Green’s functions and one-body quantum problems G F ca n b e u se d to co n v e rt ( 1 2 r V ( r ) ) ( r ) 0 2 in to a n in te g ra l e q u a tio n a n d to co n v e rt in te g ra l o v e r so m e v o lu m e to su rfa ce in te g ra ls o v e r b o u n d a ry S o f . Source introduce G satisfying: m u ltip ly ( G (r',r)( m u ltip ly ( (r ) ( 1 2 1 2 1 2 1 2 ( 1 2 r V ( r ) )G ( r ', r ) ( r ' r ) 2 r V ( r ) ) ( r ) 0 2 by G (r',r) The delta not yet invented at Green’s time r V ( r ) ) ( r ) 0 . 2 r V ( r ) )G ( r ', r ) ( r ' r ) 2 by r V ( r ) )G ( r ', r ) ( r ) ( r ' r ) (r ) 2 1 G (r ',r)( 1 (r ) ( su btract : (r ) ( 1 2 2 V 1 2 r V ( r ) ) ( r ) 0 . 2 r V ( r ) )G ( r ', r ) ( r ) ( r ' r ) 2 disappears 1 r )G ( r ', r ) G (r ',r)( 2 r ) ( r ) ( r ) ( r ' r ) 2 2 in te g ra te o n r 1 2 dr [ ( r ) r G ( r ', r ) G (r',r) r ( r )] 2 2 dr ( r ) ( r ' r ) ( r '). N ow interchan g e (r ) 1 2 r and r' dr '[G (r,r') r ' ( r ') ( r ') r 'G ( r , r ')] 2 2 This is the sought integral equation: next, we convert volume integral -> surface integral 2 (r ) S tartin g fro m 1 2 dr '[G (r,r') r ' ( r ') ( r ') r 'G ( r , r ')] 2 2 convert volume -> surface integral using the divergence theorem. divergence theorem : divA dr A .( ) dr A .n dS S In se rt ( ).n dS S ( ( r ) ( r ) ( r )) dr 2 2 ( ( r ) ( r ) ).n dS S N o w r r ', th e n (r') G ( r,r ' ). In th is w ay th e re su lt (r ) 1 2 dr '[G (r,r') r ' ( r ') ( r ') r 'G ( r , r ')], r ' 2 2 is co n v e n ie n tly re w ritte n as a su rface i n te g ral (r ) 1 2 S [G (r,r') r ' ( r ') ( r ') r 'G ( r , r ')]n dS , r ' S . 3 Simple use of Green’s functions for Schroedinger’s equation H E , E 1 G reen 's o p erato r G su ch th at ( H )G 1 In tro d u ce H H 0 H 1 w ith easy H 0 . ( H 0 ) 1 H 1 H 1 H operator identities ( H 0 H 1 H 1 ) 1 H0 1 H0 1 H0 1 H 1 H H1 H1 1 H1 1 H 1 H 1 H0 Example: H1=V(r): then, in the coordinate representation r 1 H r' r 1 H0 r' r 1 H0 H1 1 H r' 4 N ext introduce com plete set in r r 1 H 1 H w here r' r r' r 1 H0 1 H0 r' r' r r '' r 1 H0 1 H0 H1 1 r' H H 1 r '' r '' 1 H r' H 1 r '' V ( r '') r '' Lippmann-Schwinger equation G r , r ' G0 r , r ' d r '' G 0 r , r '' V r '' G r '', r ' 3 The Lippmann-Schwinger equation is most convenient when the perturbation is localized . Typical examples are impurity problems, in metals. The alternative is embedding (Inglesfield 1981) 5 W e w ish to solve the one-body problem H ψ = ε ψ w ith H 1 V ( r ), 2 2 but V ( r ) is com plicat ed in som e regio n. Suppose we can solve except inside the surface S. We can also solve S ( ( 1 2 r V ( r )) g ( r ', r , ) ( r r '), r and r ' outside 2 and wave functions outside are related to g by Green’s theorem (r ) 1 2 [G ( r, r') r ( r ') ( r ') r 'G ( r , r ') ] n dS , r outside, r ' on S . ' S It is assumed that G outside S is not modified by the presence of the localized perturbation. W e can also solve ( ( 1 2 r V ( r )) g ( r ', r , ) ( r r ') 2 r ' g ( r , r ') 0. w ith the boundary condition on S T hen for r outside S (r ) 1 2 g ( r , r ') ( r ')·ndS , r ' on S . S 6 T he relati on (r ) 1 2 g ( r , r ') ( r ')·ndS , r outsi de S S also fixe s a relati on betw een and on S through g. Let us see ho w . S uppose ( r ) is a know n function for r S . S W e call it ( r ). T hen, (r ) 1 2 g ( r , r ') ( r ')·ndS , for r , r ' S . S T his c an be considered as a m atrix relation and inve r t ed: ( r ')·n 2 d S g 1 ( r , r ') ( r '), r , r ' S S w it h g 1 ( r , r ') a m atrix inverse, and so know ledge of ( r ) determ ines on the surface S . know ledge of ( r ) determ ines outside S . 