A2 revision starters & activities Question 1 The light-dependent stage of photosynthesis takes place on the thylakoid membranes in chloroplasts. These membranes surround the thylakoid space (lumen) and are arranged into stacks known as grana. Figure 1a shows the arrangement of photosystems in the thylakoid membrane as well as summarising the processes that occur there. Figure 1a Figure 1a (a) Using the information in Figure 1a explain: (i) why the pH of the thylakoid space (lumen) is lower than that of the stroma (ii) what significance this has for ATP production. [4] (b) Herbicides (weedkillers) interfere with electron transport by accepting electrons. Explain how this causes plants to die. [3] [Total: 7] Sample answer a) i. ii. b) Hydrogen ions are pumped into the thylakoid space as electrons are passed along the electron carriers (G in Figure 1a). This creates a higher concentration of hydrogen ions inside the thylakoid space, which lowers the pH in the lumen. Because of this, the hydrogen ions diffuse down the concentration gradient across the thylakoid membrane from the lumen to stroma through ATP synthetase channels, which in turn generates ATP. So a low pH results in ATP formation. By accepting electrons, weedkillers could prevent production of ATP from chemiosmosis. Also, NADP will not be reduced so no NADPH would be produced. This means that the light-independent stage (Calvin cycle) will not happen, so there will be no fixation of carbon dioxide into sugars or other organic molecules such as fatty acids or amino acids. As a result the plant will die. Examiner’s comments a) This is a Stretch and Challenge question because it requires you to use information from a diagram to bring together related concepts – pH and ATP production. i. Here you should discuss hydrogen ions not H or simply hydrogen. Notice that some of the main terms used in the answer – e.g. thylakoid lumen, stroma, ATP synthetase – are present in Figure 3, so remember to use them to ensure you get all the available marks! Referring to the figure also demonstrates that you are using it as requested in the question. ii. This answer is a good one for Stretch and Challenge as it brings everything together – it relates back to what is being asked for in the question. Remember to always answer the question! You could also gain marks in part (a) for correctly referring to chemiosmosis or to an electrochemical gradient or proton motive force. Examiner’s comments . Here you are not expected to know exactly how weedkillers work – the command word suggest tells you this. However, especially for a Stretch and Challenge question, you should use the information given to put forward a possible reason – but don’t take a wild guess! Notice that the answer to part (b) builds upon your previous answer to part (a). This is a common occurrence in Stretch and Challenge questions and can give you a clue as to where to begin your answer. You can also gain marks in part (b) for mentioning that autotrophic nutrition stops or that no respiratory substrate will be produced – however don’t mention food as in ‘the plant does not produce food’. Note: In the diagram can you identify the pigments P680, P700 and the type of molecule represented by G? These are not Stretch and Challenge elements but core knowledge for revision. Question 2 Figure 4 shows the relationship between various metabolic processes in yeast. Figure 2a In an investigation, yeast cells were homogenised (broken up) and the resulting homogenate centrifuged. Portions containing only nuclei, ribosomes, mitochondria or cytosol (residual cytoplasm) were isolated. Samples of each portion and of the complete homogenate were incubated in four different ways: 1. with glucose. 2. with pyruvate 3. with glucose and cyanide 4. with pyruvate and cyanide. Cyanide inhibits carriers in the electron transport chain such as cytochromes. After incubation, the presence or absence of carbon dioxide and lactate in each sample was determined. The results are summarised in Table 2b below. = absent = present = a little Samples of homogenate Complete Nuclei only Ribosomes only Mitochondria only Cytosol Carbon dioxide Ethanol Carbon dioxide Ethanol Carbon dioxide Ethanol Carbon dioxide Ethanol 1. Glucose 2. Pyruvate 3. Glucose and cyanide 4. Pyruvate and cyanide a) Carbon dioxide Ethanol Suggest why more carbon dioxide is produced when the complete homogenate is incubated with just glucose or pyruvate present than when cyanide is also present [3] The results are summarised in Table 2b below. = absent = present = a little Samples of homogenate Complete Nuclei only Ribosomes only Mitochondria only Cytosol Carbon dioxide Ethanol Carbon dioxide Ethanol Carbon dioxide Ethanol Carbon dioxide Ethanol 1. Glucose 2. Pyruvate 3. Glucose and cyanide 4. Pyruvate and cyanide b) Carbon dioxide Suggest why carbon dioxide is produced when mitochondria are incubated with pyruvate but not when incubated with glucose. Ethanol [3] The results are summarised in Table 2b below. = absent = present = a little Samples of homogenate Complete Nuclei only Ribosomes only Mitochondria only Cytosol Carbon dioxide Ethanol Carbon dioxide Ethanol Carbon dioxide Ethanol Carbon dioxide Ethanol 1. Glucose 2. Pyruvate 3. Glucose and cyanide 4. Pyruvate and cyanide a) Carbon dioxide Ethanol Suggest why ethanol production can still occur in the presence of cyanide. [3] [Total: 9] Sample answer (a) Without cyanide the complete homogenate can break down the glucose/pyruvate fully to produce carbon dioxide. However, when cyanide is present pyruvate does not enter the mitochondria. Cyanide inhibits an enzyme involved in oxidative phosphorylation. It reduces ATP production. If oxidative phosphorylation stops, so does Krebs cycle and link reaction. Some carbon dioxide is produced when pyruvate is converted to ethanal. You could also say that breakdown of the glucose/pyruvate is incomplete. A correct reference to anaerobic respiration will also gain a mark. Sample answer b) Pyruvate is the end product of glycolysis and it can enter mitochondria where carbon dioxide is produced (in the Krebs cycle and the link reaction). Glucose cannot enter the mitochondria, and the enzymes for breaking down glucose are only found in the cytoplasm not in mitochondria. You can also gain a mark for saying that carbon dioxide is produced by decarboxylation or a decarboxylase enzyme. Furthermore, glucose cannot enter mitochondria because there are no carriers for glucose in mitochondrial membrane. Also, glycolytic enzymes are not found in mitochondria but they are found in cytoplasm (cytosol). Sample answer c) Pyruvate is converted to ethanal in cytoplasm and the ethanal is converted to ethanol. The enzymes for these conversions are not inhibited by cyanide. You can gain a mark by using the information in the question that tells you that conversion of pyruvate to ethanol does not involve electron carriers in the electron transport chain, so cyanide will not affect it. Examiner’s comments This question requires some background knowledge of cellular respiration: ribosomes and nuclei are not involved; glycolysis occurs only in the cytoplasm not in mitochondria, etc. However, it is a Stretch and Challenge question since the answers have to be deduced from the table and the information given. For instance, you can deduce from the table that mitochondria can only operate with pyruvate and are affected by cyanide whereas cytosol is not. Note: Some parts of this exam question have been omitted as we are only concentrating on the Stretch and Challenge aspects. The omitted questions were on core concepts in cellular respiration and asked about processes A, B and C. Can you identify and discuss these processes? Stretch and Challenge elements are likely to be included in this way as an extension to sections on recall and core understanding. Note: Some parts of this exam question have been omitted as we are only concentrating on the Stretch and Challenge aspects. The omitted questions were on core concepts in cellular respiration and asked about processes A, B and C. Can you identify and discuss these processes? Stretch and Challenge elements are likely to be included in this way as an extension to sections on recall and core understanding.