b2 | L(e1 ), L(e2 ), L(e3 )) Example 4 on page 188 Let L be a linear transformation mapping R2 into itself defined by L ( 1b 2b ) ( 1) b 2,2 where b [b1 , b 2 ] is the ordered basis Chapter 4---Section 2 Matrix Representations defined in example 3. Find the matrix A representing L with respect to [b1 , b 2 ] . Solution: Use three methods as in example 3. Example 6 on page 190 Determine the matrix representation of L with respect to the given bases. Let L: R2 R3 be the linear transformation defined by L ( x) x2( x1 , x2 x1, xT 2 ) Find the matrix representation of L with respect to the ordered bases [u1 , u 2 ] and [b1 , b2 , b3 ] , where u1 (1, 2)T , u 2 (3,1)T b1 (1, 0, 0)T , b 2 (1,1, 0)T , b3 (1,1,1)T Assignment for section 2, chapter 4 Hand in: 2, 6, 8, 16, 20 Not required: 9—15, 17, 19 Chapter 4---Section 3 Similarity §3 Similarity Let L be a linear operator on V, E=[ v1 , v2 , , vn ] be an ordered basis for V, A is the matrix representing L with respect to the basis E. u x1 v1 x 2 v2 L(v j ) a1 j v1 a2 j v2 xn nv, L(u) y1v1 y2 v2 anj vn [v1 , v 2 , yn v n a1 j a2 j , v n ] [v1 , v 2 , anj , v n ]a j y=Ax F=[ w1 , w 2 , , wn ] u c1w1 c2 w 2 cn w n , L(u) d1w1 d2 w 2 L(w j ) b1 j w1 b2 j w 2 bnj w n [w1 , w 2 , dn w n b1 j b2 j , w n ] [w1 , w 2 , bnj , w n ]b j d=Bc Let the transition matrix corresponding the change of basis from F=[ w1 , w 2 , , w n ] to [ v1 , v2 , Then x=Sc, y=Sd, S 1 y BS 1x , vn ] y SBS 1x or A SBS 1 Chapter 4---Section 3 Similarity Coordinate vector of u: x Basis E= [v1 , v2 , , vn ] V uL(u) V Coordinate vector of L(u) :y Basis E Ax=y x=Sc S-1 S Coordinate vector of u: c Basis E= [w1 , w 2 , , wn ] V y=Sd uL(u) Bc=d V Coordinate vector of L(u): d Basis F Hence, we have established the following theorem. Theorem 4.3.1 Let E=[ v1 , v2 , , vn ] and F=[ w1 , w 2 , , w n ] be two ordered bases for a vector space V, and let L be a linear operator on Rn . Let S be the transition matrix representing the change from F to E. If A is the matrix representing L with respect to E, and B is the matrix representing L with respect to F, then B S 1 AS . ★Definition Let A and B be nxn matrices. B is said to be similar to A if there is a nonsingular matrix S such that B S 1 AS . Example 2 (on page 204) Example Let L be the linear operator on R3 defined by L(x)=Ax, where Chapter 4---Section 3 Similarity 2 2 0 1 1 2 . 1 1 2 Thus the matrix A represents L with respect to the standard basis for R3 . Find the matrix representing L with respect to the basis [ y1 , y2 ,y3 ], where y1 ( 1, 1T, ,0 y) 2 ( 2,1,1)T , y3 (1,1,1)T . Solution 0 0 0 D= 0 1 0 is the matrix representing L w.r.t the basis 0 0 4 [ y1 , y2 ,y3 ],. Or, we can find D using D Y 1 AY An x (YDY 1 )n x=(YDnY 1 )x Using this example to show that it is desirable to find as simple as a representation as possible for a linear operator. In particular, if the operator can be represented by a diagonal matrix, this is usually preferred representation. It makes the computation of Dx and D n x easier. Assignment for section 3, chapter 4 Hand in: 2, 3, 4, 8, 10, 15 Not required 5, 6