


The equivalent mass of MnSO 4 is half of its molecular mass when it is converted into-
1. Mn
2
O
3
2. KMnO
4
3. MnO
2
4. K
2
MnO
4
Answer : - 3 rd option
Mn 2+ →
Mn 4+


1.98 g of Zn displaces 1.92 g of copper from
CuSo4 solution. So the Equivalent mass of Zinc is : - (Equivalent Mass of Cu = 31.8)
1. 32.79
2. 32.3
3. 65.5
4. 63.5
Answer :Option No 1
E=32.79
1.98 = E
1.92 31.8


The element whose atom has a mass of
6.642 x 10 -26 Kg is –
1. Silver
2. Zinc
3. Calcium
4. Boron
Answer:- Option No3
Atomic Mass = Mass of atom x N
4
= 6.642x10
-26 x 6.022x10
23
= 0.040 kg = 40 g
= at Mass of calcium = 40


The number of molecules in 16 g of methane is
1. 3.0 x 10 23
2. 6.022x10
23
3. 16/6.022x 10 23
4.
16
3.0 x 10 23
Answer : - Option No 2
6.022x10
23


19.7 kg of gold was recovered from a smuggler. So the number of atoms of gold recovered is
( At . Mass of Au = 197)
1. 100
2. 6.022x10
23
3. 6.022x10
24
4. 6.022x10
25
Answer : - Option No4


Assuming fully decomposed the volume of CO
2 released at STP when 9.85 g of BaCo
3
( At Mass of Ba=137) will be
1. 0.84L
2. 2.24 L
3. 4.06L
4. 1.12L
Answer : - Option no 4
Baco
3
→
Bao+Co
2
197g
→
22.4 L
9.85g
→
? – 9.85x 22.4
197
= 1.12L


The Indicator used in titrating oxalic acid with caustic soda solution is
1. Methyl Orange
2. Methyl Red
3. phenolphthalein
4. Diphenylamine
Answer : - Option No 3


If a Mixture containing 3 moles of Hydrogen and 1 mole of Nitrogen is converted completely into ammonia, the ratio of initial and final volumes at the same temperature and pressure would be
1. 1:2
2. 2:1
3. 1:3
4. 3:1
Answer : - Option no 2
N
2
+3H
2
→
2NH
3
4: 2 or 2:1


The Molarity of a solution containing 5g of NaoH in 250cm 3 solution is
1. 0.5
2. 0.1
3. 3. 2
4. 4. 1
Answer : - Option No1
M = mass/dm3
G.mol. Mass
20 = 0.5
40


The volume of water to be added to 100cm 3 of
0.5N H
2
SO
4 to get decinormal solution is –
1. 400cm 3
2. 500cm 3
3. 450cm 3
4. 100cm 3
Answer : - Option no 1
N
1
V
1
= N
2
V
2
100x0.5 = V
2 x0.1 i.e. V
2
=500cm 3
Vol of water to be added 500-100= 400cm 3


30g of Magnesium and 30g of oxygen are reacted and the residual mixture contains
1. 60g of Mg only
2. 40g of MgO and 20g of O2
3. 45g of MgO and 15g of O2
4. 50g of MgO and 10g of O2
Answer : - Option number 4
2Mg +O
2
→
2MgO 48g Mg reacts with 32g of O2
48g 32g 2x40g so that 30g Mg, 30x32 = 20g of O2
48
Mass of MgO = 30+20=50
Mass of unreacted O2 = 30 – 20=10


20 cm 3 of 0.05N HCl and 35cm 3 of 0.01N NaOH are mixed. The resulting solution will be-
1. Be Neutral
2. Be basic
3. Turn phenolphthalein into pink
4. Turn methyl orange red
Answer : - Option number 4


When a small amount of FeCl
3 is added to a freshly precipitated Fe(OH)
3
, a reddish brown colloidal solution is obtained. This phenomenon is know as-
1. Dialysis
2. Peptisation
3. Protection
4. Dissolution
Answer : - Option number 2


In the preparation of AgI solution, the excess of potassium iodide solution is added to silver nitrate solution. The colloidal solution will have
1.
Positive charge
2. Negative charge
3. No charge
4. Both positive and negative charge
Answer : - Option No 2


