Graded Assignment SCI203A: Biology | Unit 3 | Lessons 10 and 11: Laboratory: Determining the Rate of Diffusion Name: Date: Graded Assignment Lab Report Answer the questions below. When you are finished, submit this assignment to your teacher by the due date for full credit. Completing Data Tables (5 points) 1. Look at the sample cube and example data table. Then complete the data tables based on your observations during Parts A and B of the lab. Score Sample Cube Example Data Table: Calculations for Sample Cube Surface Area (SA) Sides 6 Length 4 Width 4 SA for Sample Cube 6 x 4 x 4 = 96 Volume (V) Length 4 Width 4 Height 4 V for Sample Cube 4 x 4 x 4 = 64 Surface Area-toVolume Ratio (SA/V) SA 96 V 64 SA/V for Sample Cube 96/64 = 1.5 Answer: Data Table 1: Calculations for Cube 1 Surface Area (SA) Sides 6 Length 1cm Width 1cm SA for Cube 1 6x1x1=6 Volume (V) Length 1cm Width 1cm Height 1cm V for Cube 1 1x1x1=1 SA V SA/V for Cube 1 Surface Area-toVolume Ratio (SA/V) 6cm © 2006 K12 Inc. All rights reserved. Copying or distributing without K12’s written consent is prohibited. 1cm 6÷1=6 Page 1 of 4 Graded Assignment SCI203A: Biology | Unit 3 | Lessons 10 and 11: Laboratory: Determining the Rate of Diffusion Data Table 2: Calculations for Cube 2 Surface Area (SA) Sides 6 Length 2cm Width 2cm SA for Cube 2 6x2x2=24 Volume (V) Length 2cm Width 2cm Height 2cm V for Cube 2 2x2x2=8 SA V SA/V for Cube 2 Surface Area-toVolume Ratio (SA/V) 24 24÷8=3 8 Data Table 3: Calculations for Cube 3 Surface Area (SA) Sides 6 Length 2.5cm Width 2.5cm SA for Cube 3 6x2.5x2.5=37.5 Volume (V) Length 2.5cm Width 2.5cm Height 2.5cm V for Cube 3 2.5x2.5x2.5=15.625 SA V 15.625 SA/V for Cube 3 37.5÷15.625=2.4cm Surface Area-toVolume Ratio (SA/V) 37.5 Data Table 4: Diffusion Rates Length of Side 1 cm 2 cm 2.5 cm Part A: 5 Minutes Start Time: Finish Time: Distance Vinegar Diffused 2mm 3mm 2.5mm Diffusion Rate (mm/minute) 2÷5=0.4mm/min 3÷5=0.6mm/min 2.5÷5=5mm/min Part B: 10 Minutes Start Time: Finish Time: Distance Vinegar Diffusion Rate Diffused (mm/minute) 10mm 10÷10=1mm/min 4.5mm 4.5÷10=0.45mm/min 3mm 3÷10=0.3mm/min Analysis Questions (4 points) 2. Look at your data tables. List the cubes in order from largest to smallest. Then list them again in order of the surface area-to-volume ratios, from the largest ratio to the smallest ratio. Compare the lists. Score Answer: © 2006 K12 Inc. All rights reserved. Copying or distributing without K12’s written consent is prohibited. Page 2 of 4 Graded Assignment SCI203A: Biology | Unit 3 | Lessons 10 and 11: Laboratory: Determining the Rate of Diffusion Making Graphs (2points) 3. Make a graph of your data, showing the distance vinegar diffused versus the surface area-tovolume ratio. Your graph should plot distance on the vertical axis, and the ratio on the horizontal axis. Plot the points on your graph and connect them with a line. Score Answer: (2points) 4. Make another graph, this time showing the diffusion rate (mm/minute) versus surface area-tovolume ratio. Plot the rate on the vertical axis, and the ratio on the horizontal axis. Score Answer: (2 points) 5. Observe the two graphs you made, and analyze these results. What does the data tell you about connection between the surface area-to-volume ratio and the diffusion rate? Score Answer: ( 8 points) 6. Did the vinegar diffuse all the way to the center of any of the cubes? If so, which ones? What does this tell you about surface area-to-volume ratio and the diffusion rate? Please use the data from the “Diffusion Rate” data table to support your answer. Score Answer: © 2006 K12 Inc. All rights reserved. Copying or distributing without K12’s written consent is prohibited. Page 3 of 4 Graded Assignment SCI203A: Biology | Unit 3 | Lessons 10 and 11: Laboratory: Determining the Rate of Diffusion Concluding Statement (2 points) 7. Using what you have learned in this exercise, write a paragraph applying the concepts. Describe a cell which effectively uses diffusion as a means to move materials in and out. Use this information to suggest how being small helps cells survive, and being made of many small cells helps large organisms maintain homeostasis. Score Answer: Your Score © 2006 K12 Inc. All rights reserved. Copying or distributing without K12’s written consent is prohibited. ___ of 25 Page 4 of 4