Page 22 General Linear Regression Model in Matrix Terms Suppose we have one response variable Y and (p-1) predictor (explanatory) variables X1, X2, . . . , Xp-1, and n observations, so that the dataset looks like the following: X1 X2 . . . Xp-1 Y (random error) X11 X21 X12 . . . X1(p-1) X22 . . . X2(p-1) Y1 Y2 1 1 ………. ….. …. ….. …… ….. …… ………. ….. …. ….. …… ………. ….. …. Xn1 Xn2 . . . Xn(p-1) Yn n b The general linear regression model is given by Yi = 0 + 1Xi1 + 2X12 + . p-1X1(p-1) + . . . i, i = 1, 2, …, n. In matrix terms this becomes Y=X+ where Yi = 0 + 1Xi1 + 2X12 + . p-1X1(p-1) +... i, Y is the vector of n responses Y1, Y2, . . . , Yn X is the n x p matrix with first column all 1’s and the values of X1, X2 , . . .Xp-1 (assumed to be of rank p) is the p x 1 vector of parameters. 0, 1. , . . . , p-1. is an n x 1 vector of uncorrelated errors. 1, 2, . . . , p. The random errors 1, 2, . . . , p are assumed to be independent with mean 0 and common variance 2. For the purpose of making statistical inferences, it is further assumed that the errors are normally distributed. Page 23 Estimation of Parameters. The most commonly used criterion to estimate the parameters in the model is the principle of least squares, which involves minimizing n Q= 2 i = Σ[Yi - 0 - 1Xi1 - 2Xi2 - . p-1Xi(p-1)]2 = (Y = X )′ ( Y = X ) 1 It is easily shown that the value b of which minimizes Q is the solution of the least squares normal equations X′Xb = X′Y which has the solution b = (X′X)-1X′Y Note: If we assume that the errors are normally distributed then the least squares estimator b is also the maximum likelihood estimator of (to be discussed later). Residuals ei are the difference between observed and fitted values and are given by ei = Yi – Yˆi , or in vector form by e = Y – Yˆ = Y – Xb = Y - X(X′X)-1X′Y = [I – X(X′X)-1X′]Y = (I –H)Y where H = X(X′X)-1X′. H is called the ‘hat matrix’ and plays an important role in regression diagnostics (to be discussed below). The resulting minimum value of Q, called the sum of squared errors SSE, is given by SSE = e i2 = (Y- Xb)′(Y –Xb) = Σ(Yi – Yˆi )2 Page 24 The fitted values are given by Yˆ = Xb = X(X′X)-1X′Y = HY This representation of the vector Yˆ of predicted (fitted) values displays directly the relationship between them and the observations. Letting h ij denote the i,jth element of H, the fitted value, we have Yˆi = n h Y ij j 1 j High values of the diagonal elements hij indicate that the observation Yi has a high influence on the fitted value. Example. Two predictors X1 and X2 , n = 4 observations: 1 2 1 3 X= 1 4 1 10 3 3 , Y = , 3 40 0.374 0.303 .123 0.329 0.284 0.013 , 0.284 0.265 0.148 0.013 0.148 .0.961 0.445 0.374 H = 0.303 .123 .0.445 0.329 Diag= 0.265 0.961 The diagonal elements hii measure the influence (leverage) of the individual observations. Both h22 and h44 have very high leverage. For example, Yˆ4 = -0.123 Y1 + 0.013 Y2 + 0.148 Y3 + 0.961 Y4 . Fitted Line Plot y = - 11.56 + 5.013 x S R-Sq R-Sq(adj) 40 Here is a plot of the fitted and observed values: y 30 20 10 0 1 2 3 4 5 6 x 7 8 9 10 5.14750 94.8% 92.3% Page 25 From the graph it is easy to see why the observation Y4 has a large influence (leverage) on its fitted value (and on the fitted regression line as well). Coefficient of Multiple Determination R2. We ask: ‘How much improvement is obtained by using a predictor to obtain fitted (average) values of the response, versus just using the mean y ?’, One answer is the following: Compare the two ways of getting fitted values: 1. Use the average value (sample mean ) of the observations Y , so Yˆ Y and compute SSTO = (Yi Y ) 2 = sum of squared errors of predictions. 2. Use the fitted regression line, getting fitted values Yˆ = ˆ0 ˆ1 x in the simple linear regression model.. Then compute SSE = (Yi Yˆi ) 2 . Compare the sum of squared errors of fitted and observed values for the two methods. Then R2 = (SSTO – SSE)/ SSTO equals the proportionate reduction in the sum of squared errors using the fitted regression line vs. using the sample mean Y . R2.is usually expressed as a percentage reduction. It is also interpreted as the amount of variability in the observations that can be explained (or accounted for) by the predictors. Note that the sample variance of the observations is S y2 = SSTO/ (n-1) and the variance of the residuals using the