Aerosol-cloud interaction Anatoli Bogdan Institute of Physical Chemistry, University of Innsbruck Austria and Department of Physics, University of Helsinki Finland Contents - role of aerosol in cloud formation ideal gas vapor pressure and partial vapor pressure Kelvin equation hygroscopic aerosol particles Raoult’s law Kohler curves Cloud condensation nuclei or CCNs or cloud seeds are small particles (typically 0.2 µm, or 1/100 th the size of a cloud droplet) about which cloud droplets coalesce. Water requires a non-gaseous surface to make the transition from a vapor to a liquid. In the atmosphere, this surface presents itself as tiny solid or liquid particles called CCNs. When no CCNs are present, water vapor can be supercooled below 0°C before droplets spontaneously form. At T > 0 ºC, the air would have to be supersaturated to ~400% before the droplets could form. The concept of cloud condensation nuclei has led to the idea of cloud seeding, that tries to encourage rainfall by seeding the air with condensation nuclei. It has further been suggested that creating such nuclei could be used for marine cloud brightening, a geo-engineering technique. Aerosol pollution over Northern India and Bangladesh - NASA http://en.wikipedia.org/wiki/Cloud_condensation_nuclei http://earthobservatory.nasa.gov/Features/Aerosols/ Warm Clouds Warm clouds consist entirely of droplets which have been formed by condensation onto aerosol particles. Aerosol particles respond to changes in humidity in different ways depending on their chemical composition and solubility. Particles which are soluble or hydrophilic take on water as humidity increases and increase in size. Above a certain relative humidity soluble particles will deliquesce – the solid particle dissolves in the water it has taken on and becomes a tiny liquid drop, but not yet a cloud drop. For many soluble salts deliquescence happens at relative humidity around 60 – 80%. These droplets exist in equilibrium with water vapor in the surrounding air. The growth of such particles with increase in relative humidity is expressed by the Köhler equation and is a function of the size and chemical composition of the particle. Prior to the consideration of the Kohler aquation, we will firstly consider several important notions needed for the understanding of the matter. General about gases and vapors Perfect gas Atmosphere is a mixture of gases. Prier to the study of the real atmosphere (a mixture of real gases) we firstly will consider a notion of perfect (ideal) gas. Gas under very small pressure (≤ 1 atm) is a very good approximation of perfect gas. In perfect gas: i) the distance between molecules is much larger than the length of free path of molecules and ii) the interaction between molecules is restricted only to their collisions which are considered to be similar to that of the hard balls. Thus in the perfect gas, the molecules possess only kinetic energy whereas potential energy of interaction between the molecules is absent. As a result internal energy E of perfect gas is independent on pressure and volume, E ≠ E (p, V). Internal energy is determined only by the kinetic motion of molecules and can be easily changed by the addition (or withdrawing) of heat i.e., by changing its temperature. Thus E =E (T). The atmosphere is a mixture of gases including water vapor Vapor pressure of water Above the surface of liquid water there always exists some amount of vapor and consequently there is a vapor pressure. When a container containing water is open then the number of the escaping molecules is larger than the number of molecules coming back from the vaporphase (Fig. 1). In this case water vapor pressure is small and far from saturation. When the container is closed then the water vapor pressure above the surface increases (concentration of molecules increases) and therefore the number of molecules coming back increases too (Fig.2). After a while, the number of molecules escaping the liquid and those coming back becomes equal. Such situation is called by dynamic equilibrium between the escaping and returning molecules (Fig. 3). In this case, the water vapor pressure over the liquid water is called saturated water pressure. Saturated water vapor pressure is a function of temperature only and independent on the presence of other gases. The temperature dependence is exponential. In the case of water vapor, the semi empirical dependence reads as p w ,s e A B C ln T DT T where temperature is in Kelvin and A = 77.34, B = -7235, C = - 8.2, D = 0.005711. 