In a colloidal system , total number of phases is/are
1. One
2. Two
3. Three
4. Eight
Answer : - Option number 2


Colloidal particles carry some charge. This can be show by
1. Electrophoresis
2. Dialysis
3. Tyndall effect
4. Brownian Movement.
Answer : - Option no 1


A metallic oxide has formula MO, If the atomic mass of the metal is 24. the Equivalent mass of the metal is
1) 12.
2) 24.
3) 36.
4) 18.
Answer : - Option No1


One mole of H
2
SO
4 in a dm 3 forms
1) 2N Solution.
2) IN Solution.
3) 0.105N Solution.
4) 0.25N Solution.
Answer : - Option No1


The volume of 0.5N NaOH which neutralizes 6.3g of oxalic acid crystals?
1)100cm 3 .
2)20cm 3 .
3)200cm 3 .
4)400cm 3 .
Answer : - Option No3
0.5NxV/1000=6.3/63


Surface tension of hydrophilic sols is?
1) Lower than water. 2) Higher than water.
3) Equal to water. 4) Higher or lower than water.
Answer : - Option No1


Lyophillic sols are more stable than lyophobic sols because?
1) The colloidal particles have positive charge.
2) The colloidal particles have no charge.
3) The colloidal particles are solvated.
4) There is strong electrostatic repulsion.
Answer : - Option No3


Colloidal particles can be separated from those of particles of molecular dimensions by
1) Dialysis.
2) Coagulation
3) Electrophoresis.
4) pyrolysis.
Answer : - Option No 1


An example of micelle is
1) Sodium stearate.
2) Gold sol.
3) Nacl Solution.
4) Ruby Glass.
Answer : - Option No1


Gelatin is mostly used in making ice creams in order to
1) Prevent making of a colloid.
2) Stabilize the colloid and prevent crystallizations.
3) Develop a taste.
4) Enrich the aroma.
Answer : - Option No 2


Cloud bursts due to
1) Attraction towards the electrical charge on the earth.
2) Large amount of water present in the cloud.
3) Dense cloud present in the upper atmosphere.
4) Mutual discharge of oppositely charged clouds resulting in the coagulation.
Answer : - Option No 4


Gold numbers of Gelatin(I), Gum arabic (II), egg albumin (III) are 0.005,0.20 and 0.18 respectively. Arrange these in decreasing order of protective power.
1) I > II > III.
2) I > III > II.
3) II > III > I.
4) III > II > I.
Answer : - Option No 2


Which of the following least effective in causing flocculation of ferric hydroxide sol?
1) K
4
[Fe(CN)
6
]
2) Na
2
CrO
4
3) KBr
4) Na
2 so
4
Answer : - Option No 3


The Method usually employed for the destruction of a colloidal sol is
1) Addition of electrolytes.
2) Diffusion through animal membrane.
3) Condensation
4) Dialysis.
Answer : - Option No 1


Butter is a colloid formed when
1) Fat is dispersed in water.
2) Water is dispersed in fat.
3) Fat globules are dispersed in water and milk.
4) Fat globules are dispersed in water and curds.
Answer : - Option No 2


If the dispersed phase is a liquid and the dispersed medium is solid, the colloid is known as a/an
1) Sol.
2) emulsion.
3) gel.
4) Foam.
Answer : - Option No 3


In case of small cuts, bleeding is stopped by applying potash alum, here alum acts as
1) Fungicide.
2) Disinfectant.
3) Germicide.
4) coagulating agent .
Answer : - Option No 4


The simplest way to check whether a system is colloidal is by
1) Tyndall effect.
2) Brownian movement.
3) Electro dialysis.
4) Finding out particle size.
Answer : - Option No 1


A liquid is found to scatter a light beam but leaves no residue on passing through the filter paper.
1) a suspension.
2) An oil.
3) a colloidal sol.
4) a true solution.
Answer : - Option No 3


Dialysis can separate
1) Glucose and Fructose.
2) Glucose and Sucrose.
3) Glucose and Nacl.
4) Glucose and protein.
Answer : - Option No 4