regression equation is given by MSE = SSE/(n-p). the random errors εi. s = MSE is the estimated standard deviation of It is easily shown that the ‘Total sum of Squares’ SSTO can be decomposed as SST0 = (Yi Y ) = (Yˆi Y ) 2 + 2 (Yi Yˆi ) 2 = SSR + SSE. Page 26 This breakdown of sum of squares can be summarized in an ‘Analysis of Variance’ Table: Source of Sum of df Variation Squares ------------- ---------------------- -----Regression SSR = (Yˆi Y ) 2 p - 1 Error SSE = (Yi Yˆi ) 2 n – p ------------- ---------------------- -----Total SSTO = (Yi Y ) 2 n – 1 MS F-Test -------------------- ------------MSR=SSR/(p-1) MSR/MSE MSE = SSE/(n-p) -------------------- The F-test is used to test the hypothesis that all of the parameters 1, 2., …, p-1 are simultaneously zero. Use the p-value of the test to make a decision on this (this is probably practically not an issue!). Confidence Intervals. Recall (from page 23) that b = (X′X)-1X′Y is the estimated vector of (vector) of parameters . It can be shown that the variance –covariance matrix of b is given by Var-Cov (b) = (X′X)-1σ2 which is estimated by Est. Var-Cov (b) = (X′X)-1MSE The square root of the diagonal elements s(bi) of this matrix are the standard errors of the estimated regression parameters b1, b2., …, bp-1. Confidence intervals for the bi ‘s are then given by bi ± t* s(bi), where t* is a critical value of the t-distribution with n-p df. Tests of hypotheses about individual parameters are conducted using the tdistribution also—refer to the p-values of these tests in regression output. Page 27 Similarly, one can construct confidence intervals for the mean response µnew=E(Ynew) corresponding to a population mean indexed by for values of ' x1, x2., …, xp-1. The mean response is estimated by Ŷnew = X h' b , where X new is the (row) vector of values of x1, x2., …, xp-1. It can be shown that the standard error of the estimated response is given by s.e.( Ŷnew ) = ' X hnew ( X ' X ) 1 X new MSE Model Selection Criteria. If there are (P-1) predictors x1, x2., …, xP-1. one can conceivably fit 2P-1 different models to the data. For example, there are P-1 models with one predictor x1, P(P-1) models with 2 predictors, etc. Some criteria used for comparing models include the following (p as a subscript below refers to the number of predictors in a model): SSEp, R p2 , Ra2, p , Cp , AICp , BICp, and Pressp . These can be described as follows: SSEp or R p2 . Note first that SSEp and R p2 are equivalent measures, in that R p2 = 1 = SSE p SSTO The goal in using either of these statistics is to choose a model where their values are ‘small’. One can plot, e.g., R p2 against p and choose a model, or models, where it is asmptoting (not changing). Ra2, p , is the same measure as R p2 but with an adjustment for sample size. It is given by Ra2, p = 1 MSE (n 1) SSE p = 1 2 p (n p) SSTO Sy where S y2 = SSTO/(n-1) is the sample variance of the observations. Thus, Ra2, p looks at how the ratio of sample variances for the model with p Page 28 predictors changes in comparison with the model with no predictors (a ‘baseline’ model). Cp . This criterion is concerned with the total mean squared error of the n fitted values for each subset selection model. It is a bit complicated to describe here. Suffice to say, most statisticians now prefer to use the BIC criterion. BICp. Schwarz’s Bayesian Information Criterion is given by BICp = n ln SSEp – n ln + [ln n] p We will look at an example using the : SDSS Quasar Sloan Digital Sky Survey team (CASt dataset SDSS_quasar.dat). Here are 8 of the first 10 observations in the dataset (which contains 46420 observations in all). The variables are as follows: Dec. z u_mag g_mag r_mag i_mag z_ mag Radio X-ray J_mag H_mag K_mag M_i 15.30 1.20 19.92 -25.08 13.94 2.24 19.22 -27.42 14.93 0.46 19.64 -22.73 0.04 0.48 18.24 -24.05 14.18 0.95 19.52 -24.57 -8.86 1.25 19.15 -26.06 15.33 0.99 19.41 -24.71 13.77 0.77 19.35 -24.19 19.81 19.39 19.16 19.32 -1.00 -9.00 0.00 0.00 0.00 18.89 18.45 18.33 18.11 -1.00 -9.00 0.00 0.00 0.00 19.47 19.36 19.19 19.00 -1.00 -9.00 0.00 0.00 0.00 17.97 18.03 17.96 17.91 0.00 -1.66 16.65 15.82 14.82 19.28 19.11 19.16 19.07 -1.00 -9.00 0.00 0.00 0.00 18.72 18.26 18.28 18.26 13.97 -9.00 0.00 0.00 0.00 19.18 18.99 19.08 19.13 -1.00 -1.88 0.00 0.00 0.00 19.00 18.92 19.01 18.84 -1.00 -9.00 0.00 0.00 0.00