Practice Quiz 3
Hurley 4.3 - 4.7
For the quiz …
I will provide you with a categorical proposition, like…
No apples sold in Minnesota are mushy weapons
I’ll ask you for its
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quality
qualifier
quantity
quantifier
copula
distribution
letter name
terms
1
Consider:
No non-A are B (T) Obversion
a. Some non-A are B. (F)
b. All A are non-B. (Und.)
c. All non-A are non-B. (T)
d. Some non-A are not B. (T)
e. No B are non-A. (T)
2
Consider:
All A are non-B. (F) Contraposition
a. All A are non-B. (F)
b. All non-B are A. (Und.)
c. No non-A are B. (Und.)
d. All B are non-A. (F)
e. Some non-A are not B. (T)
3
Consider:
Some A are not non-B. (T)  Some A are B.
a.Contraposition (T)
b.Contrary (F)
c.Conversion (T)
d.Obversion (T)
e.Subcontrary (Und.)
4
Consider:
Some non-A are B. (F)  Some B are non-A.
a. Subcontrary (T)
b. Conversion (Und.)
c. Contraposition (Und.)
d. Conversion (F)
e. Contraposition (F)
5
Assume Aristotle (Traditional standpoint).
Consider:
Some A are non-B. (F)  Some A are not non-B. (F)
a. Illicit, contrary
b. Illicit, subalternation
c. Subcontrary
d. Illicit, subcontrary
e. Contraposition
6
No S are P. (Aristotelian standpoint)
After filling in the diagram …
a.Area 2 is shaded, and there is a circled X in area
1.
b.Areas 1 and 3 are shaded.
c.Area 1 is shaded, and there is a circled X in area
2.
d.There is an X in area 2.
e.Area 1 is shaded, and there are no other marks.
7
All S are P. (Boolean standpoint)
After filling in the diagram …
a.Areas 1 and 3 are shaded.
b.Area 2 is shaded, and there are no other marks.
c.Area 1 is shaded, and there is a circled X in area
2.
d.There is an X in area 2.
e.Area 1 is shaded, and there are no other marks.
8
Shade area 2 and place an X in area 1.
Which of the following would be valid inferences:
a.shaded area 2.
b.an X in area 3.
c.an X in area 1.
d.shaded 1.
e.no X’s or shadings.
9
Shade area 1 and place an X in area 2.
Which of the following would be valid inferences:
a.shaded area 2.
b.an X in area 3.
c.shaded area 1, and X in area 2.
d.shaded 1.
e.no X’s or shadings.
10
Assume Aristotle (Traditional standpoint).
Consider:
No non-A are B. (T)  Some non-A are not B. (F)
a. Illicit, subalternation
b. Illicit, contradictory
c. Contradictory
d. Illicit, subcontrary
e. Conversion
11
Assume Bool (Modern standpoint).
Consider:
No A are B. (T)  Some A are B. (F)
a. Existential fallacy
b. Illicit, contradictory
c. Contradictory
d. Illicit, subcontrary
e. Conversion
12
Assume Bool (Modern standpoint).
Consider:
No A are B. (T)  All A are B. (F)
a. Existential fallacy
b. Illicit, contrary
c. Contradictory
d. Illicit, subcontrary
e. Conversion
13
Assume Aristotle (Traditional standpoint)
All square circles are happy shapes.
 Some square circles are happy shapes.
a. Existential fallacy
b. Valid, contradictory
c. Valid, subcontrary
d. Invalid, subalternation
e. Invalid, contrary