THE UNIFIED FIELD EXPLAINED

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
All physical constants are RATIOS

Every RATIO is a RATIO between two
charges
These two charges move following the law of
Sin and Cosine
The sum of both functions represent the total
field.


LET US BEGIN TAKING A SNAP SHOT AT A WAVE MOVING AHEAD:
WE HAVE FOUND THE TWO OPPOSED FORCES
AT REST
ONE TO THE LEFT : THE COSINE “Y “ at 180° = -1
ONE TO THE RIGHT: THE SIN “ Y” at 0° = 0
Cos Y=-1
Sin Y= 0
In Order to make it less abstract we put two opposite forces:
Oxygen to the left and Hydrogen to the right
Then let´s observe them move 45°
Electricity
Sin Y = + 0.70711
Cos Y= - 0.7011
Magnetism:
Sin Y = + 0.70711
CosY = + 0.70711
OH-H
H-OH
Cos Y=-1
O-
Sin Y= 0
H+
Now we have: ELECTRICITY and MAGNETISM
at an angle of 90° between them.
And ionized Water as Hydrogen Hydroxide
Electricity
Sin Y = + 0.70711
CosY= - 0.7011
OH-H
Cos Y=-1
O-
Magnetism:
Sin Y = + 0.70711
Cos Y = + 0.70711
H-OH
Sin Y= 0
H+
GRAVITY:
Sin 90°= 1
Cos 90°= 0
G= Sin Y + CosY = 1 + 0 = 1
And H2O WATER! (MATTER)
Magnetism:
Sin Y = + 0.70711
Cos Y = + 0.70711
Electricity
Sin Y = + 0.70711
Cos Y= - 0.7011
H-OH
OH-H
Cos Y=-1
O-
G
Sin Y= 0
H+
•When the two polar forces oppose, at sin 0°=0, and
Cos 180°= -1 ,
the resultant field is 100% an EMISSION FIELD.
•When the two polar forces oppose at an angle of 90°,
the resultant field is a MAGNETIC FIELD/ ELECTRICAL
FIELD
•When the two polar forces approach Sin 90°=1 and
Cos 90°=0 both vectors add, changing direction 180°,
thus the resultant force will oppose the emission field
and it is called Gravity
So Gravity is the sum:
G = sin y + cos y
G=1+0
Which means that the resultant force will be
equal to 1, or almost one, as 0.981 . Now, G, the
constant, the gravitational constant, in
Newton´s equation:
F=G (M1M2)/r2
Actually represents the sine added to the
cosine of the angle equal to 90°
G = Sin y + Cos y = 1 – 0 = 1
Note: We have divided G/10=0.981
So the Max Planck ´s equation :
E= h
h = Sin y + Cos y
C/
Becomes the equation of the Unified Field:
E= (Sin y + Cos y)x 
or
E= (Sin y + Cos y)(C/)
Magnetism
Electricity
Earth Gravity= 9.81 Nm
10 – 9,81 = 0.19
Sin 0.19 = 78.5°
79°
Gravity at the
northen
hemisphere
11.5°
23°
Ecliptic
78.5°
78.5°
Sin 23°=0.391
Gravity at
the
southern
hemisphere
The two vectors
of Gravity add,
Giving as the
result the
inclination of
axis of the Earth
on Ecliptic
Electricity
Sin Y = + 0.70711
CosY= - 0.7011
1
2 =1.414…..
+
1
The Pythagorean Monocord
Magnetism:
Sin Y = + 0.70711
CosY = + 0.70711
Pythagoras
Monocord
Ignis :Fire, Plasma
Aer : Air, Gas
Aqua: Water, Liquid
Terra: Earth, Solid
Mercury eccentricity=
AC Phase angle Deg.:
0.21
22.33
78.14
F
Venus eccentricity=
AC Phase angle Deg.:
Gravity (sin y)
0.38
Field (-cos y)
-0.98
0.01
89.61
F
Earth eccentricity=
AC Phase angle Deg.:
F
Moon (a) eccentricity=
AC Phase angle Deg.:
-1.00
0.02
89.04
-1.00
0.03
-1.00
0.08
-1.00
0.09
-1.00
0.05
-1.00
0.06
-1.00
0.05
Cos y
-0.997031
-0.6170
Cos y (grades)
174.64
-6.17 Nm
Cos y
-0.995629
-0.6156
