Axial Force Member Design CE A433 – Spring 2008 T. Bart Quimby, P.E., Ph.D. University of Alaska Anchorage Civil Engineering Tension Members • Members subject to axial tension include truss elements, diaphragm chords, and drag struts. • The basic Design Inequality is: ASD: ft < F’t Ta/An < Ft CDCMCF LRFD: Tu < fT’n Tu < f KFFt lCMCF An An: Net Area • Net Area accounts for loss of area due to holes and other cuts in the member. • Net Area is the gross area less the area of any grain that is cut. • There is no account for stagger. Compression Members • Members subject to axial compression include columns, studs, truss elements, diaphragm chords, and drag struts. • The basic Design Inequality is: ASD: fc < F’c Pa/A < Fc CDCMCFCP LRFD: Pu < fP’n Pu < f KFFt lCMCFCP A A: Area • In Buckling Region – A = Gross Area, Ag • In Non-Buckling Regions (i.e. near ends in most cases) – A = Net Area, An CP: Column Stability Factor • Applies only to compressive stress, Fc • Applies to both Sawn Lumber and Glulams • Found in NDS 3.7.1 – This factor accounts for instability in laterally unsupported columns (i.e. column buckling) – Different in each principle direction More CP • See NDS Equation 3.7-1 • Column buckling is a function of the laterally unbraced (buckling) length, le, and cross section properties (Moment of Inertia, Ie, and Area, A) and is different in each principle cross section direction. • First check the slenderness ratio – le/d must not exceed 50 • Then compute CP • Note that CP is a function of the member size! – This means that you must know the member size before computing this factor – When designing, this dependency leads to iterative computations Laterally Unbraced Length, lu • This is the distance between locations of lateral support in the Weak Axis plane of buckling Buckling • Most members have Strong Axis two principle Buckling directions and lu is frequently different in each direction. le: Effective Length • Effective length is a function of the laterally unbraced length and the end conditions. • Most timber connections are considered to be pinned. Effective Length Coefficients From AISC Steel Construction Manual Slenderness • NDS 3.7.1.4 • The slenderness ratio le/d must not exceed 50 – luy1/d1, luy2/d1 – lux1/d2 Computing CP • NDS Equation 3.7-1 • Accounts for buckling and material strengths Material Strength Euler Strength Combined Bending & Axial Force NDS 3.9 Combined Axial Force and Bending • Both axial force and bending create normal stresses on a cross section. stotal, x,y = saxial + sbending-x + sbending-y sx,y = P/A + Mxy/Ix + Myx/Iy • The result is a planar equation across the section. Allowable Composite Stress • Note that each stress component has a DIFFERENT allowable stress, so the limiting value of the combined stress needs to be a composite of the individual allowable stresses. saxial < saxial,allowable sbending-x < sbending-x,allowable sbending-y < sbending-y,allowable scombined < scombined,allowable Combining Allowable Stress • These can be rewritten as the following ratios: saxial / saxial,allowable < 1.00 sbending-x / sbending-x,allowable < 1.00 sbending-y / sbending-y,allowable < 1.00 • In each case, the ratio goes to 1.0 as the normal stress approaches it’s allowable Interaction Equation • Instead of finding a composite allowable stress, we can combine the stress ratios saxial / sa,allow + sbx / sbx,allow + sby / sby,allow < 1.00 • Most combined stress and combined force equations used in structural engineering use this form. Second Order Effects • Secondary moments are created with axial force is applied to an already bent member. • See text in A Beginner’s Guide to the Steel Construction Manual, section 10.3 for more explanation about second order effects. • Second order effects are ignored in combined tension and bending • Second order effects can be very significant in combined compression and bending Bending & Axial Tension • NDS 3.9.1 • Both interaction equations must be satisfied. Bending & Axial Compression • NDS 3.9.2 • Moments are “magnified” by the factors M1 1 f c FcE1 M2 2 fc f b1 1 F F cE 2 bE