ENE 428 Microwave Engineering Lecture 4 Reflection and Transmission at Oblique Incidence, Transmission Lines 1 RS Plane wave propagation in general dielectrics Assume lossless medium The propagation directions are ai , ar , and at The plane of incidence is defined as the plane containing both normal to the boundary and the incident wave’s propagation direction. The angle of incidence i is the angle the incident field makes with a normal to the boundary RS 2 Polarizations of UPW obliquely incident on the boundary (1) Perpendicular polarization or transverse electric (TE) polarization E is normal to the plane of incidence and tangential to the boundary. Only the x component of the magnetic field is tangential. 3 RS Polarizations of UPW obliquely incident on the boundary (2) Parallel polarization or transverse magnetic (TM) polarization H is normal to the plane of incidence and tangential to the boundary. Only the x component of the electric field is tangential. 4 RS TE polarization x i E E0i e j 1z ' a y i z i H E0i e j 1z ' (a x ' ) 1 We can write i E E0i e j 1 ( x sini z cosi ) a y and i H E0i 1 e j1 ( x sini z cosi ) ( cos i a x sin i a z ) 5 RS Reflected and transmitted fields for TE polarization Reflected fields r E E0r e j 1 ( x sinr z cosr ) a y r H E0r 1 e j1 ( x sinr z cosr ) (cos r a x sin r a z ) Transmitted fields t E E0t e j 2 ( x sint z cost ) a y t H RS E0t 2 e j2 ( x sint z cost ) ( cos t a x sin t a z ) 6 Snell’s laws of reflection and refraction (1) Tangential boundary condition for the electric field j x sin j x sin at z = 0 E0i e 1 i a y E0r e j1x sinr a y E0t e 2 t a y for this equality to hold, 1x sin i 1x sin r 2 x sin t Snell’s law of reflection Snell’s law of refraction RS i r 1 sin t or 2 sin i n1 sin 1 n2 sin 2 7 Snell’s laws of reflection and refraction (2) the critical angle for total reflection (i )critical 2 sin 1 1 If i cri, then it is total reflection and no power can be transmitted, these fields are referred as evanescent waves. 8 RS Reflection and transmission coefficients for TE polarization (1) From the electric field’s B.C. with phases matched, we have E0i E0r E0t . (1) Tangential B.C. for the magnetic field considering matched phase and equal incident and reflected angles is E0i E0r 1 cos i E0t 2 cos t . (2) 9 RS Reflection coefficient for TE polarization Solving Eqs. (1) and (2) gets 2 cos i 1 cos t i E E0 2 cos i 1 cos t r 0 or TE 2 cos i 1 cos t . 2 cos i 1 cos t 10 RS Transmission coefficient for TE polarization Solving Eqs. (1) and (2) gets 2 2 cos i E E0i 2 cos i 1 cos t t 0 or TE Notice that 2 2 cos i . 2 cos i 1 cos t TE 1 TE 11 RS Ex2 A 2 GHz TE wave is incident at 30 angle of incidence from air on to a thick slab of nonmagnetic, lossless dielectric with r = 16. Find TE and TE. 12 RS Fields for TM polarization Incident fields i E E0i e j 1 ( x sini z cosi ) (cos i a x sin i a z ) i H E0i 1 e j1 ( x sini z cosi ) a y Reflected fields r E E0r e j1 ( x sinr z cosr ) (cos r a x sin r a z ) r H E0r 1 e j 1 ( x sinr z cosr ) a y Transmitted fields t E E0t e j 2 ( x sint z cost ) (cos t a x sin t a z ) t RS H E0t 2 e j2 ( x sint z cost ) a y 13 Reflection and transmission coefficients for TM polarization Solving B.C.s gets TM and Notice that 2 cos t 1 cos i 2 cos t 1 cos i TM 22 cos i . 