Cos y (grades)
177.23
-6.16 Nm
Cos y
-0.998833
1.6412
Cos y (grades)
176.79
16.41 Nm
Cos y
-0.998431
-0.0684
Cos y (grades)
177.36
Field (-cos y)
-0.68 Nm
Cos y
-0.998937
EM field
-1.00
0.01
89.44
F
-3.78 Nm
EM field
-6.89
Gravity (sin y)
1.12
Cos y (grades)
175.58
Field (-cos y)
87.36
F
Neptune eccentricity=
AC Phase angle Deg.:
-0.999662
EM field
62.87
Gravity (sin y)
0.89
Cos y
-0.3777
Field (-cos y)
86.79
F
Uranus eccentricity=
AC Phase angle Deg.:
-0.19 Nm
EM field
68.43
Gravity (sin y)
0.93
Cos y (grades)
178.51
Field (-cos y)
87.23
F
Saturn eccentricity=
AC Phase angle Deg.:
-0.999861
EM field
-39.79
Gravity (sin y)
2.64
Cos y
-0.0189
Field (-cos y)
84.64
F
Jupiter eccentricity=
AC Phase angle Deg.:
-1.00 Nm
EM field
22.33
Gravity (sin y)
0.38
Cos y (grades)
179.04
Field (-cos y)
85.58
F
Mars eccentricity=
AC Phase angle Deg.:
-0.999977
EM field
22.33
Gravity (sin y)
0.38
Cos y
-0.1000
Field (-cos y)
88.51
F
Moon (b) eccentricity=
AC Phase angle Deg.:
Cos y (grades)
179.61
-5.99 Nm
EM field
38.46
Gravity (sin y)
0.62
-0.978636
-0.5987
Field (-cos y)
78.81
1.38
Gravity (sin y)
0.98
Cos y
EM field
64.16
Gravity (sin y)
0.90
Cos y (grades)
168.14
-0.1089
Cos y (grades)
179.44
Field (-cos y)
-1.09 Nm
Cos y
-0.999953
EM field
-1.00
0.1200
1.20 Nm
The eccentricity of
planets´orbits it is
related to the intensity
of the emission field =
Cos y
Electric comets imply that the Sun is the center of an electric field. It is the most
positively charged body in the solar system. A comet approaching the Sun from
a much more distant region will carry far more negative charge than those
orbiting closer to the Sun.
David Talbott
http://www.thunderbolts.info/wp/2011/10/06/comet-elenin%E2%80%94the-debate-that-never-happened/
A proof of Mercury´s emission field
It is obvious that at Sin y= 90°the Emission Field is at its
Maximum and the Gravity Field, being equal to
Cos y=0 is at its Minimum, so the
Emission Field is at its Minimum at
Sin y=270°=-1and the Gravity Field is at its Maximum at Cos
y=270°=0
Thus:
•The lesser the emission field the greater the gravity (mass)
field:
•E = (Sin y + Cos y)(C/)
We have adopted the notation
Where the Maximum EM Field
“Repulsion” be expressed as
A NEGATIVE VALUE/CHARGE
‫إمام‬
Sin y +
Cos Y
√2
1
1
‫إمام‬
The Unified field
A wave……..
EVERYTHING IS ELECTRIC AND EVERY PHENOMENON IN NATURE
IS AN ALTERNATE CURRENT”…..AT DIFFERENT PHASE ANGLES
BETWEEN THE TWO OPPOSITE FORCES
In order to know how Energy develops following The Unified Field
Law, let us do:
E= (Sin y + Cos y)x 
E= (Sin y *  ) + (Cos y *  )
Thus, let us take some known frequencies;
Sound frequencies and plot them:
WE GET A LOGARITHM SPIRAL
The perfect expression of Power
from a Birkeland Current, or an
Alternate Current or……
Andromeda galaxy, under
IR light, where all the
Suns look connected
The FIBONACCI series
The Way of Nature
The Way of The Unifed Field!
EMISSION FIELD
45 °
45 °
Cos Y=-1
Sin Y= 0
180°
GRAVITY FIELD
Sin Y + Cos Y
Adolfo Rios Pita Giurfa
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