4 feet
8 feet
Natasia is planning on repainting one wall in her living
room. As shown in the diagram below, there are two
windows that will not be painted.
Subtract
theof
Find
the area
Living Room
area
of the
the
entire
wall…
Find the area
windows from the
of the windows
area of the
(they will not
entire wall…
3 feet
be painted)…
A  bh
10 feet
Given that the two windows are the exact same size,
what is the total area of the wall that Nasasia plans to
paint?
A  3 4
A  12 sq ft
2 windows 24 sq ft
80 sq ft - 24 sq ft  56 sq ft
A  10 8
A  80 sq ft
Adwin purchased a new door for the front of his house as
shown below. He would like to stain the door using a cherry
wood stain. To determine how much stain to buy, Adwin
first needs to find the area of the door.
The door consist of
a rectangle
measuring 4 ft by
7 ft and a semicircle with a
diameter of 4 feet.
Find the area
of the semicircle…
A


r
3.14 for pi
1
2
A  6.(3.14)(2)
(3.14)(4)
28 sq ft
2
½ since it is
2
How many square feet is thea door?
3.14radius
for  .
semi- Use The
Find the area
of the
rectangle…
A  bh
is half the
diameter.
A  4 7
A  28 sq ft
28  6.28  34.28 sq ft
circle
Adwin also purchased weather stripping to go around the
door. How many feet of weather stripping did he buy?
The door consist of
a rectangle
measuring 4 ft by
7 ft and a semicircle with a
diameter of 4 feet.
Weather stripping
would be the perimeter
of door… (3 sides of
the rectangle and ½
the circumference of
the circle.
C  d
diameter
1
C  (4)(3.14)  6.283.14 for pi
2
½ since it is
a semicircle
7  4  7  6.28  24.28 ft
Mr. McClellan wants to install crown molding around the
edges of his family room. The shape and dimensions of his
family room are shown below.
Label the missing
dimensions…
Calculate
Family Room
12 feet
the
perimeter…
10 feet
10 feet
4 feet
4 feet
2 feet
2 feet
4 feet
Mr. McClellan needs to know the perimeter
of the family room in order to know how much
molding to purchase. What is the perimeter,
in feet, of Mr. McClellan’s family room?
12  10  4  2  4  2  4  10  48 ft
4 8
Amishio would like to repaint the front of his mailbox.
What would be the area that he wants to paint?
3 in
4 in
The front of the mailbox would
consist of a rectangle measuring 8
inches by 3 inches and a semicircle with a diameter of 8 inches.
Find the area
of the semicircle…
Find the area
of the
rectangle…
½ since it is
a semicircle
A r
3.14 for pi
4 9 . 1 2
2
1
A  (3.14)(4)
8 inches
2
A  bh
1
8 inches
A  (3.14)(16)
A  8 3
2
A  24 sq in
A  25.12 sq in
24  25.12  49.12sq in
3 inches
2
The radius
is half the
diameter.