Lecture Objectives: - Define turbulence – Solve turbulent flow example – Define average and instantaneous velocities - Define Reynolds Averaged Navier Stokes equations Fluid dynamics and CFD movies • http://www.youtube.com/watch?v=IDeGDFZSYo8 • http://www.dlr.de/en/desktopdefault.aspx/tabid-6225/10237_read-26563/ • http://www.youtube.com/watch?v=oOGXEfgKttM • http://www.youtube.com/watch?v=IFeSZZ49vAs • http://www.youtube.com/watch?v=o53ghmaSFY8 HW problem The figure below shows a turbulent boundary layer due to forced convection above the flat plate. The airflow above the plate is steady-state. Consider the points A and B above the plate and line l parallel to the plate. Point A y x Flow direction Point A Point B line l a) For the given time step presented on the figure above plot the velocity Vx and Vy along the line l. b) Is the stress component txy lager at point A or point B? Why? c) For point B plot the velocity Vy as function of time. Method for solving of Navier Stokes (conservation) equations • Analytical - Define boundary and initial conditions. Solve the partial deferential equations. - Solution exist for very limited number of simple cases. • Numerical - Split the considered domain into finite number of volumes (nodes). Solve the conservation equation for each volume (node). v v x x Infinitely small difference x x finite “small” difference Numerical method • Simulation domain for indoor air and pollutants flow in buildings 3D space Split or “Discretize” into smaller volumes Solve p, u, v, w, T, C Capturing the flow properties 2” nozzle Eddy ~ 1/100 in Mesh (volume) should be smaller than eddies ! (approximately order of value) Mesh size for direct Numerical Simulations (DNS) ~1000 ~2000 cells For 2D wee need ~ 2 million cells Also, Turbulence is 3-D phenomenon ! Mesh size • For 3D simulation domain 2.5 m Mesh size Mesh size 4m 5m 3D space (room) 0.01m → 50,000,000 nodes Mesh size Mesh size 0.1m → 50,000 nodes 0.001m → 5 ∙1010 nodes 0.0001m → 5 ∙1013 nodes Indoor airflow jet exhaust supply jet turbulent The question is: What we are interested in: - main flow or - turbulence? We need to model turbulence! Reynolds Averaged Navier Stokes equations First Methods on Analyzing Turbulent Flow - Reynolds (1895) decomposed the velocity field into a time average motion and a turbulent fluctuation v x (x, y, z, t ) V x (x, y, z) v x (x, y, z, t ) ' vx’ Vx - Likewise f f , f stands for any scalar: vx, vy, , vz, T, p, where: t t 1 t t f dt Time averaged component From this class We are going to make a difference between large and small letters Averaging Navier Stokes equations p P p , ρ ρ ρ , Substitute into Navier Stokes equations v x Vx v x ' Instantaneous velocity v y Vy v y ' fluctuation around average velocity v z Vz v z ' Average velocity T T T' Continuity equation: v x x v y y v z z time (Vx v x ' ) x (Vy v y ' ) y ( Vz v z ' ) z Vx x x Vy y Vz z v x ' x v y ' y y v z ' z 0 Average of average = average Vx x Vy y Vz z v x ' x Vz z v y ' y v x ' 0 0 0 Average whole equation: Vx Vy v z ' z Average of fluctuation = 0 0 x v y ' y v z ' z 0 Average Vx x Vy y Vz z 0 Time Averaging Operations f' 0 f' f ' 0 f 1f 2 ( 1 f '1 )( 2 f ' 2 ) 1 2 f '1 f ' 2 div f div div (f1f 2 ) div ( 1 2 ) div (f1f 2 ) ' div ( grad f ) div grad ' Example: of Time Averaging Write continuity equations in a short format: ρ( v x τ vx v x vy x v x y vz v x z ) p x vx 2 μ x 2 vx 2 μ y v vx i vy j vz k vx v x x vy vx v x 2 x 2 vz y vx v x 2 y 2 div ( v x v ) v x div v div ( v x v ) z =0 continuity vx 2 z 2 μ div(grad vx) Short format of continuity equation in x direction: