7_3 graph using intercepts_TROUT09

advertisement

Warm Up #10

1.) Graph 5x + 7y =35

2.) Graph y= 2x -3

Graph 5x + 7y =35

Solve for “y”

7y = -5x +35

Y = -5/7 x + 5

X -values Y= -5/7x +5 Y- values (X, Y)

7 -5/7( 7 )+5 0 (7, 0)

0 -5/7( 0 )+5 5 (0,5)

-7 -5/7 (-7 )+5 10 (-7, 10)

Find 3 points using the table, and graph the line of the equation.

y = 2x - 3

0

1

-1

-1

-3

-5

7.3 Linear Equations and Their

Graphs

Linear Equations

(Graphs are straight lines)

1. Equation is linear only if the each variable has an exponent of “1”.

3 x

1

2. (exponent in denominator is not linear)

3 x

1

3. Products of variables not linear, ie (x)(y) y = 2x + 1 y = x 2 + 1 y – 3x = -7

5y = 14 xy = 2 y

 x

2 y

2 x

-6 -4 -2

A

-1

-2

-3

-4

2

1 y

4

3 x - intercept

B

2 4 y - intercept

X

6

Graphing using Intercepts

1) Let x=0 and determine the y-intercept.

2) Let y=0 and determine the x-intercept

3) Plot both points. Connect them with a line.

Graph

4x + 3y = 12 using intercepts

6

Find x-intercept

4x + 3( 0 ) = 12

4x = 12 x = 3

5

4

3

2

Find y-intercept

4( 0 ) + 3y = 12

3y = 12 y = 4

1

-8 -6 -4 -2 2 4 6 8

-1

-2

-3

-4

-5

-6

Graph

2x + 3y = 12 using intercepts

6

5

4

3

2 x y

0

4

6 0

1

-8 -6 -4 -2 2 4 6 8

-1

-2

-3

-4

-5

-6

Graph

3x + 5y = 15 using intercepts

6

5

4

3

2 x y

0

3

5 0

1

-8 -6 -4 -2 2 4 6 8

-1

-2

-3

-4

-5

-6

Graph

5x - 2y = 10 using intercepts

6

5

4

3

2

1 x y

0 

5

2 0

6 8 -8 -6 -4 -2 2 4

-1

-2

-5

-6

-3

-4

Graph

2y = 3x - 6 using intercepts

6

5

4

3

2 x y

0 

3

2 0

1

-8 -6 -4 -2 2 4 6 8

-1

-2

-3

-4

-5

-6

Horizontal and Vertical Lines

• The graph of y= # is HORIZONTAL

• The graph x =# is VERTICAL

-8

Graph

4y = 16 using 3-points

6

5

4

3

2

1 x y

0

3

6

-6 -4 -2

-1

-2

-3

-4

-5

-6

2 4 6 8

-8

Graph

3x = 18 using 3-points

6

5

4

3

2

1 x y

-6

0

3

- 4

-4 -2

-1

-2

-3

-4

-5

-6

2 4 6 8

Differences between graphing by using a table and graphing by finding the x and y intercepts

• When graphing by a table you need to solve for y (Slope Intercept Form y=mx+b)

• When graphing by finding the x and y intercepts you do not have to solve for y

(Standard Form Ax +By =C)

Assignment

Page 316

( 16 – 42 even and 45-49 all)

Download