2 cos t 1 cos i TM cos i (1 TM ) cos t 14 RS Total transmission for TM polarization Brewster’s angle for total transmission i BA sin 1 22 ( 22 12 ) 22 12 12 22 For lossless, non-magnetic media, we have BA sin 1 1 1 r1 r2 15 RS Ex3 A uniform plane wave is incident from air onto glass at an angle from the normal of 30. Determine the fraction of the incident power that is reflected and transmitted for a) and b). Glass has refractive index n2 = 1.45. a) TM polarization b) TE polarization 16 RS Transmission lines (1) • Transmission lines or T-lines are used to guide propagation of EM waves at high frequencies. • Examples: – – – – – • Transmitter and antenna Connections between computers in a network Interconnects between components of a stereo system Connection between a cable service provider and aTV set. Connection between devices on circuit board Distances between devices are separated by much larger order of wavelength than those in the normal electrical circuits causing time delay. 17 RS Transmission lines (2) • Properties to address: – – – – time delay reflections attenuation distortion 18 RS Distributed-parameter model • Types of transmission lines 19 RS Distributed-parameter model • The differential segment of the transmission line R’ = resistance per unit length L’= inductance per unit length C’= capacitor per unit length G’= conductance per unit length 20 RS Telegraphist’s equations • General transmission lines equations: v( z, t ) i ( z, t ) i ( z, t ) R ' L ' z t i ( z, t ) v( z , t ) v( z, t )G ' C ' z t 21 RS Telegraphist’s time-harmonic wave equations • Time-harmonic waves on transmission lines dV ( z ) ( R ' j L ') I ( z ) dz dI ( z ) (G ' jC ')V ( z ) dz After arranging we have d 2V ( z ) 2V ( z ) 0 dz where ( R ' j L ')(G ' jC ') j . 22 RS Traveling wave equations for the transmission line • Instantaneous form v( z, t ) V0 e z cos(t z ) V0e z cos(t z ) i( z, t ) I 0 e z cos(t z ) I 0e z cos(t z ) • Phasor form V ( z ) V0 e z V0e z I ( z ) I 0 e z I 0e z 23 RS Lossless transmission line • lossless when R’ = 0 and G’ = 0 0 j j L ' C ' L ' C ' and 1 up L 'C ' 24 RS Low loss transmission line (1) • low loss when R’ << L’ and G’ << C’ 1/ 2 j R ' j L ' (G ' jC ')1/ 2 1/ 2 1/ 2 R' G' j L ' C ' 1 1 j L ' j C ' Expanding 1 x in binomial series gives 2 x x 1 x 1 ...... 2 8 for x << 1 25 RS Low loss transmission line (2) Therefore, we get 1 C' L' (R ' G' ) 2 L' C' R' 1 G' LC 1 ( ) 8 C ' L ' 26 RS Characteristic impedance Characteristic impedance Z0 is defined as the the ratio of the traveling voltage wave amplitude to the traveling current wave amplitude. V0 V0 Z0 I0 I0 or RS R ' j L ' Z0 . G ' jC ' For lossless line, L' Z0 . C' 27 Power transmission Power transmitted over a specific distance is calculated. The instantaneous power in the +z traveling wave at any point along the transmission line can be shown as 2 V Pi ( z, t ) v( z, t )i( z, t ) 0 e2 z cos 2 (t z ). Z0 The time-averaged power can be shown as 2 T T V 1 1 2 z 2 Pavg ( z ) Pi ( z, t )dt 0 e cos (t z )dt. T0 Z0 T0 RS 2 V Pavg ( z ) 0 e2 z Z0 W. 28 Power ratios on the decibel scale (1) A convenient way to measure power ratios Power gain (dB) Pout G (dB) 10 log( ) Pin dB Power loss (dB) Pin attenuation(dB) 10 log( ) dB Pout 1 Np = 8.686 dB RS 29 Power ratios on the decibel scale (2) Representation of absolute power levels is the dBm scale P G(dBm ) 10log( ) 1mW dBm 30 RS Ex1 A 12-dB amplifier is in series with a 4-dB attenuator. What is the overall gain of the circuit? Ex2 If 1 W of power is inserted into a coaxial cable, and 1 W of power is measured 100m down the line, what is the line’s attenuation in dB/m? 31 RS Ex3 A 20 m length of the transmission line is known to produce a 2 dB drop in the power from end to end, a) what fraction of the input power does it reach the output? b) What fraction of the input power does it reach the midpoint of the line? c) What is the attenuation constant? 32 RS