1.3.2 Air humidity Amount of water vapor in the air can be expressed by several different ways: Specific humidity: Mass of water vapor per unit mass of humid air: m H 2O m air Absolute humidity: Mass of water vapor per unit volume of humid air (kg/m3). Relative humidity (RH): Ratio of water vapor pressure pw to the saturated water vapor pressure at that temperature multiplied by 100%, RH = pw p pure s ,w (T ) 100 % . (1.53) Saturation ratio, S: Ratio S = pw p pure s ,w (T ) . (1.54) From the last two definitions we see that RH = S·100% i.e., their physical meanings are almost the same. Supersaturation: S - 1 > 0. For the perfect gas a following (experimental) equation of state p = f (T, V, n) is true pV= nNAkbT, (1.1) where p is pressure, V volume, n number of moles, NA Avogadro number, kb Boltzmann constant, and T temperature in Kelvin. Since kb NA = R (gas constant), for the amount of gas of one mole (n = 1) the equation of state (1.1) can be written as pV = RT. (1.2) Using simple kinetic theory of gases and Newton’s laws of motion, one can show (see, for example, Understanding Physics (1998), p. 249, or Hinds (1982), pp. 15-16) that pV = RT = KE = m mol N 3 2 , (1.3) where KE is kinetic energy of the molecules composing the perfect gas, mmol mass of molecule, N number of molecules, and 2 average of square of molecular velocities (see below). The expression (1.3) means that the kinetic energy KE, which is also the internal energy of the perfect gas E, is independent on pressure, volume or molecular weight and depends only on temperature, i.e. KE = E = E (T), Equations derived for the perfect gas work also in the case of mixture of gases, provided that the individual gases (components of the gaseous mixture) and the mixture itself behave perfectly. Mathematically this means that are valid both: the equations of state for each component of the gaseous mixture i, piV = niRT (1.7) and the equation of state for the mixture itself pV = nRT. (1.8) Dalton’s law for a mixture of perfect gases: The pressure p exerted by a mixture of the perfect gases is the sum of the partial pressures pi of the gases. Mathematically it reads p = ∑ pi. (1.9) Physical meaning of partial pressure: According to the Dalton’s law for the perfect gases, the pressure p exerted by a gaseous mixture is the sum of the partial pressures pi of the gases. In the case of the perfect gases, the partial pressure pi is simply the pressure which the gas would exert if it occupied the container alone at the same temperature. But in the case of the real gases at moderate pressures, the interaction between molecules of different gases makes the total pressure being slightly different (smaller) from the simple sum of the pressures of the gas components if they were alone. Therefore for the real gas, the partial pressure pi of the gas component i in the gaseous mixture is defined as pi = Xi p, (1.15) where p is the total pressure of the mixture.(Compare (1.15) with (1.10)). It follows from Eqs. (1.9) and (1.15) that p = (X1 + X2 + X3 + · · ·) p = p1 + p2 + p3 + · · · = ∑ pi, (1.16) i.e, similar for the mixture of the perfect gases, the sum of the partial pressures of real gases is also equal to the total pressure of the mixture. (But total pressure of the mixture of the perfect gases is not equal to that of the real gases!) Kelvin equation: ps(r)/ ps(∞) = exp ({2 σw}/{ρwRvTr}) = exp (a/r) r = droplet radius ps(r) = the actual vapour pressure of droplet of radius r ps(∞)= the saturation vapour pressure over bulk water σw = surface tension ρw= water density Rv - the universal gas constant, T - temperature Example: Saturation ratio 1 1.1 2 Critical radius 0.12 μm 0.0126 μm 1.73 nm What is going on with soluble aerosol particles, for example, such which are composed of NaCl, sea salt, ammonium sulfate etc. Hygroscopy is the ability of a substance to attract water molecules from the atmosphere through either absorption or adsorption. Hygroscopic substances include sugar, honey, glycerol, ethanol, methanol, sulfuric acid, many salts, and many other substances. Deliquescent materials (mostly salts) have a strong affinity for water. Such materials absorb a large amount of moisture (water vapor) from the atmosphere until it dissolves in the absorbed water and forms an aqueous solution. Deliquescence occurs when the vapour pressure of aqueous solution is smaller than the partial pressure of water in the atmosphere. All soluble salts will deliquesce if the air is sufficiently humid. 