Vibrations in linear 1-degree of freedom systems; I. undamped systems (last updated 2011-08-26) Kjell Simonsson 1 Aim The aim of this presentation is to give a short review of basic vibration analysis in undamped linear 1 degree-of-freedom (1-dof) systems. For a more comprehensive treatment of the subject, see any book in basic Solid Mechanics or vibration analysis. Kjell Simonsson 2 Linear 1-dof systems A 1-dof system is a simplification of reality, where it has been assumed that the mass of the body/structure • can be associated with one specific small part of the body • is restricted to one "major vibration mode" A typical example of a situation for which a 1-dof assumption is applicable is a slender structure on which a single heavy detail is attached, where the latter mainly moves in one (translational or angular) direction, see below where the movement is depicted in blue. EIL The term linear 1dof-systems, implies that all the governing relations are linear, which e.g. is the case of a linear elastic structure (material linearity), subjected to so small deformations that the ordinary stress and strain measures may be used (geometric linearity). Kjell Simonsson 3 m lateral motion E AL m horizontal motion LG K rotational motion J A simple example Let us study some basic phenomena of linear 1-dof vibration analysis (of un-damped) systems, by considering one of the simple examples shown above! m EIL F F0 sin 0t By making a free body diagram of the (point) mass, we get EIL S S x m F where the coordinate x describes the position of the mass (equal to the deflection of the rod), and where the force S represents the interaction between the rod and the point mass. Elementary solid mechanics now gives : mx S F 3EI 3 mx 3 x F SL x L 3EI Kjell Simonsson 4 A simple example; cont. By introducing the lateral/bending stiffness k, we get mx kx F , k 3EI L3 or, by dividing with m and introducing the complete expression for F x F k x 0 sin 0t m m Thus, the lateral motion of the mass as a function of time is governed by a linear 2'nd order ordinary differential equation with constant coefficients! The solution is given by the sum of the homogeneous solution and the particular solution, x xhom x part , where the former corresponds to the self vibration of the mass caused by the initial conditions (placement and velocity), while the latter is caused by the applied force. Kjell Simonsson 5 A simple example; cont. Homogeneous solution For the homogeneous solution we have k k 0 r i xhom C1ei k / m t C2e i m m k k k k C1 cos t i sin t C2 cos t i sin t m m m m k k C1 C2 cos t iC1 C2 sin t m m r2 A k /m t B As can be seen, for free vibrations with F=0, the point mass can only vibrate with the frequency k / m , which we refer to as the natural frequency or eigenfrequency of the structure. By denoting it e , we get xhom A cos et B sin et , e k / m Kjell Simonsson 6 A simple example; cont. Homogeneous solution; cont. Alternatively we may express this as xhom xhom A B A cos et B sin et X cos et sin et X X cos sin A & B or X & ϕ are found by 1 A X sin et , tan using the initial conditions B Since we in all physical contexts have some kind of damping, i.e. processes that transform the mechanical energy into e.g heat, it follows that the self vibration caused by some initial conditions sooner or later will vanish. Thus, at such a stationary state ("fortvarighet" in Swedish), only the particular solution will remain. It can finally be noted that the circular eigenfrequency fe and the eigenperiod Te are defined as f e e / 2 , Te 1 / f e Kjell Simonsson 7 Resonance Homogeneous solution; cont. We may also analyze the eigenfrequency of a structure/body by the Finite Element method (FEM), see below where an animation of the vibration mode (eigenmode) can be found for a similar type of structure. Kjell Simonsson 8 A simple example; cont. Particular solution For the particular solution we let x part C3 sin 0t F0 sin 0t m F 1 0 2 sin 0t 2 m e 0 02C3 sin 0t e2C3 sin 0t C3 F0 1 m e2 02 x part As can be seen, for forced vibrations the displacement amplitude will depend on how close to the eigenfrequency the applied frequence is. Theoretically, we will get infinite amplitudes for the case 0 e. We refer to this as resonance! Kjell Simonsson 9 A simple example; cont. Particular solution; cont. It may be noted that the particular solution can be recast in another form, as illustrated below x part F0 F0 1 1 sin t 0 m e2 02 m e2 1 2 1 0 e where the factor 1 1 0 e xstat sin0 t 1 1 0 e F , xstat 0 k 2 is the so called dynamic impact factor Kjell Simonsson 10 2 sin0 t Resonance As we saw above, the amplitude of the particular solution goes to infinity when the applied frequency approaches the eigenfrequency of the system. Since the obtained particular solution is not valid for this case (we are not allowed to divide by zero), we instead have to proceed as follows F0 sin et m C4t cos et xpart e2 x part x part F0 d 2 C4 cos et eC4t sin et e C4t cos et sin et dt m eC4 sin et eC4 sin et e2C4t cos et e2C4t cos et F0 F0 eC4 sin et eC4 sin et sin et C4 m 2me x part F0 t cos et 2me Kjell Simonsson 11 F0 sin et m Resonance On the previous slide we found that the amplitude of the forced vibration at resonance grows linearly with time x part x part F0 t cos et 2me i.e. we get the type of behavior illustrated to the right t Even though (as will be seen later on) damping will make the theoretical vibration amplitude finite, it may still be very large near the "resonance" frequency. The same is true for multi-dof systems and continuous systems. As a consequence, all engineering designs must be designed such that they are not operated in a resonance region, since that inevitably will cause premature failure unless additional damping devices are used. Kjell Simonsson 12