7 N ext, w e w rite S d x 3 2 as a surface integral using G re en's theorem . ouside S D ivide by and m ultiply by : M ultiply H * H * ψ =ε * ψ + |ψ | H ψ =ε ψ +ψ ε H ψ =εψ V ary ε : 2 ε ψ ψ * 2 S ubstituting, H H =|ψ | * ouside S * ψ d x 3 2 ε * ψ H * by ψ : * d x [ H 3 ouside S * ψ ψ * H ] T h e term w ith V can cels an d w e can u se G reen 's th e o rem : ( ) dr 2 2 ouside S ( ).n dS S w ith *, d x 3 2 1 2 [ S * , H - ψ 1 2 , o u tsid e S 2 ].ndS (sign change for ouside norm al) * 8 W e can vary ε k eep in g ( r ) ( r ) o n S ψ 0 o n S . T h is is clever b ecau se w e g et : d x 3 ouside S 2 1 2 S * .ndS (sign change for ouside norm al) 1 R ecall : w e have seen that ( r ')·n 2 d S g ( r , r ') ( r '), r , r ' S S w ith g 1 ( r , r ') a m atrix inve rse, and so know ledge of ( r ) determ ines o n S , henc e also d x 3 2 . ouside S John E. Inglesfield, Emeritus Professor ,Cardiff 9 Inglesfield embedding W e w ish to solve the one-body problem w ith H 1 V ( r ), bu t V is com plicated in som e region. 2 2 The Lippmann-Schwinger equation is less convenient when the perturbation is extended. Typical examples are surface problems, when one wants to treat the effects of surface creation, reconstruction, or contamination. In such cases one can resort to slab models, but there are serious drawbacks in any attempt to represent a bulk by a few atomic layers, with quantized normal momenta. The only practical alternative is the method of embedding. 1) in an extended system, there is a localized perturbing potential. A surface S divides the perturbed region I from the far region II where the potential is negligible. 2) the problem in I alone can be solved 3) the extended unperturbed system could be treated easily because it is highly symmetric 4) the wave functions match those of the extended system on S. II S I (r ) P roblem : to find ( r ) (r) ( r ) ( r ) such that E | H | | rI r II r S; is stationary (that is, H | E | ) 10 II S I (r ) P roblem : to find ( r ) (r ) ( r ) ( r ) such that E | H | | rI r II r S; is stationary (that is, H | E | ) S trategy: w rite E only in term s of in I an d on S . | d x 3 2 I d x 3 V 2 1 2 I 3 2 an d sin ce II ouside S | d x d x 3 2 S 1 2 * S * .n d S , w h ere ( r ')·n 2 d S g .n d S , 1 ( r , r ') ( r '), r , r ' S . S S o , | is a fu n ctio n al o f . 11 (r ) P roblem : to find ( r ) (r ) ( r ) ( r ) II S such that E I | H | | rI r II r S; is stationary (that is, H | E | ) S trategy: w rite E only in term s of in I an d on S . N ext,w e w an t | H | d x H 3 * I w here d x 3 * H d x * 3 V II extends to a sm all volum e around S . V W e have just seen how to w rite d x in term s of : 3 * II V o u sid e S d x 3 2 1 2 S * .n d S , w h ere ( r ')·n 2 d S g S 1 ( r , r ') ( r '), r , r ' S . 