Three-phase Circuits Balanced 3-phase systems Unbalanced 3-phase systems SKEE 1043 Circuit Theory Dr. Nik Rumzi Nik Idris 1 Balanced 3-phase systems POWER CALCULATION Instantaneous power Phase voltage of Y connected load with Z per phase: Phase current, lagging by : v AN(t) 2Vp cos(t) ia (t) 2Ip cos(t ) vBN(t) 2Vp cos(t 120o ) ib (t) 2Ip cos(t 120o ) vCN(t) 2Vp cos(t 120o ) ic (t) 2Ip cos(t 120o ) Total instantaneous power: p = vANia + vBNib+ vCNic p(t) 2VpIp [cos(t) cos(t ) cos(t) cos(t 120o ) cos(t) cos(t 120o )] Which can be re-written as: p(t) VpIp [3 cos cos(2t ) cos(2t 240o ) cos(2t 240o )] p(t) 3VpIp cos 2 Balanced 3-phase systems Instantaneous power POWER CALCULATION p(t) 3VpIp cos • Instantaneous power is NON PULSATING • Smoother energy conversion for electrical machine in 3phase system • True for delta () connected load too 3 Balanced 3-phase systems POWER CALCULATION Complex, apparent, active, and reactive Phase voltage Vp Vpv (rms) Phase current Ip Ipi (rms) The complex power per phase: Sp VpIp* VpIp cos jVpIp sin Pp jQp Total complex power: S 3VpIp* 3VpIp For Y connection, Vp VL 3 and Ip IL S 3VLIL Apparent power is as before, i.e. S S 4 Balanced 3-phase systems POWER CALCULATION Power measurement using a wattmeter wattmeter is an instrument used for measuring the average power. The basic structure Equivalent Circuit with load If v(t) = Vmcos (t + v) and i(t) = Imcos (t + i) then the wattmeter will measure the average power: Reading on wattmeter P VmIm cos v i 2 5 Balanced 3-phase systems POWER CALCULATION Power measurement using a wattmeter wattmeter is an instrument used for measuring the average power. 6 Balanced 3-phase systems POWER CALCULATION 3-phase power measurement using wattmeters: two-wattmeter method In order to measure average power in 3-phase system ONLY 2 wattmeters are needed Vcb Z Y Z Y Vca Ic Vcn Vab 30o 30o Van Vbn Ia 30o Vbc Reading by wattmeter1, P1 VabIa cos1 VLIL cos( 30o ) Reading by wattmeter2, P2 VcbIc cos2 VLIL cos( 30o ) 7 Balanced 3-phase systems POWER CALCULATION Reading by wattmeter1, P1 VabIa cos1 VLIL cos( 30o ) Reading by wattmeter2, P2 VcbIc cos2 VLIL cos( 30o ) IT CAN BE SHOWN : P1 P2 3VLIL cos() PTotal P1 P2 P2 P1 VLIL sin() QTotal 3(P2 P1) tan QTotal PTotal • This is also true for a connected load as well • This is also true if the load is unbalanced (ONLY for P1+P2) • Two-wattmeter method CANNOT be used for a 3-phase, 4 wire system UNLESS the neutral current = 0 • P1=P2 resistive load, P2 > P1 inductive load, P2 < P1 capacitive load 8