1.4.1 Raoult’s law a) Ideal solution: The expression (1.58) shows that the chemical potential of the liquid A in the solution increases with increasing the partial vapor pressure pA and becomes equal to the chemical potential of pure liquid when pA = p*A. The French chemist F. Raoult experimentally found that the ratio of the partial vapor pressure of the component A to its vapor pressure as a pure liquid is approximately equal to the mole fraction XA (see 1.13) in the solution i.e., pA p A X A or pA = XA p*A. (1.60) The Eq. (1.60) is known as the Raoult’s law. The Raoult’s law is valid also for the component B. Linear dependence of the partial vapor pressures pA and pB are shown by the dashed lines in Fig. 6. Fig. 6. Equilibrium partial pressures of the components of ideal and non-ideal binary solution as a function of the mole fraction XA. For the real solution, relationships between the pA, pB, and the mole fractions XA, XB are not linear as it is in the case of ideal solution where the linear relationships are shown by the straight dashed lines LR and KQ. When XA → 1, then we have a dilute solution of B in A. In this region the Raoult’s law pA = XA p*A is applied for the component A. For the component B the Henry’s law pB = KB XB is applied. In the region where XA → 0, we have the Raoult’s law pB = XB p*B for B component and the Henry’s law pA = KA XA for A component. The straight lines LM and KN depict the Henry’s The solutions, which obey the Raoult’s law throughout the whole composition range from pure A to pure B, are called ideal solutions. The solutions, which components are structurally similar, obey the Raoult’s law very well. In Fig. 6, the equilibrium partial pressures of the components A and B in the ideal solution are shown by dashed lines of LR and KQ. Solution is only ideal if is satisfied for each component. Dissimilar liquids (large difference in the liquid structures) significantly depart from the Raoult’s law. Nevertheless, even for these mixtures, the Raoult’s law is obeyed closely for the component in excess as it approaches purity i.e., when XA → 1 or XA → 0 (Fig. 6). Raoult’s law: Mathematically, for a plane water surface the reduction in vapour pressure due to the presence of a non-volatile solute is expressed: p* (∞)/ps(∞) = 1 – (3νmsMw)/(4 πMsρwr3) = 1 - b/r3 where p* (∞) - the saturation vapour pressure of pure water ps* (∞) - the saturation vapour pressure of bulk solution Ms- molecular weight of the solute Ms- mass of the solute Ν- degree of dissociation Combining the Kelvin equation and the expression from the Raoult’s law, we can obtain so called Kohler equation. Köhler Curve = Kelvin equation + Raoult’s law p*(r)/ps(∞) = (1 - b/r3)·exp(a/r) ≈ 1 + a/r - b/r3 where a ~ 3.3 10-7/T [m] b ~ 4.3 10-6i Ms/ms [m3/mol] Ms= molecular mass of salt [kg/mol] ms= mass of salt [kg] The critical radius rc and critical supersaturation Sc are calculated as rc= (3b/a)1/2 and Sc= (4 a3/[27 b])1/2 Kohler curves show how the critical diameter and critical supersaturation are dependent upon the amount of solute. http://en.wikipedia.org/wiki/File:Kohler_curves.png As humidity increases, aerosol continues to swell, even after vapor saturation is reached. Once a critical supersaturation is reached, corresponding to the peak of the Köhler curve for that particle, a particle becomes activated as a cloud droplet. Activated particles are no longer in stable equilibrium with the vapor phase, but are able to continue to grow by vapor deposition provided that conditions remain supersaturated. Droplet size is determined by the number of particles activated and the amount of water vapor available for condensation which is generally determined by the vertical height of an adiabatic ascent. If droplets are able to grow to a sufficient size and the cloud exists for a sufficient length of time droplets will coalesce as they collide with each other through random motion, gravitational settling, or motion within the dynamics of the cloud system.