Section 7.4
Proportional parts of triangles
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Non parallel transversals that intersect parallel lines can be extended to form similar triangles.
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So, the sides of the triangles are proportional.
Side Splitter Theorem or Triangle
Proportionality Theorem
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If a line is parallel to one side of a triangle and intersects the other two sides, it divides those two sides proportionally.
A
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If BE || CD, then
B E AB
AE
BC ED
D C
AB||ED, BD = 8, DC = 4, and AE = 12.
C
•
Find EC
D E
•
•
CD
CE
DB EA
4
EC
8 12 by
EC = 6
B
?
A
UY|| VX, UV = 3, UW = 18, XW = 16.
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Find YX.
UV
YX
WV XW
3
YX
15 16
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YX = 3.2
Y
U
X
V
W
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If a line intersects the other two sides and separates the sides into corresponding segments of proportional lengths, then the line is parallel to the third side.
A
•
If
BC ED
B E
• then BE || CD
C D
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In triangle DEF, DH = 18, and HE = 36, and DG = ½ GF.
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To show GH || FE,
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Show DG
DH
GF HE
• Let GF = x, then DG = ½ x.
• Substitute
1
2 x x
18
36
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Simplify 1
2
18
1 36
• Simplify 1
1
2 2
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Since the sides are proportional, then GH
|| FE.
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A midsegment of a triangle is parallel to one side of the triangle, and its length is one-half the length of that side.
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If D and E are mid-
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Points of AB and AC,
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Then DE || BC and
• DE = ½ BC
•
•
•
•
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Triangle ABC has vertices A(-2,2), B(2, 4) and C(4,-4). DE is the midsegment of triangle ABC.
Find the coordinates of D and E.
D midpt of AB
2
2 2
,
2
4
D(0,3)
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E midpt of AC
•
E(1, -1)
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Part 2 - Verify BC || DE
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Do this by finding slopes
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Slope of BC = -4 and slope of DE = -4
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BC || DE
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Part 3 – Verify DE = ½ BC
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To do this use the distance formula
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BC = which simplifies to
2 17
•
DE = 17
• DE = ½ BC
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1. If three or more parallel lines intersect two transversals, then they cut off the transversals proportionally.
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If three or more parallel lines cut off congruent segments on one transversal, then they cut off congruent segments on every transversal.
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1. In the figure, Larch, Maple, and
Nutthatch Streets are all parallel. The figure shows the distance between city blocks. Find x.
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Find x and y.
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Given: AB = BC
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3x + 4 = 6 – 2x
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X = 2
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Use the 2 nd corollary to say DE = EF
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3y = 5/3 y + 1
• Y = ¾