12 C ontribution in V H d x V V H d x * * 3 3 ( * 1 V ( r )) d x , but the term in V vanishes w it h V 2 3 V 2 1 d x * 2 3 2 V V 1 d x * 2 3 2 V In each dS , w ith z dS , 1 2 * dSdz 2 1 2 V * div gra d dSdz V S By the divergence theorem 1 2 * div grad dSdz 1 2 V T o sum up, * .n outer .n inner dS H d x * 3 2 V B ut recall: 1 1 2 * .n outer dS . * .n outer dS . S ( r ')·n 2 d S g 1 ( r , r ') ( r '), r, r ' S S so everything is written in terms of and one obtains a localized variational problem in region I equivalent to a Schrödinger equation with a potential at S. 13 Absence of Magnetism in classical physics Ampere Postulated “molecular-ring” currents to explain the phenomenon of magnetism Bohr-Van Leeuwen Theorem (1911) Partition function for a Classical electron in canonical ensemble Z px2 p y2 pz2 d x d p ex p 2 m K BT 3 3 Classical electron in magnetic field eH 2 2 2 ( p y ) p p y z x 3 3 c Z d x d p exp 2 m K BT A change of variable removes the field. dp x d ( px eH y) c Z V 2 m K B T 3 2 14 magnetism cannot exist (catastrophe of classical physics) Langevin paramagnetism "gas" of ions w ith m agnetic m o m e nts g B J in fiel d B . H am iltonian H g B J .B M m agnetization N z V olum e Q uantum partition function J Z m J (2 J 1) g B B sinh 2 K T mg B B B exp[ ] K BT gBB sinh 2 K BT z K BT M ean m o m en t ln ( Z ) B g B JB J ( Paul Langevin (1872-1946) g B BJ ), K BT w h ere B J ( x ) is k n o w n as B rillo u in fu n ctio n BJ ( x) 2J 1 2J co th ( (2 J 1) x 2J ) 1 2J co th ( x 2J ) 15 C ase J 1 (electron), g 2 : 2 J the partition function is Z m J exp[ mg B B ] 2 cosh( K BT BB ) K BT BH BH M B tanh H igh tem perature behaviour: V K T K BT B N N B H 1 2 M V C urie law (for param agn etis m ) K BT 16 Can we explain ferromagnetism as due to dipole-dipole interactions? Orders of magnitude estimate e Interaction energy of tw o dipoles (B ohr M agneton) 2mc B 2 at distance a lattice several B ohr radii : E dip B 2 3 aB S ince ( e ) 2mc e 1 2 2 me 2 2 c 1 3 e 2 2 2 4m c 3 m e 2 6 6 1 mc , 2 4 4 , m c 0.5 M eV , 1 2 3 a lattice 0 K 0.025 eV 137 B 2 if a lattice 4 a B E dip dipole-dipole 0 .1 K . 0 3 64aB interaction far to o sm all to explain ferrom ag nets! Heisenberg chain: a solvable 1d model of magnetism N H H eisen berg J n 1 S n .S n 1 , J0 ferrom agn etic 18 Hans Bethe solved the linear chain Heisenberg model H , , E ( , , 1 2 N 1 2 N ) 1 , 2 , Born July 2, 1906 Strassburg, Germany Died March 6, 2005 Ithaca, NY, USA Residence USA Nationality American Field Physicist Institution University of Tübingen Cornell University Alma mater University of Frankfurt University of Munich Academic advisor N Arnold Sommerfeld Zur Theorie der Metalle. I. Eigenwerte und Eigenfunktionen der linearen Atomkette Zeitschrift für Physik A, Vol. 71, pp. 205-226 (1931) 19 1 , 2 , N spins ½ on a ring with a configuration , N Symmetries N H H eisen berg J S n .S n 1 is in varian t for tran slation s of all sp in s n 1 th ere is a con served w avevector K of all th e sy stem N H H eisen b erg J S n .S n 1 is in v a ria n t fo r sp in ro ta tio n s n1 (sin ce sca la r p ro d u cts a re in v a ria n t) c o n se rv e d to ta l sp in S , c o n se rv e d Sz N N Separated problem s for each set K ,S , S z 2 . 20 N H H eisen berg J S n .S n 1 can b e re w ritte n n1 N H H eisen berg H 0 H X Y , H0 J S z .S n z , H XY n1 n 1 H XY J N 2 (Sn Sn 1 Sn Sn 1 ) m oves , to J 2 N (S n S n 1 S n S n 1 ) n 1 rig h t or le ft n1 Ground state for J>0: all spins up, no spin can be raised, and so no shift can occur H XY J 2 N ( S n S n 1 S n S n 1 ) H X Y ... 