lab 9

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BUFFER
SOLUTIONS
LAB 9
INTRODUCTION
Adding trace amount of acid to water will result in increase in
H+ concentration. In the same manner, adding trace amount
of alkali eg. NaOH to pure water will result in increase of OH−
So we can say that water has no ability to resist change in H+
concentration or pH.
(pH = − log [H+])
WHAT IS A BUFFER
SOLUTION?
Buffer solution:
Is a system that possesses the property of resisting change
in the pH with the addition of small amount of strong acid or
base.
The efficiency of the system called buffer capacity.
COMPOSITION
Buffer solution is usually composed of a weak acid and a salt
of the acid eg. Acetic acid and sodium acetate, or weak base
and a salt of the base eg. Ammonium hydroxide and
ammonium chloride.
WEAK ACID BUFFER
Weak acids do not completely dissociate when in solution,
instead an equilibrium is set up;
HA ā‡Œ H+ + A−
The dissociation constant or š‘²š’‚ value is calculated by the
following equation:
š‘²š’‚ =
Where
š€− = salt
š‡š€ = acid
š‡ + š€−
(š‡š€)
WEAK ACID BUFFER
Dissociation constants of some weak acids at 25 °C
ACID
š‘²š’‚
Acetic acid
1.75 x 10-5
Benzoic acid
6.4 x 10-5
Formic acid
1.76 x 10-4
Lactic acid
1.38 x 10-4
Salicylic
1.06 x 10-3
WEAK ACID BUFFER
š‡ + š€−
š‘²š’‚ =
(š‡š€)
…… (1)
Since most š‘²š’‚ values are small numbers its more convenient
to express them as negative logarithm
pš‘²š’‚ = − log š‘²š’‚
So equation (1) will be
š©š‘²š’‚ = −š’š’š’ˆ š‡ + − š„šØš 
š¬ššš„š­
šššœš¢š
and because pH = −š’š’š’ˆ H +
Then
and
š©š‘²š’‚ = pH − š„šØš 
pH = š©š‘²š’‚ + š„šØš 
Weak acid buffer pH is Ė‚ 7
š¬ššš„š­
šššœš¢š
š¬ššš„š­
šššœš¢š
WEAK BASE BUFFER
BOH ā‡Œ B+ + OH−
Similary, the dissociation constant, or Kb value of weak base
is given by the equation:
š‘²š’ƒ =
š + šŽš‡−
(ššŽš‡)
Where
B+ = salt
and
ššŽš‡ = base
pH = š©š‘²š’˜ − p Kb + š„šØš 
š‘²š’˜ = 10−šŸšŸ’
š©š‘²š’˜ = 14
š’ƒš’‚š’”š’†
š’”š’‚š’š’•
PRACTICE PROBLEMS
1. the dissociation constant Ka of acetic acid is 1.75 x 10-5 at
25 °C. Calculate its pKa value.
2. What is the pH of a buffer solution prepared with 0.05 M
sodium borate and 0.005 M boric acid? The pKa of boric
acid is 9.24 at 25 °C.
3. What is the pH of a buffer solution prepared with 0.05 M
ammonia and 0.05 M ammonium chloride? The Kb of
ammonia is 1.8 x 10-5 at 25 °C.
4. What molar ratio of salt/acid is required to prepare a
sodium acetate-acetic acid buffer solution with a pH of
5.76? pKa of acetic acid is 4.76 at 25 °C.
PRACTICE PROBLEMS
5. The molar ratio of sodium acetate to acetic acid in a
buffer solution with a pH of 5.76 is 10:1. Assuming the
total buffer concentration is 2.2 x 10-5 mol/L, how many
grams of sodium acetate (m.w. 82) and how many grams
of acetic acid (m.w. 60) should be used in preparing a liter
of the solution?
6. Calculate the change in pH after adding 0.04 mol of
sodium hydroxide to a liter of buffer solution containing
0.2 M concentration of sodium acetate and acetic acid.
The pKa of acetic acid is 4.76 at 25 °C.
7. What is the pH of buffer solution prepared with 0.055 M
sodium acetate and 0.01 M acetic acid? The pKa of acetic
acid is 4.76 at 25 °C.
HOME WORK
1. What is the change in pH with addition of 0.01
hydrochloric acid to a liter of buffer solution containing
0.05 M of ammonia and 0.05 M ammonium chloride? Kb of
ammonia is 1.8 x 10-5 at 25 °C.
2. The dissociation constant of ethanolamine is 2.77 x 10-5
at 25 °C. Calculate pKb
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