Math 7 A
Fall 2013
NAME ________________________
Show necessary work to receive credit
EXAM 1 (Ch 1, R.8)
Box Your Final Answer
1. Solve by factoring: 6 x  5 
6
x
(6 pts)
2. Solve by completing the square: x 2  6 x  13
2
1
4
 2
 2
3. Solve: 2
k  k  6 k  k  2 k  4k  3
(6 pts)
(15 pts)
LCD: __________________
Restrictions: _______________
x  5  6  7
4. Solve and write the answer in interval notation:
(6 pts)
5. Solve the inequality. Graph the solution set. And write the answer in interval
notation and set-builder notation.
(8 pts)
3x  4  8 and  4 x  1  15
6. Solve: 5 x  6  3x  4  2
7. Simplify: 5 54  2 24  2 96
8. Simplify: i 83
(15 pts)
(8 pts)
(6 pts)
9. Find the real solutions by factoring: 3x x 2  2 x  2  2 x 2  2 x 
3
1
10. Find the real solutions: 3x
4
3
 5x
2
3
2 0
Math 7 A
Spring 2014
0
(15 pts)
(15 pts)
NAME ________________________
Show necessary work to receive credit
1. Solve by factoring:
5
3
 4
x4
x2
2. Solve by completing the square: x 2 
3. Solve:
2
(7 pts)
2
1
x 0
3
3
(7 pts)
3x
5x
2
 2
 2
x  5x  6 x  2 x  3 x  x  2
(15 pts)
2
LCD: __________________
Restrictions: _______________
4. Solve and write the answer in interval notation: 3  x  1 
1
2
(6 pts)
5. Solve the inequality. Graph the solution set. And write the answer in interval
notation and set-builder notation.
(9 pts)
x 4 x  3  2 x  1
2
2x  3  x  1  1
6. Solve:
3
7. Simplify:
(15 pts)
16 x 4 y  3x 3 2 xy  5 3  2 xy 4
1
3 
8. Simplify:  
i 
2
2


(8 pts)
2
(8 pts)
9. Factoring: 3 x 2  4 3  x  4 x 2  4 3  2 x
4
1
10. Find the real solutions: 2 x
2
3
 5x
1
3
(10 pts)
3  0
Math 7 A
Summer 2014
(15 pts)
NAME ________________________
Show necessary work to receive credit
1. Solve by factoring:
5
3
 4
x4
x2
(7 pts)
LCD: _________________
Restrictions:_______________
2. Solve by completing the square: x 2 
3. Solve:
2
1
x 0
3
3
(7 pts)
3x
5x
2
 2
 2
x  5x  6 x  2 x  3 x  x  2
(15 pts)
2
LCD: __________________
Restrictions: _______________
4. Solve and write the answer in interval notation: 3  x  1 
1
2
(6 pts)
5. Solve the inequality. Graph the solution set. And write the answer in interval
notation and set-builder notation.
(9 pts)
3x  4  8 and  4 x  1  15
6. Solve:
7. Simplify:
2x  3  x  1  1
3
(15 pts)
16 x 4 y  3x 3 2 xy  5 3  2 xy 4
1
3 
i 
8. Simplify:  
2
2


(8 pts)
2
(8 pts)
9. Find the real solutions by factoring: 3x x 2  2 x  2  2 x 2  2 x 
1
10. Find the real solutions: 2 x
2
3
 5x
1
3
3  0
3
2
0
(15 pts)
(10 pts)
Math 7 A
Fall 2013
NAME ________________________
Show necessary work to receive credit
2x x 5
  .
3 2 12
1.
Solve:
2.
3.
4.
5.
6.
7.
Solve by factoring: 2 x 2  5 x  3  0 .
Solve by completing the square: 4 x 2  4 x  3 .
Solve: 3x 3  2 x 2  12 x  8  0 .
Solve: x 4  3 x 2  4  0 .
Solve: 3  3x  1  x .
Solve the inequality, expressing the answer in interval notation:
3
8.
3x  4
 6.
2
Solve the absolute value inequality, expressing the answer in interval notation:
3x  4  8 .
9.
Solve the absolute value inequality, expressing the answer in interval notation:
2  2x  5  9 .
10. Write
2
in standard complex form a + bi.
3i
11. The perimeter of a rectangle is 60 meters. Find the length and width if the length
is 8 meters more than the width.
12. The hypotenuse of a right triangle measures 10 centimeters. Find the lengths of
the two legs of the triangle if one leg is 2 centimeters more than the other leg.