Young’s Double Slit Contents: •Interference •Diffraction •Young’s Double Slit •Angle •Distance •Single slit •Rayleigh Criterion Interference Sources L1 L2 When the difference in distance (L1- L2) is an integer number of wavelengths (0, 1, 2, 3…) = Constructive remainder of a half (1/2, 1 1/2, 2 1/2, …) = Destructive TOC Young’s Double Slit Experiment Monochromatic, coherent light Light spreads out from slits Screen has sum of two sources Interference pattern on screen Demo TOC Young’s Double Slit Experiment L1 d Next Maxima Central Maxima L2 L2 – L1 = d sin d = slit separation TOC Young’s Double Slit Experiment L1 d Next Maxima Central Maxima L2 L2 - L2 = d sin d = slit separation d sin = n (n = 0, 1, 2…) - constructive d sin = (n +1/2) - destructive TOC Young’s Double Slit - Angle 1|2|3|4 TOC Two slits are 3.00 x 10-6 m apart. What is the wavelength of the incident light if the bright fringes are separated by 6.00o? d sin = n d = 3.00 x 10-6 m, n = 1, = 6.00o 314 nm W Two slits are 9.00 x 10-6 m apart. If 565 nm light is incident, what angle separates the central maxima, and the third fringe out? d sin = n d = 9.00 x 10-6 m, n = 3, = 565 x 10-9 m 10.9o W Young’s Double Slit Experiment L1 d Next Maxima D s Central Maxima Similar triangles - set up proportion s= D d TOC Young’s Double Slit Distance 1|2|3|4 TOC 520 nm light hits two slits separated by 2.5 x 10-5 m. What distance separates the bright fringes on the screen that is 5.0 m distant? s = D d d = 2.5 x 10-5 m, D = 5.0 m, = 520 x 10-9 m .10 m W Light hits two slits separated by 2.50 x 10-5 m. If 5.70 cm separates the bright fringes on the screen that is 5.00 m distant, what is the wavelength of light being used? s = D d d = 2.50 x 10-5 m, D = 5.00 m, d = .0570 m 285 nm W A single slit can make an interference pattern too Rayleigh Criterion = 1.22 b = Angle of resolution (Rad) = Wavelength (m) b = Diameter of circular opening (m) (Telescope aperture) the bigger the aperture, the smaller the angle you can resolve. Central maximum of one is over minimum of the other Rayleigh Criterion 1|2 TOC What is the angular resolution of the 100 inch (2.54 m) diameter telescope on the top of Mt Wilson? (use 550 nm as the wavelength) (uh 550 nm = 550 x 10-9 m) = 1.22 b = ?, = 550 x 10-9 m, b = 2.54 m = 2.64173E-07 2.6 x 10-7 radians W What diameter telescope do you need to resolve two stars that are separated by 1.8 x 1011 m, but are 3.0 × 1017 m from us? (use 550 nm as the wavelength) (AU, 32 LY) hint = s/r = (1.8 x 1011 m)/(3.0 × 1017 m) = 1.22 b = 6.00 x 10-7, = 550 x 10-9 m, b = ? b = 1.12 m 1.1 m W