0 n1 N H H eisen berg ... J N S z .S n z n1 ... J n1 g ro u n d state en erg y E n1 ( N 0 ) J 1 4 ... N 4 21 1 reversed spin in the chain Consider for the moment no hopping, only H0 N H0 J S z .S n H 0 ... E ( ... ) z n1 ... n 1 E ( ... ) E ( ... ) E w h e re a facto r e x tra 2 2 ( J) E ( ... ) 2 * 2 * ( N 0 ) e n te rs b e cau se b e cau se 2 of J 4 N E ( ... ) J , , 4 p o sitiv e n e g ativ e , th e scalar p ro d u cts are re v e rse d . A configuration with r=1 is conveniently denoted by |n>, n=position of down spin. 22 They are all degenerate. Now introduce the hopping term. H XY J N 2 (Sn Sn 1 Sn Sn 1 ) m o v es to rig h t or left, so n 1 ( H H eisenberg E N 0 ) n J n J ( n 1 n 1 ). 2 Introducing the eigenvect or E , H H eisenberg E E E Introduce E E n f n ( H H eisenberg E N 0 am plitude ) n J of E n on J 2 ( site E n in eigenvec tor of H . n 1 E n 1 ) th at is , (E E N 0 f ( n 1) f ( n 1) ) f n J f (n ) 2 23 One- Magnon solution: spin wave (E E N 0 i s solved by N f ( n 1) f ( n 1) ( N 0 ) ) f n J f (n ) , E J , 2 4 f (n) e ik j n indeed f ( n 1) f ( n 1) , N e ik j n (e ik j e N We must insert the periodic boundary condition for the N-spin chain f n N energy : f (n) kj N 0 e (E E ) 2 j N ik j n J N E E ( N 0 ) e E 1 N N e ik j n n n 1 e ik j e ik j 1 2 N ik j n J 1 cos( k j ) 24 ik j ). N H H eisen berg J S n .S n 1 , J0 ferro m ag n etic n1 One- Magnon solution: the spin wave is a boson (spin 1) E E 0 E 1 N N e ik j n n , kj n 1 2 j 2.0 N 1.5 J 1.0 E E ( N 0 ) J 1 cos( k j ) 0.5 k 3 2 1 1 2 3 This magnon dispersion law looks like a free quasi-particle dispersion for small k Two- Magnon solution: scattering, bound states 25 Several reversed spins N L e t u s first c o n sid e r H 0 J z S n .S z n1 w ith o u t h o p p in g , n 1 w ith r N re v e rse d H 0 1 , 2 , sp in s. N E ( 1 , 2 , N ) 1 , 2 , N . A n y p atte rn o f sp in s w ill d o , b u t E ( 1 , 2 , N ) d iffe rs if far o r c o n se c u tiv e sp in s are re v e rse d : ... h av e d iffe re n t E ( 1 , 2 , E ( 1 , 2 , N) E N n u m b e r ... an d ( N 0 ) of 2 N ). J N , 4 re v e rse d sc alar p ro d u c ts . N o w in c lu d e H X Y . Two Magnons a configuration is denoted by |n1,n2>, H XY J N 2 (Sn Sn 1 Sn Sn 1 ) m oves n1<n2 reversed spins to rig h t or le ft n 1 provided that adiacent sites are up spins: if the reversed spins are close the energy is different and this is an effective interaction. W e in tro d u ce th e case n 2 n 1 1 by m ean s o f a bo u n d ary co n d itio n . F irst, w e so lv e fo r n 2 n 1 1, w h en th e sp in s are 'far' an d m o v e in d ep en d en tly . ( H H eisen berg E ( N 0 ) ) n1 , n 2 2 J n1 , n 2 J n 1 1, n 2 n 1 1, n 2 n 1 , n 2 1 n 1 , n 2 1 2 27 . ( H H eisen berg E J L et E J ( N 0 ) ) n1 , n 2 2 J n1 , n 2 n 1 1, n 2 n 1 1, n 2 n 1 , n 2 1 n 1 , n 2 1 2 f ( n1 , n 2 ) E n1 , n 2 , f n1 , n 2 2 f n1 , n 2 T hus r.r. is i ( k1 n1 k 2 n 2 ) O ne the energy origin : n 2 n1 1 EE N 0 E f ( n1 1, n 2 ) f ( n1 1, n 2 ) f ( n1 , n 2 1) f ( n1 , n 2 1) . 2 satisfied f n1 , n 2 e R ecall shift , , n1 n2 for E J M agnon by the produc t (1 cos( k 1 )) (1 cos k 2 ). S olution : E J 1 cos( k j ). Two independent magnons? NO! New k1 and k2 must be found since PBC do not separately apply to n1 and n2 (you cannot translate one magnon across the other). However there is In v arian ce u n d er g lo bal tran slatio n s o f bo t h rev ersed sp in s: f n1 N , n 2 N f n1 , n 2 . 28