ρ( v x τ div(v x v )) p x μ div(grad v x ) SM x 2 vx 2 μ z 2 Sx Averaging of Momentum Equation ρ( v x τ p div(v v )) x μ div(grad x v x ) Sx averaging ρ v x τ ρ div(v p x v) x μ div(grad vx ) Sx 0 ρ v x ρ τ ( V x v' x ) ρ τ ( V x v' x ) τ ρ div ( v x v ) div (V x V ) div ( v v ) div (V x V ) ' x div ( v v ) div ( v (v ' x v x v x ' div(grad ' x ' x v x v y ' ' ' y v x ) div(grad iv ' x ' y ρ τ v x v x ' x Vx τ v x v y ' ' j v k) ) div ( (v v i v v ' x ' z V x ) div(grad Vx) ' x ' y ' z v x v z ' ' Vx ' x v x v z ' z ' y ' j v v k) ) ' x ' z Time Averaged Momentum Equation Instantaneous velocity ρ( v x vx τ v x v x vy x y vz v x p ) z vx 2 μ x x vx 2 μ 2 y vx 2 μ 2 z 2 Sx Average velocities ρ( Vx τ Vx Vx x Vy Vx y Vz Vx z ) P x Vx 2 μ x 2 Vx Vx 2 μ y 2 2 μ z 2 v x v x ' ρ x v x v y ' ' ρ ' v x v z ' ρ y ' z Sx Reynolds stresses For y and z direction: ρ( Vy τ ρ( Vx Vz τ Vy Vx x Vy Vz x Vy Vy y Vz Vz y Vy Vz z ) Vz z P x ) Vy 2 μ P x x 2 Vy 2 μ Vz 2 μ x 2 y 2 Vz Vy 2 μ 2 μ y 2 z 2 Vz v y v x ' ρ 2 μ z 2 ' ρ ' ρ x v z v x ' x v y v y ' y v z v y ' ' ρ y v y v z ' ρ ' ' z v z v z ' ρ Total nine z Sy ' Sz Time Averaged Continuity Equation Instantaneous velocities v x x v y y v z z 0 Averaged velocities Vx x Vy y Vz z 0 Time Averaged Energy Equation Instantaneous temperatures and velocities ρc p ( T τ Vx T x Vy T y Vz T z T 2 )k x 2 T 2 k y T 2 k 2 z 2 Φq Averaged temperatures and velocities ρc p ( T τ Vx T x Vy T y Vz T z T 2 )k x 2 T 2 k y 2 T k z 2 T v x ' 2 ρ x ' T v y ' ρ y ' T v z ' ρ z ' Φq Reynolds Averaged Navier Stokes equations Vx x ρ( Vx τ Vy y Vx Vz z Vx x Reynolds stresses total 9 - 6 are unknown 0 Vy Vx y Vz Vx z ) P x Vx 2 μ x 2 Vx 2 μ y 2 Vx 2 μ z 2 v x v x ' ρ x v x v y ' ' ρ ' y v x v z ' ρ ' z Sx same ρ( ρ( Vy τ Vz τ Vx Vx Vy x Vz x Vy Vy Vy y Vz y Vz Vz Total 4 equations Vy z Vz z ) ) and P x P x Vy 2 μ x 2 Vz 2 μ 2 μ x 2 Vy y 2 Vz 2 μ 2 μ y 2 Vy z 2 Vz ' ρ 2 μ z 4 + 6 = 10 unknowns We need to model the Reynolds stresses ! 2 v y v x ' x v z v x ' ρ x v y v y ' ρ ' y v z v y ' ' ρ y v y v z ' ρ ' ' z v z v z ' ρ z Sy ' Sz Modeling of Reynolds stresses Eddy viscosity models v x v x ' ρ ' x x ' ' ( ρv x v x ) Average velocity Boussinesq eddy-viscosity approximation ' ' ρv i v j Is proportional to deformation V i V j μt x j x i Vy ρ v y v y μ t 2 y 2 ρk 3 Coefficient of proportionality Vx 2 ρ v x v x μ t 2 ρk x 3 Vx Vy ρ v x v y ρ v y v x μ t x y Vx Vz ρ v x v z ρ v z v x μ t z x Vz Vy ρ v z v y ρ v y v z μ t z y Vz 2 ρ v z v z μ t 2 ρk z 3 k = kinetic energy of turbulence ' k ' ' vxvx 2 ' vyvy 2 ' ' vzvz 2 Substitute into Reynolds Averaged equations Reynolds Averaged Navier Stokes equations Continuity: Vx 1) x Vy y Vz z 0 Momentum: 2) ρ( 3) ρ( 4) ρ( Vx τ Vy τ Vz τ Vx Vx Vx Vx x Vy x Vz x Vy Vy Vy Vx y Vy y Vz y Vz Vz Vz Vx z Vy z Vz z ) ) ) P x P x P x x x x [( μ μ t ) [( μ μ t ) [( μ μ t ) S Tz S z s tz S z Similar is for STy and STx z 4 equations 5 unknowns Vy x Vy x Vy x ] ] ] [( μ μ t ) → y y y [( μ μ t ) [( μ μ t ) [( μ μ t ) v x x Vy y Vy y Vy y ] ] ] (μ μ t ) z z z v y y [( μ μ t ) [( μ μ t ) [( μ μ t ) Vy z Vy z Vy z (μ μ t ) We need to model μt ] ST x ] ST y ] ST z v z z ] Modeling of Turbulent Viscosity μ μt Fluid property – often called laminar viscosity Flow property – turbulent viscosity constant t MVM: Mean velocity models MVM mixing length TKEM: Turbulent kinetic energy One - Eq. Free 1 Layer High Re wall 2 Layer bounded 3 Layer k - Models based on μ t Low Re TKEM Two Buoyancy Eq. Curvature k - k - l k - kl k f ...... equation models Additional models: LES: RSM: Large Eddy simulation models Reynolds stress models